   # Calculate the freezing point of 525 g of water that contains 25.0 g of NaCl. Assume i , the van’t Hoff factor, is 1.85 for NaCl. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 13.4, Problem 7CYU
Textbook Problem
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## Calculate the freezing point of 525 g of water that contains 25.0 g of NaCl. Assume i, the van’t Hoff factor, is 1.85 for NaCl.

Interpretation Introduction

Interpretation: The freezing point of 525grams of water that has25.0 gNaCl has to be calculated.

Concept introduction:

van’t Hoff factor, i: it is the relation between change in in freezing point measured and change in in freezing point calculated. It indicates the total number of ions that are produced.

van'tHofffactor,i=measuredΔTfpCalculatedΔTfp

Freezing point depression: The freezing point of the solution varies with the solute concentration.

ΔTfp=Kfpmsolute

where,

Kfp is the molal freezing point depression constant.

### Explanation of Solution

Given data:

i=1.85Massofwater(solvent)=525g=0.525kgMassofsolute(NaCl)=25.0g

Molality can be calculated using the equation:

Molality = Moleofsolute(inmol)Amountofsolvent(inkg)Moleofsolute(inmol) = 25.0g58.4g.mol-1 = 0.428 molesMolality =0.428 moles0.525kg=0.815m

Calculation of freezing point:

ΔTfp measured = Kfp.msolute=-1.86oC/m0.815m=-1

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