Mastering Chemistry With Pearson Etext -- Standalone Access Card -- For General Chemistry: Principles And Modern Applications (11th Edition)
11th Edition
ISBN: 9780133387803
Author: Ralph H. Petrucci; F. Geoffrey Herring; Jeffry D. Madura; Carey Bissonnette
Publisher: PEARSON
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Chapter 13, Problem 38E
Interpretation Introduction
Interpretation:
The value of
Concept introduction:
The Gibb’s equation of
With the help of this equation, the change in
For any reaction the
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Mastering Chemistry With Pearson Etext -- Standalone Access Card -- For General Chemistry: Principles And Modern Applications (11th Edition)
Ch. 13 - Prob. 1ECh. 13 - Consider a sample of ideal gas initially in a...Ch. 13 - Prob. 3ECh. 13 - Prob. 4ECh. 13 - Indicate whether each of the following changes...Ch. 13 - Arrange the entropy changes of the following...Ch. 13 - Prob. 7ECh. 13 - Prob. 8ECh. 13 - Indicate whether entropy increases or decreases in...Ch. 13 - Which substance in each of the following pairs...
Ch. 13 - Without performing any calculations or using data...Ch. 13 - By analogy to tH and tG how would you would you...Ch. 13 - Calculate the entropy change, S , for the...Ch. 13 - Calculate the entropy change, S , for the...Ch. 13 - IN Example 13-3, we dealt with vipH and vipH for...Ch. 13 - Pentane is one of the most volatile of the...Ch. 13 - Prob. 17ECh. 13 - Estimate the normal boiling point of bromine. Br2,...Ch. 13 - Prob. 19ECh. 13 - Refer to Figure 12-28 and equation (13.13) Which...Ch. 13 - Which of the following changes m a thermodynamic...Ch. 13 - If a reaction can be carried out only because of...Ch. 13 - Indicate which of the four cases in Table 13.3...Ch. 13 - Indicate which of the four cases in Table 13....Ch. 13 - For the mixing of ideal gases (see Figure 13-3),...Ch. 13 - In Chapter 14,, we will see that, for the...Ch. 13 - Explain why (a) some exothermic reactions do not...Ch. 13 - Explain why you would expect a reaction of the...Ch. 13 - From the data given in the following table,...Ch. 13 - Use data from Appendix D to determine values of tG...Ch. 13 - At 298 K, for the reaction...Ch. 13 - At 298 K, for the reaction...Ch. 13 - The following tG values are given for 25C ....Ch. 13 - The following tG values are given for 25C ....Ch. 13 - Write an equation for the combustion of one mole...Ch. 13 - Use molar entropies from Appendix D, together with...Ch. 13 - Assess the feasibility of the reaction...Ch. 13 - Prob. 38ECh. 13 - For each of the following reactions, write down...Ch. 13 - H2(g) can be prepared by passing steam over hot...Ch. 13 - In the synthesis of gasesous methanol from carbon...Ch. 13 - Prob. 42ECh. 13 - Use data from Appendix D to determine K at 298 K...Ch. 13 - Use data from Appendix D to establish for the...Ch. 13 - Use data from Appendix D to determine value at 298...Ch. 13 - Prob. 46ECh. 13 - Use thermodynamic data at 298 K to decide in with...Ch. 13 - Use thermodynamic data at 298 K to decide m which...Ch. 13 - For the reaction below, tG=27.07kJmol1 at 298 K....Ch. 13 - For the reaction below, tG=29.05kJmol1 at 298 K....Ch. 13 - For the reaction 2NO(g)+O2(g)2NO2(g) all but one...Ch. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - For the reaction 2SO2(g)+O2(g)2SO2(g),Kz=2.8102M1...Ch. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - To establish the law of conservation of mass,...Ch. 13 - Currently, CO2 is being studied as a source of...Ch. 13 - Prob. 61ECh. 13 - A possible reaction for converting methanol to...Ch. 13 - What must be the temperature W the following...Ch. 13 - Prob. 64ECh. 13 - The synthesis of ammonia by the Haber process...Ch. 13 - Use data from Appendix D to determine (a) tH,tS ,...Ch. 13 - Prob. 67ECh. 13 - The blowing equilibrium constants have been...Ch. 13 - For the reaction N 2 O 4 ( g ) 2N O 2 ( g ) , H e...Ch. 13 - Prob. 70ECh. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Titanium is obtained by the reduction of TiCl4(l)...Ch. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - Prob. 76ECh. 13 - Prob. 77IAECh. 13 - Prob. 78IAECh. 