Chemistry (7th Edition)
Chemistry (7th Edition)
7th Edition
ISBN: 9780321943170
Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson
Publisher: PEARSON
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Chapter 14, Problem 14.127CP
Interpretation Introduction

Interpretation:

In the following reaction of formation of carbon monoxide. 1.50 mole of CO2and excess of solid are heated in a container having volume 20.0 L at 1100 K temperature and the equilibrium concentration of CO is 7.00M. Find out:

  1. Equilibrium concentration of CO2
  2. The value of equilibrium constant at 1100 K temperature.

Concept introduction:

Equilibrium is the process in which temperature, pressure, concentration of reactant and product do not show any change with respect to time.
There are two types of equilibrium.

  1. Physical equilibrium: In this, the physical state of the reactant and the product does not change when dynamic equilibrium occurred.
  2. Chemical equilibrium: In this, the chemical composition of reactant and product does not change when dynamic equilibrium occurred. There are two types of reaction occurred in this.
  3. (a) Reversible reactions: In this reaction, reaction can occur in two ways where reactant can convert to product as well as product can convert back to reactant.
    (b) Irreversible reaction: In this reaction, reaction cannot occur in two ways where reactant can convert to product, but product cannot convert back to reactant.


Equilibrium constant Kc is defined as the ratio of the concentrations of the products raised to the power of their stoichiometric coefficients and reactants raised to the power of their stoichiometric coefficients.
Reaction quotient Q is defined as the ratio at any point of the reaction of the concentration of the product raised to the power of their stoichiometric coefficients and reactant raised to the power of their stoichiometric coefficients.

aA+bBcC+dDKc= [C]c [D]d [A]a [B]b,equilibriumQ= [C]c [D]d [A]a [B]b

To calculate:

The value of equilibrium constant and equilibrium concentration of the reaction of formation of carbon monoxide.

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Chapter 14 Solutions

Chemistry (7th Edition)

