EBK GENETICS: FROM GENES TO GENOMES
6th Edition
ISBN: 9781260041255
Author: HARTWELL
Publisher: MCGRAW HILL BOOK COMPANY
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Chapter 12, Problem 14P
Recently, scientists constructed a transgene that expresses a mutant form of Drosophila histone H3 in which lysine 27 in the histone tail was changed to methionine (H3K27M). Expression of the H3K27M transgene results in aberrant development of fruit flies because of inappropriate expression of many different genes. Explain this finding.
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In a mutant mouse, it was discovered that a gene "W" is moved from its original
chromosomal locus to the telomere region, where chromatin is packed into
heterochromatin. Given what we have learned about eukaryotic gene regulation, can
you speculate how the expression of gene W in the new mouse line would be
changed as compare to the normal mouse?
elevated in the mutant mouse than in the wild-type mouse.
cannot be determined.
O reduced in the mutant mouse than in the wild-type mouse.
change in the mutant mouse as compared to the wild-type mouse.
In a mutant mouse, it was discovered that a gene "W" is moved from its original chromosomal locus to the telomere region, where chromatin is packed into heterochromatin. Given what we have learned about eukaryotic gene regulation, can you speculate how the expression of gene W in the new mouse line would be changed as compare to the normal mouse?
Question 18 options:
elevated in the mutant mouse than in the wild-type mouse.
cannot be determined.
reduced in the mutant mouse than in the wild-type mouse.
no change in the mutant mouse as compared to the wild-type mouse.
Aurora AAurora A is a protein that acts as a kinase (transfers phosphates to molecules). Many types of cancer cells, including breast cancer cells, have higher than normal levels of this protein.Expressions of Aurora A genes in normal breast tissues (n = 10), normal tissues adjacent to tumors (n = 12) and breast tumors (n = 14).Scientists studying the production of Aurora A protein in normal frog cells observed that the amount of this protein in the cells changed throughout the cell cycle.Scientists tested chemicals that block Aurora 2 to see if they could be used as anti-cancer drugs. They found that some of the candidate drugs did slow the growth of cancer cells in cell culture in the lab. But when they tested these drugs in cancer patients to see if the drugs could slow the growth of solid tumors, they found that the benefit to patients was small when compared to the development of severe side effects such as anemia (low red blood cell count) and leukopenia (low white blood cell…
Chapter 12 Solutions
EBK GENETICS: FROM GENES TO GENOMES
Ch. 12 - For each of the terms in the left column, choose...Ch. 12 - Many proteins other than histones are found...Ch. 12 - What difference exists between the compaction of...Ch. 12 - What is the role of the core histones in...Ch. 12 - a. About how many molecules of histone H2A would...Ch. 12 - The enzyme micrococcal nuclease can cleave...Ch. 12 - a. What letters are used to represent the short...Ch. 12 - About 2000 G bands are visible in a...Ch. 12 - Suppose you performed a fluorescence in situ...Ch. 12 - Which of the following would be suggested by a...
Ch. 12 - For each of the following pairs of chromatin...Ch. 12 - a. Drosophila b. Humans Give examples of...Ch. 12 - One histone modification that is seen consistently...Ch. 12 - Recently, scientists constructed a transgene that...Ch. 12 - Drosophila geneticists have isolated many...Ch. 12 - On the following figures, genes A and B are on the...Ch. 12 - Prob. 17PCh. 12 - The first page of this chapter displays photos of...Ch. 12 - The human genome contains about 3 billion base...Ch. 12 - The mitotic cell divisions in the early embryo of...Ch. 12 - In an experiment published in the journal Cell in...Ch. 12 - a. What DNA sequences are found at the telomeres...Ch. 12 - Prob. 23PCh. 12 - a. In a fluorescent in situ hybridization FISH...Ch. 12 - If you are comparing the two telomeres in each...Ch. 12 - a. What DNA sequences are commonly found at human...Ch. 12 - On the graphs presented in Problem 21, no data is...Ch. 12 - Prob. 29PCh. 12 - Prob. 30PCh. 12 - In the 1920s, Barbara McClintock, later a Nobel...Ch. 12 - Give at least one example of a chromosomal...Ch. 12 - Cornelia de Lange syndrome CdLS is a rare human...Ch. 12 - a. Give at least three examples of types of...Ch. 12 - A number of yeast-derived elements were added to...Ch. 12 - Prob. 36PCh. 12 - The completely synthetic yeast chromosome Syn III...