13 - Consider the following hypothetical process in...Ch. 13 - One mole of argon gas, Ar(g), undergoes a change...Ch. 13 - Prob. 81IAECh. 13 - Consider the vaporization of water: H2O(l)H2O(g)...Ch. 13 - Prob. 83IAECh. 13 - Prob. 84IAECh. 13 - The following table shows the enthalpies end Gibbs...Ch. 13 - Prob. 86IAECh. 13 - Prob. 87IAECh. 13 - Prob. 88IAECh. 13 - Prob. 89IAECh. 13 - Prob. 90IAECh. 13 - Prob. 91IAECh. 13 - Prob. 92IAECh. 13 - Prob. 93IAECh. 13 - Prob. 94IAECh. 13 - Prob. 95IAECh. 13 - Use the following data to estimate,...Ch. 13 - Prob. 97IAECh. 13 - Prob. 98IAECh. 13 - Prob. 99IAECh. 13 - Prob. 100FPCh. 13 - The graph shows how shows how tG varies with...Ch. 13 - Prob. 102FPCh. 13 - Prob. 103FPCh. 13 - Prob. 104FPCh. 13 - Prob. 105SAECh. 13 - Briefly describe each of the following ideas,...Ch. 13 - Prob. 107SAECh. 13 - Prob. 108SAECh. 13 - Prob. 109SAECh. 13 - The reaction, 2Cl2O(g)2Cl2(g)+O2(g)tH=161kJ , is...Ch. 13 - Prob. 111SAECh. 13 - Prob. 112SAECh. 13 - Prob. 113SAECh. 13 - Prob. 114SAECh. 13 - Prob. 115SAECh. 13 - Prob. 116SAECh. 13 - Which of the following graphs of Gibbs energy...Ch. 13 - At room temperature and normal atmospheric...
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- Limestone is predominantly CaCO3, which can undergo the reaction CaCO3(s)CaO(s)+CO2(g). We know from experience that this reaction is not spontaneous, yet S for the reaction is positive. How can the second law of thermodynamics explain that this reaction is not spontaneous?arrow_forwardThe deciding factor on why HF is a weak acid and not a strong acid like the other hydrogen halides is entropy. What occurs when HF dissociates in water as compared to the other hydrogen halides?arrow_forwardA 2.50-mol sample of gas is compressed isothermally from 20.0 L to 5.00 L under a constant external pressure of 10.0 atm. Calculate w, q, U, and H for the process.arrow_forward
- The reaction CO2(g)+H2(g)CO(g)+H2O(g) is not spontaneous at room temperature but becomes spontaneous at a much higher temperature. What can you conclude from this about the signs of H and S , assuming that the enthalpy and entropy changes are not greatly affected by the temperature change? Explain your reasoning.arrow_forwardQuartz, SiO2(s), does not spontaneously decompose to siliconand oxygen at 25°C, 1.0 atm in the reaction SiO2(s)Si(s)+O2(g) even though the standard entropy change of the reactionis large and positive (S=+182.02JK1). Explain.arrow_forwardFor the reaction CO(g)+3H2(g)CH4(g)+H2O(g)K=2.21011 at 473 K and 4.6108 at 533 K. Calculate G at both temperatures.arrow_forward
- Estimate the temperature range over which each of the following reactions is spontaneous. (a) 2Al(s)+3Cl2(g)2AlCl3(s) (b) 2NOCl(g)2NO(g)+Cl2(g) (c) 4NO(g)+6H2O(g)4NH3(g)+5O2(g) (d) 2PH3(g)3H2(g)+2P(g)arrow_forwardA reaction between a solid and a liquid produces 4.5 L of a gas at 0.94 atm and absorbs 4.35 kJ of heat. Determine q, w, and E for the reaction. (Assume an initial volume of 0.)arrow_forwardLiquid water at 25C is introduced into an evacuated, insulated vessel. Identify the signs of the following thermodynamic functions for the process that occurs: H, S, Twater, Ssurr,, Suniv.arrow_forward
- Explain why absolute entropies can be measured.arrow_forwardThe deciding factor on why HF is a weak acid and not a strong acid like the other hydrogen halides is entropy. What occurs when HF dissociates in water as compared to the other hydrogen halides?arrow_forwardMethane can be produced from CO and H2.The process might be done in two steps, as shown below, with each step carried out in a separate reaction vessel within the production plant. Reaction 1 CO(g)+2H2(g)CH3OH(l) S = -532 J/K Reaction 2 CH3OH(l)CH4(g)+12O2(g) S= +162 J/K NOTE: You should be able to work this problem without using any additional tabulated data. (a) Calculate H for reaction 1. (b) Calculate Gf for CO(g). (c) Calculate S° for O2(g). (d) At what temperatures is reaction 1 spontaneous? (e) Suggest a reason why these two steps would need to be carried out separately. Substance Hf (kJ mol-1) Gf (kJ mol-1) S (J mol-1 K-1) CO(s) -110.5 197.674 CH3OH( l ) -238.7 -166.4 126.8 CH4(g) -74.8 186.2arrow_forward
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