Loose Leaf for Statistical Techniques in Business and Economics
17th Edition
ISBN: 9781260152647
Author: Douglas A. Lind
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 12, Problem 16E
For exercises 15 and 16, conduct a test of hypothesis to determine whether the block or the treatment means differ. Using the .05 significance level: (a) state the null and alternate hypotheses for treatments; (b) state the decision rule for treatments; and (c) state the null and alternate hypotheses for blocks. Also, state the decision rule for blocks, then: (d) compute SST, SSB, SS total, and SSE; (e) complete an ANOVA table; and (f) give your decision regarding the two sets of hypotheses and interpret the results.
The following data was collected for a two-factor ANOVA with three treatments and three blocks.
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Let p1 be the proportion of residents in Country A coping with depression, and let p2 be the proportion of residents in Country B coping with depression. What is the null hypothesis for a test to determine whether Country A has a greater proportion of residents coping with depression than Country B?
Select the correct answer below:
H0: p1−p2>0
H0: p1−p2<0
H0: p1−p2=0
H0: p1−p2≠0
With the information shown, Please do step 3 & 4 of the hypothesis testing
1.The number of people who survived the Titanic based on class and sex is collected is collected in the table. Is there enough evidence to show that the class and the sex of a person who survived the Titanic are independent? 0.05 significance level.
Null Hypothesis: class and sex of a person who survived the titanic are independent.
Alternative Hypothesis: class and sex of a person who survived the titanic are dependent.
The contingency table is:
Class
Male
Female
Total
1st
134
59
193
2nd
94
25
119
3rd
80
58
138
Total
308
142
450
Expected frequencies table is:
Class
Male
Female
Total
1st
193×308450=132.09
193×142450=60.90
193
2nd
119×308450=81.45…
Chapter 12 Solutions
Loose Leaf for Statistical Techniques in Business and Economics
Ch. 12 - Steele Electric Products Inc. assembles cell...Ch. 12 - What is the critical F value when the sample size...Ch. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 2SRCh. 12 - Prob. 7ECh. 12 - Prob. 8E
Ch. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 3SRCh. 12 - Prob. 11ECh. 12 - The following are six observations collected from...Ch. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 4SRCh. 12 - Prob. 15ECh. 12 - For exercises 15 and 16, conduct a test of...Ch. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 5SRCh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23CECh. 12 - Prob. 24CECh. 12 - Prob. 25CECh. 12 - Prob. 26CECh. 12 - In an ANOVA table, the MSE is equal to 10. Random...Ch. 12 - Prob. 28CECh. 12 - Prob. 29CECh. 12 - Prob. 30CECh. 12 - Prob. 31CECh. 12 - Prob. 32CECh. 12 - Prob. 33CECh. 12 - Prob. 34CECh. 12 - Prob. 35CECh. 12 - Prob. 36CECh. 12 - Prob. 37CECh. 12 - Prob. 38CECh. 12 - Shanks Inc., a nationwide advertising firm, wants...Ch. 12 - Prob. 40CECh. 12 - Prob. 41CECh. 12 - Prob. 42CECh. 12 - Prob. 43CECh. 12 - Prob. 44CECh. 12 - Prob. 45CECh. 12 - Prob. 46CECh. 12 - Prob. 47CECh. 12 - Prob. 48CECh. 12 - Prob. 50DACh. 12 - Prob. 51DACh. 12 - Prob. 1PCh. 12 - Prob. 2PCh. 12 - Prob. 3PCh. 12 - Prob. 4PCh. 12 - Prob. 5PCh. 12 - Prob. 6PCh. 12 - Prob. 7PCh. 12 - Prob. 1CCh. 12 - Prob. 2CCh. 12 - Prob. 1.1PTCh. 12 - The likelihood of rejecting a true null hypothesis...Ch. 12 - Prob. 1.3PTCh. 12 - Prob. 1.4PTCh. 12 - Prob. 1.5PTCh. 12 - Prob. 1.6PTCh. 12 - In a two-tailed test, the rejection region is...Ch. 12 - Prob. 1.8PTCh. 12 - Prob. 1.9PTCh. 12 - Prob. 1.10PTCh. 12 - Prob. 2.1PTCh. 12 - Prob. 2.2PTCh. 12 - Prob. 2.3PT
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