Campbell Biology In Focus
2nd Edition
ISBN: 9780134203072
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece
Publisher: PEARSON
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Chapter 12.3, Problem 3CC
WHAT IF? Genes A, B, and C are located on the same chromosome. Testcrosses show that the recombination frequency between A and B is 28% and that between A and C is 12%. Can you determine the linear order of these genes? Explain.
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Linkage Mapping Using Dihybrid Testcrosses in Fruit Flies
In fruit flies, the normal honey-gray body-color (bl*) is dominant to black (bl),
having normal red eyes (pu+) is dominant to purple (pu), and having normal
wings (vg+) is dominant to vestigial (vg). The three genes are located close
together on the same chromosome.
Your task is to use data from three dihybrid testcrosses to (1) calculate
recombination frequencies, (2) convert recombination frequencies into map
distances, and (3) build a map of the chromosome interval covered by the
three genes, indicating their order and distances between them.
BLACK PURPLE DIHYBRID CROSS
In the parental generation, you mate a pure-breeding wild-type female
(bl+/blt;put/pu+) with a pure-breeding black, purple male (bl/bl;pu/pu) to
produce an F1 generation that is all wild-type (bl+/bl;pu*/pu). Note that the F1
flies are all dihybrid.
Next, you mate several F1 dihybrid females (bl+/bl;pu*/pu) with tester males,
which are black, purple…
Trihybrid Cross: Several testcrosses have revealed the rate of recombination for the following genes which are KNOWN TO BE LINKED:
k-m 0.30
k-l 0.76
l-m 0.50
What is the order of the three genes and why is the frequency of recombination between the closest pair of genes not equal to the recombination rate between the two genes farthest apart? (0.8 > 0.76)
Crossover frequencies for some genes on a tomato
plant:
• Normal leaves (M) and tall plant (D) 12%
• Normal leaves (M) and normal tomato (O) 33%
• Normal leaves (M) and simple florescence (S) 64%
• Tall plant (D) and normal tomato (0) 21%
• Tall plant (D) and simple fluorescence (S) 52%
Draw a chromosome map and state the cross-over
frequency between genes for a normal tomato and
simple florescence.
Chapter 12 Solutions
Campbell Biology In Focus
Ch. 12.1 - Which one of Mendels laws relates to the...Ch. 12.1 - MAKE CONNECTIONS Review the description of meiosis...Ch. 12.1 - WHAT IF? Propose a possible reason that the first...Ch. 12.2 - A white-eyed female Drosophila is mated with a...Ch. 12.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 12.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 12.3 - When two genes are located on the same chromosome,...Ch. 12.3 - For each type of offspring of the testcross in...Ch. 12.3 - WHAT IF? Genes A, B, and C are located on the same...Ch. 12.4 - About 5% of individuals with Down syndrome have a...
Ch. 12.4 - WHAT IF? The ABO blood type locus has been mapped...Ch. 12.4 - MAKE CONNECTIONS The gene that is activated on the...Ch. 12.4 - Women born with an extra X chromosome (XXX) are...Ch. 12 - A man with hemophilia (a recessive, sex-linked...Ch. 12 - Pseudohypertrophic muscular dystrophy is an...Ch. 12 - A space probe discovers a planet inhabited by...Ch. 12 - Using the information from problem 3, scientists...Ch. 12 - A man with red-green color blindness (a recessive,...Ch. 12 - You design Drosophila crosses to provide...Ch. 12 - A wild-type fruit fly (heterozygous for gray body...Ch. 12 - Assume that genes A and B are 50 map units apart...Ch. 12 - Prob. 9TYUCh. 12 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 12 - FOCUS ON EVOLUTION Crossing over is thought to be...Ch. 12 - FOCUS ON INFORMATION The continuity of life is...Ch. 12 - SYNTHESIZE YOUR KNOWLEDGE Butterflies have an X-Y...