Ch. 14 - Prob. 14.11PCh. 14 - APPLY 14.12 Magnesium hydroxide is the active...Ch. 14 - Prob. 14.13PCh. 14 - Prob. 14.14ACh. 14 - Prob. 14.15PCh. 14 - Conceptual APPLY 14.16 The reaction A2 + B2 2...Ch. 14 - PRACTICE 14.17 The H2/CO ratio in mixtures of...Ch. 14 - APPLY 14.18 Calculate the equilibrium...Ch. 14 - PRACTICE 14.19 Calculate the equilibrium...Ch. 14 - APPLY 14.20 Calculate the equilibrium...Ch. 14 - Prob. 14.21PCh. 14 - Prob. 14.22ACh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24ACh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26ACh. 14 - Prob. 14.27PCh. 14 - Prob. 14.28ACh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30ACh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32ACh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - PROBLEM 14.37 The affinity of hemoglobin (Hb) for...Ch. 14 - Prob. 14.38PCh. 14 - Prob. 14.39CPCh. 14 - The following pictures represent the equilibrium...Ch. 14 - The reaction A2+BA+AB has an equilibrium constant...Ch. 14 - Prob. 14.42CPCh. 14 - Prob. 14.43CPCh. 14 - Prob. 14.44CPCh. 14 - The following pictures represent equilibrium...Ch. 14 - Prob. 14.46CPCh. 14 - Prob. 14.47CPCh. 14 - Prob. 14.48CPCh. 14 - Prob. 14.49CPCh. 14 - Prob. 14.50SPCh. 14 - Identify the true statement about the...Ch. 14 - Prob. 14.52SPCh. 14 - Prob. 14.53SPCh. 14 - For each of the following equilibria, write the...Ch. 14 - Prob. 14.55SPCh. 14 - Prob. 14.56SPCh. 14 - Prob. 14.57SPCh. 14 - For each of the following equilibria, write the...Ch. 14 - Prob. 14.59SPCh. 14 - 14.60 If Kc = 7.5 × 10-9 at 1000 K for the...Ch. 14 - Prob. 14.61SPCh. 14 - Prob. 14.62SPCh. 14 - Prob. 14.63SPCh. 14 - Prob. 14.64SPCh. 14 - Prob. 14.65SPCh. 14 - Prob. 14.66SPCh. 14 - Prob. 14.67SPCh. 14 - Prob. 14.68SPCh. 14 - Prob. 14.69SPCh. 14 - Prob. 14.70SPCh. 14 - Prob. 14.71SPCh. 14 - Prob. 14.72SPCh. 14 - Prob. 14.73SPCh. 14 - Prob. 14.74SPCh. 14 - Prob. 14.75SPCh. 14 - Prob. 14.76SPCh. 14 - Prob. 14.77SPCh. 14 - Prob. 14.78SPCh. 14 - Prob. 14.79SPCh. 14 - Prob. 14.80SPCh. 14 - Prob. 14.81SPCh. 14 - Prob. 14.82SPCh. 14 - Prob. 14.83SPCh. 14 - Prob. 14.84SPCh. 14 - Prob. 14.85SPCh. 14 - Prob. 14.86SPCh. 14 - Prob. 14.87SPCh. 14 - Prob. 14.88SPCh. 14 - Prob. 14.89SPCh. 14 - Prob. 14.90SPCh. 14 - Prob. 14.91SPCh. 14 - Prob. 14.92SPCh. 14 - Prob. 14.93SPCh. 14 - Prob. 14.94SPCh. 14 - Prob. 14.95SPCh. 14 - Prob. 14.96SPCh. 14 - Prob. 14.97SPCh. 14 - Prob. 14.98SPCh. 14 - Prob. 14.99SPCh. 14 - Prob. 14.100SPCh. 14 - Prob. 14.101SPCh. 14 - Prob. 14.102SPCh. 14 - Prob. 14.103SPCh. 14 - Prob. 14.104SPCh. 14 - Consider the endothermic reaction...Ch. 14 - Prob. 14.106SPCh. 14 - Prob. 14.107SPCh. 14 - Prob. 14.108SPCh. 14 - Prob. 14.109SPCh. 14 - Prob. 14.110SPCh. 14 - Prob. 14.111SPCh. 14 - Prob. 14.112SPCh. 14 - Prob. 14.113SPCh. 14 - Prob. 14.114SPCh. 14 - Prob. 14.115SPCh. 14 - Prob. 14.116SPCh. 14 - Prob. 14.117SPCh. 14 - Prob. 14.118SPCh. 14 - Forward and reverse rate constants for the...Ch. 14 - Prob. 14.120CPCh. 14 - Prob. 14.121CPCh. 14 - Prob. 14.122CPCh. 14 - Prob. 14.123CPCh. 14 - Prob. 14.124CPCh. 14 - Prob. 14.125CPCh. 14 - Prob. 14.126CPCh. 14 - Prob. 14.127CPCh. 14 - Prob. 14.128CPCh. 14 - Prob. 14.129CPCh. 14 - Prob. 14.130CPCh. 14 - At 1000 K, Kp, = 2.1 106 and H=107.7kJ for the...Ch. 14 - Prob. 14.132CPCh. 14 - Prob. 14.133CPCh. 14 - Prob. 14.134CPCh. 14 - Prob. 14.135CPCh. 14 - Prob. 14.136CPCh. 14 - Prob. 14.137CPCh. 14 - Prob. 14.138CPCh. 14 - Prob. 14.139CPCh. 14 - Prob. 14.140CPCh. 14 - Prob. 14.141CPCh. 14 - Prob. 14.142CPCh. 14 - Prob. 14.143CPCh. 14 - Prob. 14.144CPCh. 14 - Prob. 14.145CPCh. 14 - Prob. 14.146CPCh. 14 - Prob. 14.147MPCh. 14 - Prob. 14.148MPCh. 14 - Prob. 14.149MPCh. 14 - Prob. 14.150MPCh. 14 - Prob. 14.151MPCh. 14 - Prob. 14.152MPCh. 14 - Prob. 14.153MPCh. 14 - Prob. 14.154MPCh. 14 - Prob. 14.155MPCh. 14 - Prob. 14.156MPCh. 14 - Prob. 14.157MPCh. 14 - Prob. 14.158MPCh. 14 - Prob. 14.159MP
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