Explanation Given: The equation of circle, x 2 + y 2 − 5 x + 7 y = 3 and x 2 + y 2 + 4 y = 0 . Circle, C 1 : x 2 + y 2 − 5 x + 7 y − 3 =0 Circle, C 2 : x 2 + y 2 + 4 y = 0 Equation of line passing through the intersection of circle

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 1, Problem 13SP

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To find: Theequation of line passing through the intersection points of two circle.

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Chapter 1, Problem 12SP

Chapter 1, Problem 14SP

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In Problems 7 & 8, Find an equation in point-slope form, y-y1=m(x-x1), of the line through the given points. 7. (2,7) and (4, -5) 8. (3, 20) and (-5,4) Can Explain to me Step by Step

The properties in Problem 83 provide us with another way to write the equation of a line parallel or perpendicular to a given line that contains a given point not on the line. For example, suppose that we want the equation of the line perpendicular to 3x + 4y = 6 that contains the point (1, 2). The form 4x - 3y = k, where k is a constant, represents a family of lines perpendicular to 3x + 4y = 6 because we have satisfied the condition AA' = -BB'. Therefore, to find what specific line of the family contains (1, 2), we substitute 1 for x and 2 for y to determine k.4x - 3y = k4(1) - 3(2) = k-2 = k Thus the equation of the desired line is 4x - 3y = -2. Use the properties from Problem 83 to help write the equation of each of the following lines.(a) Contains (1, 8) and is parallel to 2x + 3y = 6(b) Contains (-1, 4) and is parallel to x - 2y = 4(c) Contains (2, -7) and is perpendicular to 3x - 5y = 10(d) Contains (-1, -4) and is perpendicular to 2x + 5y = 12

How do I find problem c) in interval [0,2 π)?

Chapter 1 Solutions

Calculus

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Theequation of line passing through the intersection points of two circle.

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Chapter 1 Solutions