Probability and Statistics for Engineering and the Sciences
Probability and Statistics for Engineering and the Sciences
9th Edition
ISBN: 9781305251809
Author: Jay L. Devore
Publisher: Cengage Learning
bartleby

Videos

Textbook Question
Book Icon
Chapter 1.4, Problem 48E

Exercise 34 presented the following data on endotoxin concentration in settled dust both for a sample of urban homes and for a sample of farm homes:

U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0
F: 4.0 14.0 11.0 9.0 9.0 8.0 4.0 20.0 5.0 8.9 21.0
9.2 3.0 2.0 0.3
  1. a. Determine the value of the sample standard deviation for each sample, interpret these values, and then contrast variability in the two samples. [Hint: Σxi = 237.0 for the urban sample and = 128.4 for the farm sample, and x i 2  = 10,079 for the urban sample and 1617.94 for the farm sample.]
  2. b. Compute the fourth spread for each sample and compare. Do the fourth spreads convey the same message about variability that the standard deviations do? Explain.
  3. c. The authors of the cited article also provided endotoxin concentrations in dust bag dust:
U: 34.0 49.0 13.0 33.0 24.0 24.0 35.0 104.0 34.0 40.0 38.0 1.0
F: 2.0 64.0 6.0 17.0 35.0 11.0 17.0 13.0 5.0 27.0 23.0
28.0 10.0 13.0 0.2

Construct a comparative boxplot (as did the cited paper) and compare and contrast the four samples.

a.

Expert Solution
Check Mark
To determine

Find and interpret the sample standard deviations of endotoxin concentration of urban homes and farm homes.

Compare the two standard deviations.

Answer to Problem 48E

The sample standard deviation of endotoxin concentration urban homes is 22.3EUmg_.

The sample standard deviation of endotoxin concentration of farm homes is 6.0877EUmg_.

Urban homes have greater variability than farm homes.

Explanation of Solution

Given info:

The data represents the values of endotoxin concentration in settled dust for a sample of urban homes and farm homes. Additional information is that the sum of observations and sum of squares of observations is given for both urban homes and farm homes. The values are i=111xi(U)=237, i=115xi(F)=128.4, i=111xi(U)2=10,079 and i=115xi(F)2=1,617.94.

Calculation:

Urban homes:

Variance:

Both the variance and the standard deviation are based on how much each observation deviates from a central point represented by the mean. In general, the greater the distances between the individual observations and the mean, the greater the variability of the data set.

Because the mean acts as a balancing point for observations larger and smaller than it, the sum of the deviations around the mean is always zero.

The shortcut formula for variance is,

Variance(s2)=i=111xi2(i=111xi)2nn1.

The values of sum of observations and sum of squares of observations for urban homes is i=111xi(U)=237 and i=111xi(U)2=10,079.

The variance of endotoxin concentration of urban homes is:

Variance(s2)=i=111xi(U)2(i=111xi(U))2nn1=10,097(237)21110=10,0975,106.2710=499.073

Thus, the variance of the endotoxin concentration of urban homes is 499.073.

Standard deviation:

The general formula for standard deviation is,

Standarddeviation=Variance

The sample standard deviation of endotoxin concentration of urban homes is:

Standarddeviation=Variance=499.073=22.3

The standard deviation of endotoxin concentration of urban homes is 22.3.

Interpretation:

The standard deviation is based on how much each observation deviates from a central point represented by the mean.

The standard deviation of endotoxin concentration of urban homes is 22.3EUmg_

From this it can be said that, among 11 observations of endotoxin concentration of urban homes, the approximate deviation between observed endotoxin concentration and mean endotoxin concentration for urban homes is 22.3EUmg_.

Farm homes:

The values of sum of observations and sum of squares of observations for farm homes is i=115xi(F)=128.4 and i=115xi(F)2=1,617.94.

The variance of endotoxin concentration of farm homes is:

Variance(s2)=i=115xi(F)2(i=115xi(F))2nn1=1,617.94(128.4)21514=1,617.941,099.10414=37.0597

Thus, the variance of the endotoxin concentration of farm homes is 37.0597.

