Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 13, Problem 87GP

(a)

To determine

To Find: The density on a hot day.

(a)

Expert Solution
Check Mark

Answer to Problem 87GP

The density at a temperature of 38C is 0.597×103 kg/m3 .

Explanation of Solution

Given:

Initial temperature, T1 = 0°C = 273 K .

Final temperature,  T2= 38°C = 311 K .

Density at 0°C, ρ1 = 0.68×103 kg / m3 .

Formula used:

Ideal gas law formula is used to determine the density at increased temperature,

  P×V = n×R×Tn and R constantP×VT = constant

Here, P is the pressure,

  V is the volume,

  n is the number of molecules,

  R is the universal gas constant,

  T is the Temperature.

Write the expression for density.

   ρ = MassVolume

  So, Volume V = MassDensity

Calculation:

Substitute the given values in the above equation,

  P1×V1T1 = P2×V2T2 

Pressure is same at both the temperature. Thus,

  V1T1 = V2T2

  V1V2 = T1T2......... Equation (1)

Write the expression for the volume.

   V = MassDensity 

Mass is same at both the temperatures. Thus,

  V1 = 1ρ1 and V2 = 1ρ2

  V1V2 = ρ2ρ1......... Equation (2)

From equation (1) and equation (2)

  ρ2ρ1 = T1T2ρ2 = 273311×0.68×103 = 0.597×103 kg/m3

Conclusion:

Thus, the density at a temperature of 38oC is 0.597×103 kg/m3 .

(b)

To determine

To Find: The percentage change in the density.

(b)

Expert Solution
Check Mark

Answer to Problem 87GP

The percentage change in the density at both the temperature is 87.79 % .

Explanation of Solution

Given:

Density at 0°C ,  ρ1 = 0.68×103 kg / m3 .

Density at 38°C ,  ρ1 = 0.597×103 kg / m3 .

Formula used:

The percentage change in the density at both the temperature is determined by the following temperature,

  % change in density = Density at 38°CDensity at 0°C

Calculation:

Substitute the given values in the above equation,

  % change in density = 0.597×1030.68×103×100 = 0.8779×100% change in density = 87.79 %

Conclusion:

Thus,the percentage change in the density at both the temperature is 87.79 % .

Chapter 13 Solutions

Physics: Principles with Applications

Ch. 13 - Prob. 11QCh. 13 - Prob. 12QCh. 13 - Prob. 13QCh. 13 - Prob. 14QCh. 13 - Prob. 15QCh. 13 - Prob. 16QCh. 13 - Prob. 17QCh. 13 - Prob. 18QCh. 13 - Prob. 19QCh. 13 - Prob. 20QCh. 13 - Prob. 21QCh. 13 - Prob. 22QCh. 13 - Prob. 23QCh. 13 - Prob. 27QCh. 13 - How does the number of atoms in a 27.5-gram gold...Ch. 13 - Prob. 2PCh. 13 - (a) “Room temperature” is often taken to be 68°F....Ch. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - The Eiffel Tower (Fig. 13-31 [) is built of...Ch. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - To what temperature would you have to heat a brass...Ch. 13 - Prob. 11PCh. 13 - To make a secure fit. rivets that are larger than...Ch. 13 - An ordinary glass is filled to the brim with 450.0...Ch. 13 - An aluminum sphere is 8.75 cm in diameter. What...Ch. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - An aluminum bar has the desired length when at...Ch. 13 - The pendulum in a grandfather clock is made of...Ch. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32PCh. 13 - Prob. 33PCh. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - Prob. 46PCh. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Prob. 50PCh. 13 - Prob. 51PCh. 13 - Prob. 52PCh. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - Prob. 55PCh. 13 - Prob. 56PCh. 13 - Prob. 57PCh. 13 - Prob. 58PCh. 13 - Prob. 59PCh. 13 - Prob. 60PCh. 13 - Prob. 61PCh. 13 - Prob. 62PCh. 13 - Prob. 63PCh. 13 - Prob. 64PCh. 13 - Prob. 65PCh. 13 - Prob. 66PCh. 13 - Prob. 67PCh. 13 - Prob. 68PCh. 13 - Prob. 69PCh. 13 - Prob. 70PCh. 13 - Prob. 71PCh. 13 - Prob. 72PCh. 13 - Prob. 73GPCh. 13 - Prob. 74GPCh. 13 - Prob. 75GPCh. 13 - Prob. 76GPCh. 13 - Prob. 77GPCh. 13 - Prob. 78GPCh. 13 - Prob. 79GPCh. 13 - Prob. 80GPCh. 13 - Prob. 81GPCh. 13 - Prob. 82GPCh. 13 - Prob. 83GPCh. 13 - Prob. 84GPCh. 13 - Prob. 85GPCh. 13 - Prob. 86GPCh. 13 - Prob. 87GPCh. 13 - Prob. 88GPCh. 13 - Prob. 89GPCh. 13 - Prob. 90GPCh. 13 - Prob. 91GP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Kinetic Molecular Theory and its Postulates; Author: Professor Dave Explains;https://www.youtube.com/watch?v=o3f_VJ87Df0;License: Standard YouTube License, CC-BY