a. Explanation Given: A ball is thrown from a cliff, the equation of motion of the ball is s = − 16 t 2 + 96 t + 144 . Concept/ method used: The initial height of the object at t = 0 is the height of the cliff. Calculation: The equation of motion of the ball is ( s in feet, t in sec.) s = s 0 + v 0 t + 1 2 a t 2 The equation of motion of the ball is ( s in feet, t in sec.) with respect to origin at the base of cliff b. To determine To find: The time, the ball hits the ground at the base of cliff. c. To determine To estimate: The when the ball is at maximum height, and also the maximum height.

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 1.4, Problem 53PS

To determine

To find:The height of the cliff.

To determine

To find:The time, the ball hits the ground at the base of cliff.

To determine

To estimate:The when the ball is at maximum height, and also the maximum height.

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Chapter 1.4, Problem 52PS

Chapter 1.4, Problem 54PS

Chapter 1 Solutions

Calculus

Ch. 1.1 - Prob. 1PS Ch. 1.1 - Prob. 2PS Ch. 1.1 - Prob. 3PS Ch. 1.1 - Prob. 4PS Ch. 1.1 - Prob. 5PS Ch. 1.1 - Prob. 6PS Ch. 1.1 - Prob. 7PS Ch. 1.1 - Prob. 8PS Ch. 1.1 - Prob. 9PS Ch. 1.1 - Prob. 10PS

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The height of the cliff.

Solution Summary: The author calculates the height of the cliff by substituting t=0 in the equation.

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To find:The height of the cliff.

To find:The time, the ball hits the ground at the base of cliff.

To estimate:The when the ball is at maximum height, and also the maximum height.

Want to see the full answer?

Chapter 1 Solutions