   # Silver ion has an average concentration of 28 ppb (parts per billion) in U.S. water supplies. (a) What is the molality of the silver ion? (b) If you wanted 1.0 × 10 2 g of silver and could recover it chemically from water supplies, what volume of water in liters would you have to treat? (Assume the density of water is 1.0g/cm 3 .) ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 13, Problem 12PS
Textbook Problem
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## Silver ion has an average concentration of 28 ppb (parts per billion) in U.S. water supplies. (a) What is the molality of the silver ion? (b) If you wanted 1.0 × 102 g of silver and could recover it chemically from water supplies, what volume of water in liters would you have to treat? (Assume the density of water is 1.0g/cm3.)

(a)

Interpretation Introduction

Interpretation: The molality of silver ions has to be identified.

Concept introduction:

Molality: The amount of solute (mol) per kilogram of solvent.

Concentration (C, mol/kg) =  molality of solute = Amount of solute (mol)Mass of solvent (Kg)

### Explanation of Solution

Given data:

Concentrationofsilverions=28ppb

1 ppm = 1000 ppb = 281000ppm=0.028ppm

1ppm=1mg/kg,0.028 ppm = 0.028 mg/kg = 0.028 ×10-3g/kg= 0.028 ×10-3g/L(massofsilver ionsin1Lofwater)

No

(b)

Interpretation Introduction

Interpretation: The volume of water in litres has to be identified.

Concept introduction:

Molality: The amount of solute (mol) per kilogram of solvent.

Concentration (C, mol/kg) =  molality of solute = Amount of solute (mol)Mass of solvent (kg)

Density=massvolume

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