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- Genes A and B are 7.5 map units apart on one chromosome. Genes C and D are 8.0 map units apart on a second non-homologous chromosome. • The recombination frequency between A and B is? • The recombination frequency between A and C is? • The recombination frequency between C and D is? • The recombination frequency between B and D is?arrow_forwardSaved Gene linkage Complete the following statements about gene linkage. Not all choices will be used. independent A chromosome contains a long series of different are in a definite assortment that sequence linkage group Their position, or on the chromosome is fixed. locus alleles All of the alleles on a chromosome form a(n) they tend to be inherited together. because gametes Because they reside so close together on the chromosome, there is a reduced chance that not follow the traditional Mendelian genotypic ratios. will occur and therefore they do 30 acerarrow_forward!! 48 The recombination frequency between purple color and large wings in Drosophila is 10%. What can we conclude from this observation? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a The genes are on homologous chromosomes b The alleles åre linked The genes are 10cM apart d All of the above are truearrow_forward
- Mitotic recombination can occasionally produce a twin spot.Let’s suppose an animal species is heterozygous for two genesthat govern fur color and length: one gene affects pigmentation,with dark pigmentation (A) dominant to albino (a); the other geneaffects hair length, with long hair (L) dominant to short hair (l).The two genes are linked on the same chromosome. Let’s assume ananimal of this species is AaLl; A is linked to l, and a is linked to L.Draw the chromosomes labeled with these alleles, and explainhow mitotic recombination could produce a twin spot with onespot having albino pigmentation and long fur and the other havingdark pigmentation and short fur.arrow_forwardProblem) A university student is studying the inheritance of 2 genes of pea plants. Color of plant: Blue is dominant (B), and yellow is recessive (b) Spikes or no spikes: Having spikes is dominant (G), and having no spikes is recessive (g). Which of the following findings would indicate to the student that these two traits are located close together on the same chromosome? a) The traits show independent assortment b) All gametes of a double heterozygous individual (BbGg) are either BG or bg c) A double heterozygous individual has four types of gametes in approximately equal proportions: BG, Bg, bG, and bg d) Student finds that there is frequent crossing over between the 2lociarrow_forwardProblem Solving: In Drosophila, the gene that controls red eye color (dominant) versus white eye color is on the X chromosomes. What are the expected phenotypic results if a heterozygous female is crossed with a white-eyed male? In cats, S = short hair; s = long hair; XC = black coat; Xc = yellow coat; XCXc = tortoiseshell (calico) coat. If a long-haired yellow male is crossed with a tortoiseshell female homozygous for short hair, what are the expected phenotypic results?arrow_forward
- Linkage Mapping Using a Trihybrid Testcross in Fruit Flies Remember the black, purple, and vestigial genes from Exercise 1? Now you're going to have to construct a map of the same region from trihybrid testcross data. The new map should be similar to the one from Exercise 1, but it won't be identical because we're starting with a new, independent data set. BLACK PURPLE VESTIGIAL TRIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (bl+/bl*pu*/pu+vg+/vg+ with a pure-breeding black, purple, vestigial male (bl/bl;pu/pu vg/vg) to produce an F1 generation that is all wild-type (bl/bliput/pu;vg+/vg). Note that the F1 flies are all trihybrid. Next, you mate several F1 trihybrid females (bl/bl:put/pu;vg+/vg) with tester males, which are black, purple, vestigial (bl/bl;pu/pu;vg/vg). The offspring of this trihybrid testcross are: Phenotype Wild-type Black, purple, vestigial Vestigial Black, purple Purple, vestigial Black Purple Black, vestigial bl pu vg bl pu…arrow_forwardItem 10 10 of 15 > A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring +у ct 63 W + + 60 w y ct 16 + + + 11 + + ct 4 w y + + у + 247 w + ct 197 5.5 mu 21.5 mu >< ct 5.5 mu 21.5 mu y ct 21.5 mu 5.5 mu ct 4.5 mu 20.5 mu y ct 20.5 mu 4.5 mu ct Submit Request Answerarrow_forwardIn Drosophila (fruit flies), jammed wings (J), daughterless (da), curly wings (Cy), star eyes (S), and a black body (b) are determined by genes located on the same chromosome. Gene Combination Recombination Frequency J and Cy 34.9 J and da 1.7 S and Cy 4.8 Cy and b 42.4 S and da 38 b and S 47.2 What is the map unit distance between b and da?Answer map unitsRecord your answer as a value rounded to one decimal place.arrow_forward
- Below you will find a spreadsheet of the "class" data, use this to complete data table 2. Remember, the class is a total of 24 students, to calculate frequency use the genotype with the highest frequency for each characteristic and divide that number by 24. Don't forget to answer the question on the bottom of page 107! Gender Letters XY XX Sex X, Y 11 13 XX Homozygous Heterozygous Homozygous Recessive Genotype highest frequency Characteristic Dominant Aa Eyebrows Eye Shape Hitchhikers А, а R, r 14 10 11 3 Rr Hh Н, h D, d Е, е F,f G, g В, Ь 15 Earlobes 4 8. 12 dd Ee Tongue Roll Widows Peak 7 10 13 Ff Face Shape 9. 12 3 Gg Eye Color 14 Bb MacBook Air esc 4) FI F2 F4 F5 F6 F8 F9 F10 F1I F12 @ # $ &arrow_forwardURGENT PLEASE HELP A researcher crosses mice with brown eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes:F1: 6 apricot, short : 30 brown, long : 15 brown, short : 9 apricot, longYou know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results.a) Making use of the appropriate genetic convention for naming alleles, give the genotype of the male parent in this cross. b) What is your null hypothesis for the chi-square test? c) Give the expected number of individuals in the “brown, long” class.arrow_forwardmapping three linked genes, the heterozygous AaBbCc was crossed to aabbcc individual the following phenotypes were obtained: ABC 4 abc 2 ABc 150 abC 141 aBc 18 AbC 20 Abc 30 aBC 35 A) What are the alleles found on each parental chromosome(genotypes of the parents)? B) How many double recombinants(cross over) were there? c) what is the linear arrangement of loci on the chromosome?arrow_forward
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