Chapter 13, Problem 3P

(a) “Room temperature” is often taken to be 68°F. What is this on the Celsius scale? (b) The temperature of the filament in a lightbulb is about 1900 ⁰C. What is this on theFahrenheit scale?

To determine

(a)To determine:

The temperature on the Celsius scale for the given Fahrenheit temperature.

Answer to Problem 3P

Solution:

  $20°C$

Explanation of Solution

Given:

Temperature = $68°F$

Formula used:

  $T(°C)=\frac{5}{9}[T(°F)-32]$

Calculation: The formula to convert temperature from the Fahrenheit scale to the Celsius scale is

  $T(°C)=\frac{5}{9}[T(°F)-32]$

Substituting the value of $T\left(°F\right)$ here

  $T\left(°C\right)=\frac{5}{9}[68-32]=20°C$

Conclusion

Therefore, the required temperature is $20°C$ .

(b)To determine:

The temperature on the Fahrenheit scale for the given Celsius temperature.