Principles of Foundation Engineering
9th Edition
ISBN: 9780357684832
Author: Das
Publisher: Cengage Learning US
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Chapter 13, Problem 13.10P
A free-headed drilled shaft is shown in Figure P13.10. Let Qg = 260 kN, Mg = 0, γ = 17.5 kN/m3, ϕ′ = 35°, c' = 0, and Ep = 22 × 106 kN/m2. Determine
- a. The ground line deflection, xo
- b. The maximum bending moment in the drilled shaft
- c. The maximum tensile stress in the shaft
- d. The minimum penetration of the shaft needed for this analysis
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A free-headed drilled shaft, shown in Figure 4, has an elastic modulus, Ep = 20,000 MPa.
M, = 880 kN m
Q = 245 kN,
Sand
at = 19 kN/m3
O' = 34°
1.2 m
Figure 4
(a) Determine the ground line deflection, x.
Figure P10.7 shows a drilled shaft without a bell. Assume the following values:L1 = 6 m cu(1) = 50 kN/m2L2 = 7 m cu(2) = 75 kN/m2Ds = 1.5 mDetermine:a. The net ultimate point bearing capacity [use Eqs. (10.33) and (10.34)]b. The ultimate skin friction [use Eqs. (10.37) and (10.39)]c. The working load Qw (factor of safety = 3)
Refer to Figure 11.26b. For the drilled shaft with bell, given:Thickness of active zone, Z = 9 mDead load = 1500 kN Live load = 300 kNDiameter of the shaft, Ds = 1 mZero swell pressure for the clay in the active zone = 600 kN/m2Average angle of plinth-soil friction, Φ'ps = 20°Average undrained cohesion of the clay around the bell = 150 kN/m2. Determine the diameter of the bell, Db. A factor of safety of 3 against uplift is required with the assumption that dead load plus live load is equal to zero.
Chapter 13 Solutions
Principles of Foundation Engineering
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Determine the ultimate load-carrying capacity of...Ch. 13 - For the same data given in Problem 13.4, determine...Ch. 13 - Prob. 13.6PCh. 13 - A 3 ft diameter straight drilled shaft is shown in...Ch. 13 - Prob. 13.8PCh. 13 - Figure P13.9 shows a drilled shaft extending into...Ch. 13 - A free-headed drilled shaft is shown in Figure...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
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- Example : Figure shows bellow a drilled shaft without a bell Assume the folowing values : L1 =6 m Cu(1) = 50 KN/m L2 = 7 m Cu2) = 75 KN/m? Ds = 1.5m Determine : The net ultimate point bearing capacity by use general equation. b. The ultimate skin friction by use general equation. The working load, Qw, factor of safety = 3 a. C.arrow_forwardA 20 mm diameter hole is drilled on the centerline of a steel strap 50 mm wide by 5 mm thick, subjected to an axial pull P = 10 kN. Determine the approximate maximum unit stress adjacent to the hole. Hint: This is a stress concentration question. The first step is to calculate the K value. Select one: O a. 0.1 kN/mm? b. 0.0733 kN/mm? c. 0.146 kN/mm2arrow_forwardThe same torque is applied to two tubes with identical metal sheets, determine the ratio of square/ circle of the shear stresses. Given: r = 16 mm, %3D S = 17 mm, and t = 2.80 mm. %3D トarrow_forward
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