Explanation Definition Used: Absolute Value: | x | = { − x x < 0 x x ≥ 0 Let a and b be two real numbers such that | a | < b and b > 0 . Now, there are two possible cases: Case 1 : a ≥ 0 Then by the definition of absolute value | a | = a ….. (1) Also, it is given that | a | < b …

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 1.2, Problem 57PS

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To prove that:if |a|<b and b>0 then −b<a<b .

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Chapter 1.2, Problem 56PS

Chapter 1.2, Problem 58PS

Chapter 1 Solutions

Calculus

Ch. 1.1 - Prob. 1PS Ch. 1.1 - Prob. 2PS Ch. 1.1 - Prob. 3PS Ch. 1.1 - Prob. 4PS Ch. 1.1 - Prob. 5PS Ch. 1.1 - Prob. 6PS Ch. 1.1 - Prob. 7PS Ch. 1.1 - Prob. 8PS Ch. 1.1 - Prob. 9PS Ch. 1.1 - Prob. 10PS

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Prob. 5PE Ch. 1 - Prob. 6PE Ch. 1 - Prob. 7PE Ch. 1 - Prob. 8PE Ch. 1 - Prob. 9PE Ch. 1 - Prob. 10PE Ch. 1 - Prob. 11PE Ch. 1 - Prob. 12PE Ch. 1 - Prob. 13PE Ch. 1 - Prob. 14PE Ch. 1 - Prob. 15PE Ch. 1 - Prob. 16PE Ch. 1 - Prob. 17PE Ch. 1 - Prob. 18PE Ch. 1 - Prob. 19PE Ch. 1 - Prob. 20PE Ch. 1 - Prob. 21PE Ch. 1 - Prob. 22PE Ch. 1 - Prob. 23PE Ch. 1 - Prob. 24PE Ch. 1 - Prob. 25PE Ch. 1 - Prob. 26PE Ch. 1 - Prob. 27PE Ch. 1 - Prob. 28PE Ch. 1 - Prob. 29PE Ch. 1 - Prob. 30PE Ch. 1 - Prob. 1SP Ch. 1 - Prob. 2SP Ch. 1 - Prob. 3SP Ch. 1 - Prob. 4SP Ch. 1 - Prob. 5SP Ch. 1 - Prob. 6SP Ch. 1 - Prob. 7SP Ch. 1 - Prob. 8SP Ch. 1 - Prob. 9SP Ch. 1 - Prob. 10SP Ch. 1 - Prob. 11SP Ch. 1 - Prob. 12SP Ch. 1 - Prob. 13SP Ch. 1 - Prob. 14SP Ch. 1 - Prob. 15SP Ch. 1 - Prob. 16SP Ch. 1 - Prob. 17SP Ch. 1 - Prob. 18SP Ch. 1 - Prob. 19SP Ch. 1 - Prob. 20SP Ch. 1 - Prob. 21SP Ch. 1 - Prob. 22SP Ch. 1 - Prob. 23SP Ch. 1 - Prob. 24SP Ch. 1 - Prob. 25SP Ch. 1 - Prob. 26SP Ch. 1 - Prob. 27SP Ch. 1 - Prob. 28SP Ch. 1 - 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Prob. 82SP Ch. 1 - Prob. 83SP Ch. 1 - Prob. 84SP Ch. 1 - Prob. 85SP Ch. 1 - Prob. 86SP Ch. 1 - Prob. 93SP Ch. 1 - Prob. 95SP Ch. 1 - Prob. 96SP Ch. 1 - Prob. 97SP Ch. 1 - Prob. 98SP Ch. 1 - Prob. 99SP

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To prove that: if | a | < b and b > 0 then − b < a < b .

Solution Summary: The author explains that if a and b are two real numbers, then -bab is the desired inequality.

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To prove that:if |a|<b and b>0 then −b<a<b .

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Chapter 1 Solutions

To prove that: if | a | &lt; b and b &gt; 0 then − b &lt; a &lt; b .

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To prove that:if |a|<b and b>0 then −b<a<b .

Want to see the full answer?

Chapter 1 Solutions

To prove that: if | a | < b and b > 0 then − b < a < b .