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- Recently, scientists constructed a transgene that expresses a mutant form of Drosophila histone H3 inwhich lysine 27 in the histone tail was changed to methionine (H3K27M). Expression of the H3K27Mtransgene results in aberrant development of fruit fliesbecause of inappropriate expression of many differentgenes. Explain this finding.arrow_forwardThe GAL gene system in yeast is used to metabolize galactose. In the presence of galactose, the GAL genes are expressed; however, in the absence of galactose, the GAL genes are repressed. A yeast mutant is discovered that continuously expresses the GAL genes in the presence or absence of galactose. Which one of the following mutations is likely the cause of constitutively expressed GAL genes? deletion of GAL4 deletion of the UAS elements in the regulatory regions of GAL genes O deletion of GAL3 O deletion of GAL80arrow_forwardExpression of recombinant proteins in yeast is an important tool for biotechnology companies that produce new drugs for human use. In an attempt to get a new gene X expressed in yeast, a researcher has integrated gene X into the yeast genome near a telomere. Will this strategy result in good expression of gene X? Why or why not? Would the outcome of this experiment differ if the experiment had been performed in a yeast line containing mutations in the H3 or H4 histone tails?arrow_forward
- Suppose a researcher has three different Drosophila strains that have mutations in the bicoid gene called bicoid-A, bicoid-B, and bicoid-C; the wild type is designated bicoid +. To study these mutations, phenotypically normal female flies that are homozygous for the given bicoid mutation were obtained, and their oocytes were analyzed using a Northern blot to determine the size and/or amount of the bicoid mRNA and in situ hybridization to determine the bicoid mRNA location within the oocyte. A wild-type strain was also analyzed as a control. In both cases, the probe was complementary to the bicoid mRNA and the results are shown below. (Anterior is on the left; posterior is on the right.) Northern blot 1 2 - 3 4 In situ hybridization Wild type Lane 1. Wild type (bicoid*) Lane 2. bicoid-A Lane 3. bicoid-B Lane 4. bicoid-C bicoid-B bicoid-A bicoid-C Which mutation is likely to cause the embryo to develop two "anterior" ends? bicoid-B Obicoid-A bicoid-Carrow_forwardFlowering Locus C (FLC) is a gene that is responsible for flowering in certain plants. FLC is normally expressed in new seedlings, which prevents flowering. When a plant is exposed to cold temperatures, FLC expression decreases and the plant produces flowers. FLC is regulated through epigenetic modifications. Based on this information, you should expect which of the following in histone proteins near the FLC gene: 1.In new seedlings, histones will be acetylated; while in the cold, histone methylation occurs 2.In new seedlings, histones will be methylated; while in the cold, histone acetylation occurs 3.In new seedlings, histones will be methylated; while in the cold, histone deacetylation occursarrow_forwardLysine 4 of histone H3 (H3K4) is methylated in thenucleosomes of many transcriptionally active genes.Suppose you want to determine all the places in thehuman genome where nucleosomes contain methylated H3K4.a. Starting with an antibody that specifically bindsonly to the tails of histone H3s that have K4 methylation, what kind of experiment would you perform? Outline the major steps of this experiment.b. Do you think that you would get the same results ifyour starting material was skin cells in one experiment and blood precursor cells in a second experiment? Explain.c. Describe a follow-up experiment that could determine if your data from part (a) are consistent withthe idea that H3K4 methylation marks appear onlyat transcriptionally active genesarrow_forward
- Researchers have exploited Minute mutations in orderto study the phenotypes associated with recessive lethal mutations (l−) that decrease the rate of cell divisionand thus make only very tiny homozygous mutant clones that are difficult to analyze. Many differentstrains of Drosophila carry dominant loss-of-functionMinute (M) mutations in a variety of genes encodingribosomal protein subunits. The M genes are haploinsufficient; flies with only one wild-type M+ gene copyhave a slower pace of cell division, and thus prolongeddevelopment and subtle morphological abnormalities.To circumvent the tiny clone problem, researchersgenerate GFP-marked homozygous l−/ l− clones thatare also M+/ M+, in flies that are l−/ l+ and M−/ M+.The loss of the Minute mutation only in cells withinthe clone gives the l−/ l− cells a growth advantageover their neighbors, enabling the mutant clone togrow large enough to study. Diagram chromosomesthat could be used to generate such clonesarrow_forwardWhat would be the most likely effect of inhibiting the translation of hunchback mRNA throughout a Drosophila embryo?arrow_forwardWhich of these epigenetic changes could lead to reduced transcription of a particular gene? Please make sure to select all correct answer options. decreasing acetylation of histones associated with the nucleosomes of that gene inducing histone modifications that allow the formation of denser nucleosomes in the regulatory region of the gene Oincreasing acetylation of histones associated with the nucleosomes of that gene repositioning the nucleosomes associated to the gene to expose the enhancer and promoter DNA of the gene Uremoving histones to expose the enhancer and promoter DNA of the genearrow_forward
- Explain why loss-of-function hedgehog and smoothened mutations yield the same phenotype in flies, but a loss-of- function patched mutation yields the opposite phenotype.arrow_forwardHistone methylation can have many different effects on gene expression. In some cases, histone methylation is associated with activation of transcription, whereas in other cases it can trigger the formation of heterochromatin and a decrease in transcription. If histone methylation has been detected in the region of gene YFG in yeast, describe an experiment that could distinguish whether the methylation is important to activate or repress transcription of gene YFG.arrow_forwardThe MAT locus allows yeast to switch mating type through a very complex mechanism. However, it has informed us a great deal about what aspects of gene expression typical to all organisms? Options: higher order changes in chromatin affect transcriptional efficiency that general transcription factors must first bind directly to histone tails and only then can they interact with their cognate binding sites that DNA methylation is involved in this silencing mechanism that SIR2 is required for all types of transcriptional repression that expression of Pol III genes provides a means of identifying active chromatinarrow_forward
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