CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Question
Chapter 12, Problem 12.81SP
Interpretation Introduction
Interpretation:
The effect of temperature on electrical conductivity of semiconductor change should be explained.
Concept introduction:
According to band theory, solids are classified as conductors, semiconductors, and insulators.
As per band theory, Bands are a continuum of energy levels. The bands are of two types: valence band and conduction band.
The band that holds valence electrons is valence band and band that is slightly higher in energy than valence band is conduction band. On the basis of band theory, a partly filled band shows conduction and is called conductors, and fully filled band doesn’t show conduction and are insulators.
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Chapter 12 Solutions
CHEMISTRY-TEXT
Ch. 12 - Calcium metal crystallizes in a cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - The density of a sample of metal "as measured to...Ch. 12 - Zinc sulfide crystallizes in the following cubic...Ch. 12 - Prob. 12.6ACh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8ACh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10A
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12ACh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Identify each of the following kinds of packingCh. 12 - Prob. 12.19CPCh. 12 - Titanium oxide crystallizes in the following cubic...Ch. 12 - Prob. 12.21CPCh. 12 - Prob. 12.22CPCh. 12 - Prob. 12.23CPCh. 12 - Prob. 12.24CPCh. 12 - Prob. 12.25CPCh. 12 - Prob. 12.26SPCh. 12 - Prob. 12.27SPCh. 12 - Prob. 12.28SPCh. 12 - Prob. 12.29SPCh. 12 - Prob. 12.30SPCh. 12 - Prob. 12.31SPCh. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Which of the four kinds of packing used by metals...Ch. 12 - What is a unit cell? How many atoms are in one...Ch. 12 - Copper crystallizes in a face-centered cubic unit...Ch. 12 - Lead crystallizes in a cubic unit cell with anedge...Ch. 12 - Prob. 12.38SPCh. 12 - Tungsten crystallizes in a body-centered cubic...Ch. 12 - Prob. 12.40SPCh. 12 - Prob. 12.41SPCh. 12 - Titanium metal has a density of and an atomic...Ch. 12 - Calcium metal has a density of 1.55 g/cm3 and...Ch. 12 - The atomic radius of Pb is 175 pm, and the density...Ch. 12 - The density of a sample of metal was measured to...Ch. 12 - If a protein can be induced to crystallize, its...Ch. 12 - The molecular structure of a scorpion toxin, a...Ch. 12 - Iron crystallizes in a body-centered cubic unit...Ch. 12 - Silver metal crystallizes in a face-centered cubic...Ch. 12 - Sodium hydride, NaH, crystallizes in a...Ch. 12 - Cesium chloride crystallizers in a cubic unit cell...Ch. 12 - If the edge length of an NaH unit cell is 488 pm,...Ch. 12 - The edge length of a CsCI unit cell (Problem...Ch. 12 - Silicon carbide, SiC, is a covalent network solid...Ch. 12 - Prob. 12.55SPCh. 12 - Prob. 12.56SPCh. 12 - Prob. 12.57SPCh. 12 - Prob. 12.58SPCh. 12 - Prob. 12.59SPCh. 12 - Prob. 12.60SPCh. 12 - Prob. 12.61SPCh. 12 - Prob. 12.62SPCh. 12 - Prob. 12.63SPCh. 12 - Prob. 12.64SPCh. 12 - Prob. 12.65SPCh. 12 - Prob. 12.66SPCh. 12 - Prob. 12.67SPCh. 12 - Prob. 12.68SPCh. 12 - Prob. 12.69SPCh. 12 - Prob. 12.70SPCh. 12 - Prob. 12.71SPCh. 12 - Prob. 12.72SPCh. 12 - Prob. 12.73SPCh. 12 - Prob. 12.74SPCh. 12 - Prob. 