Explanation Given: ( 2 cos x + 2 ) ( 2 cos x − 1 ) = 0 and the interval [ 0 , 2 π ) . Formula used: Zero product property: if a b = 0 , then either a = 0 or b = 0 or both equal zero. Calculation: ( 2 cos x + 2 ) ( 2 cos x − 1 ) = 0 Use zero-product property. 2 cos x + 2 = 0 o r 2 cos x − 1 = 0 cos x = − 2 2 o r cos x = 1 2 Now, o s x = − 2 2 ⇒ cos x = − cos π 4 ⇒ x = ( 2 n + 1

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 1.2, Problem 17PS

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To solve the equation (2cosx+2)(2cosx−1)=0 on [0, 2π) .

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Chapter 1.2, Problem 16PS

Chapter 1.2, Problem 18PS

Chapter 1 Solutions

Calculus

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To solve the equation ( 2 cos x + 2 ) ( 2 cos x − 1 ) = 0 on [ 0 , 2 π ) .

Solution Summary: The author explains how to solve the equation (2mathrmcosx+sqrt

Concept explainers

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To solve the equation (2cosx+2)(2cosx−1)=0 on [0, 2π) .

Want to see the full answer?

Chapter 1 Solutions