EBK LOGIXPRO PLC LAB MANUAL FOR PROGRAM
EBK LOGIXPRO PLC LAB MANUAL FOR PROGRAM
5th Edition
ISBN: 8220102803503
Author: Petruzella
Publisher: YUZU
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Chapter 13, Problem 13P
Program Plan Intro

Suspend (SUS) instruction:

  • The SUS instruction refers to a diagnostic instruction.
  • It is used to trap and identify specific conditions for program debugging as well as for system troubleshooting.
  • It is also used to diagnose the ladder logic program for trouble shooting by placing the controller in suspend or idle mode.

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By implementing the concepts of Classes and Objects, write a C++ program that converts the value of Delta-connected resistances to their equivalent Wye- connected resistances. Use the following formulas: R1 = R12(R31)/(R12+R23+R31) R2 = R12(R23)/(R12+R23+R31) and R3 = R31(R23)/(R12+R23+R31) The values of the 3 Delta-connected resistances, R12, R23 and R31 are to be entered from the keyboard. Accomplish the following for the given class diagram: Delta2Wye 1.) Create the class implementation using C++ R12 : double R23 : double 2.) Using the constructor, create the object, D1 from R31: double class Delta2Wye and store it in the Stack memory. + Delta2Wye( R12 : double, R23: 3.) Implement the functions of the object. Double, R31: double ) + setR( ): void + DR1(): double + DR2( ): double + DR3( ): double
A binary to 8-segment display controller will be designed to guide patients based on their body temperature. If the patient body temperature is above or equal to 38°C, the display will indicate , and it will display - otherwise. Block diagram of the complete system is shown in Fig. 1. In order to turn on a segment the corresponding control output of the controller is set to logic-1. 1) Fill in the truth table given in Fig. 2. b) a) The circuits for c0, cl and c4 will be implemented by using 8-to-1 MUXS and AND, OR, NOT gates. Draw the circuits for c0, cl and c4. The circuits for c2, c3 and c6 will be implemented by using NAND gates. Draw c) the circuits for c2, c3 and c6. A BCD EFC0 c1 1 00 0 0 0 100 0 0 1 1 0 0 0 1 0 1000 1 1 1001 0 0 1 001 0 1 1 0 01 10 001 1 1 1 0 1 0 00 0 1 0 0 1 0 10 10 0 1 01 1 101 1 00 0 1 1 0 1 0 1 1 1 0 11 1 c2 c3 c4 c5 c6 c7 c5 Sc6 c7 c2 c0 cl c2 c3 c4 c5 có c7 Binary to 8-segment controller 1 干tfff↑ А всD E F 1 1 1 1 1 1 Figure 1 Figure 2
3. Design a logic circuit that controls an elevator door in a three-story building. M is a logic signal that indicates when the elevator is moving (M = 1) or stopped (M = 0). F1, F2, and F3 are floor indicator signals that are normally LOW, and they go HIGH only when the elevator is positioned at the level of that particular floor. For example, when the elevator is lined up level with the second floor, F2 = 1 and F1 = F3 = 0. The circuit output is the OPEN signal, which is normally LOW and will go HIGH when the elevator door is to be opened. We can fill in the truth table for the OPEN output as follows: a. Because the elevator cannot be lined up with more than one floor at a time, only one of the floor inputs can be HIGH at any given time. This means that all those cases in the truth table where more than one floor input is a 1 are don't-care conditions. We can place an x in the OPEN output column for those eight cases where more than one F input is 1. b. Looking at the other eight…
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