12.75SPCh. 12 - Prob. 12.76SPCh. 12 - Prob. 12.77SPCh. 12 - Prob. 12.78SPCh. 12 - Prob. 12.79SPCh. 12 - Prob. 12.80SPCh. 12 - Prob. 12.81SPCh. 12 - Prob. 12.82SPCh. 12 - Prob. 12.83SPCh. 12 - Prob. 12.84SPCh. 12 - Prob. 12.85SPCh. 12 - Prob. 12.86SPCh. 12 - Prob. 12.87SPCh. 12 - Prob. 12.88SPCh. 12 - Prob. 12.89SPCh. 12 - Prob. 12.90SPCh. 12 - Prob. 12.91SPCh. 12 - Prob. 12.92SPCh. 12 - Prob. 12.93SPCh. 12 - Prob. 12.94SPCh. 12 - Prob. 12.95SPCh. 12 - Prob. 12.96SPCh. 12 - Prob. 12.97SPCh. 12 - Prob. 12.98SPCh. 12 - Prob. 12.99SPCh. 12 - Prob. 12.100SPCh. 12 - Prob. 12.101SPCh. 12 - A photovoltaic cell contains a p-n junction that...Ch. 12 - Prob. 12.103SPCh. 12 - Prob. 12.104SPCh. 12 - Prob. 12.105SPCh. 12 - Prob. 12.106SPCh. 12 - Prob. 12.107SPCh. 12 - Prob. 12.108SPCh. 12 - Prob. 12.109SPCh. 12 - Prob. 12.110SPCh. 12 - Prob. 12.111SPCh. 12 - Prob. 12.112SPCh. 12 - Prob. 12.113SPCh. 12 - Prob. 12.114SPCh. 12 - Prob. 12.115SPCh. 12 - Prob. 12.116SPCh. 12 - Prob. 12.117SPCh. 12 - Prob. 12.118SPCh. 12 - Prob. 12.119SPCh. 12 - Prob. 12.120SPCh. 12 - Prob. 12.121SPCh. 12 - Prob. 12.122SPCh. 12 - Prob. 12.123SPCh. 12 - Prob. 12.124SPCh. 12 - Prob. 12.125SPCh. 12 - Prob. 12.126SPCh. 12 - Prob. 12.127SPCh. 12 - Prob. 12.128SPCh. 12 - Prob. 12.129SPCh. 12 - Prob. 12.130SPCh. 12 - Prob. 12.131SPCh. 12 - Prob. 12.132SPCh. 12 - Prob. 12.133SPCh. 12 - Prob. 12.134MPCh. 12 - Prob. 12.135MPCh. 12 - Prob. 12.136MPCh. 12 - Prob. 12.137MPCh. 12 - Assume that 1588 g of an alkali metal undergoes...Ch. 12 - Prob. 12.139MPCh. 12 - Prob. 12.140MPCh. 12 - Prob. 12.141MPCh. 12 - Prob. 12.142MPCh. 12 - Prob. 12.143MPCh. 12 - Prob. 12.144MP
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- Why is the C 60form of carbon called buckminsterfullerene?arrow_forward8.97 The doping of semiconductors can be done with enough precision to tune the size of the band gap in the material. Generally, in order to have a larger band gap, the dopant should be smaller than the main material. If you are a materials engineer and need a semiconductor that has lower conductivity thin pure silicon, what clement or elements could you use as your dopant? (You do not want either an n- or a p- type material) Explain your reasoning.arrow_forward8.96 A business manager wants to provide a wider range of p- and n-type semiconductors as a strategy to enhance sales. You are the lead materials engineer assigned to communicate with this manager. How would you explain why there are more ways to build a p-type semiconductor from silicon than there are ways to build an n-type semiconductor from silicon?arrow_forward
- Use molecular orbital band diagrams to explain why metals are good conductors but semiconductors are not.arrow_forwardExplain and elaborate in 10 sentences the reason why non crystalline materials does not exhibit allotropy.arrow_forwardSilicon (Si) and germanium (Ge) can be used as semiconducting materials. The band gap between the conduction band and valence band is measured in electron volts, eV. 1 eV = 1.6022 × 10⁻¹⁹J. The band gap of each semiconductor was measured, and the two values were found to be 0.69 eV and 1.12 eV. Which of the two values belongs to Ge? A) 0.69 eV B) 1.12 eV C) Cannot be determined without further information.arrow_forward
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