Standard deviation:

The general formula for standard deviation is,

Standarddeviation=Variance.

The sample standard deviation of endotoxin concentration of farm homes is:

Standarddeviation=Variance=37.0597=6.0877

The standard deviation of endotoxin concentration of farm homes is 6.0877.

Interpretation:

The standard deviation is based on how much each observation deviates from a central point represented by the mean.

The standard deviation of endotoxin concentration of farm homes is 6.0877EUmg_

From this it can be said that among 15 observations of endotoxin concentration of farm homes, the approximate deviation between observed endotoxin concentration and mean endotoxin concentration for farm homes is 6.0877EUmg_.

Comparison:

The sample standard deviation of endotoxin concentration urban homes is 22.3EUmg_.

The sample standard deviation of endotoxin concentration of farm homes is 6.0877EUmg_.

From the standard deviation of the endotoxin concentration of urban homes and farm homes, it can be concluded that, the variation in observed and mean endotoxin concentration is greater for urban homes than for farm homes.

b.

Expert Solution
Check Mark
To determine

Obtain the fourth spread of endotoxin concentration in urban homes and farm homes.

Compare the two fourth spreads.

Check whether the interpretation about relative variability of the two different samples is same using standard deviations and fourth spreads are same.

Answer to Problem 48E

The fourth spread of the endotoxin concentration in urban homes is 22.5EUmg_.

The fourth spread of the endotoxin concentration in farm homes is 6.1EUmg_.

The variation in the endotoxin concentration is higher for urban homes than farm homes.

Yes, standard deviation and fourth spreads convey same message regarding relative variability of endotoxin concentration of urban and farm homes.

Explanation of Solution

Justification:

Fourth spreads:

In contrast to the range, which measures only differences between the extremes, the fourth spread (also called mid spread) is the difference between the upper fourth and the lower fourth. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values.

The general formula for fourth spread is,

fs=Upper fourthLowerfourth

Fourth spread of urban homes:

The lower fourth, upper fourth and fourth spreads are obtained as follows:

Step1:

The data set is arranged in ascending order as follows:

S.noUrban homes
14
25
35
46
511
617
718
823
933
1035
1180

Step2:

The lower fourth of the data is the median of the lower half of the ordered data set.

Here, the values of lower half of the ordered data set are 4, 5, 5, 6, 11and 17.

The number of observations in the lower half of the ordered data set is 6 and is even.

Hence, the median is the average of 3rd and 4th observation of the lower half of the ordered data set.

The lower fourth is obtained below as,

Lower fourth=5+62=5.5

Thus, the lower fourth is 5.5.

Step4:

The upper fourth of the data is the median of the upper half of the ordered data set.

Here, the values of upper half of the ordered data set are 17, 18, 23, 33, 35 and 80.

The number of observations in the upper half of the ordered data set is 6 and is even.

Hence, the median is the average of 3rd and 4th observation of the upper half of the ordered data set.

The upper fourth is obtained below as,

Upper fourth=23+332=28

Thus, the upper fourth is 2.015.

Step5:

The lower fourth is 5.5 and the upper fourth is 28.

The fourth spread is obtained below as,

fs=upper fourthlower fourth=285.5=22.5EUmg

Thus, the fourth spread of urban homes is 22.5EUmg_.

Fourth spread of farm homes:

The lower fourth, upper fourth and fourth spreads are obtained as follows:

Step1:

The data set is arranged in ascending order as follows:

S.noFarm homes
10.3
22
33
44
54
65
78
88.9
99
109
119.2
1211
1314
1420
1521

Step2:

The lower fourth of the data is the median of the lower half of the ordered data set.

Here, the values of lower half of the ordered data set are 0.3, 2, 3, 4, 4, 5, 8 and 8.9.

The number of observations in the lower half of the ordered data set is 8 and is even.

Hence, the median is the average of 4th and 5th observation of the lower half of the ordered data set.

The lower fourth is obtained below as,

Lower fourth=4+42=4

Thus, the lower fourth is 4.

Step4:

The upper fourth of the data is the median of the upper half of the ordered data set.

Here, the values of upper half of the ordered data set are 8.9, 9, 9, 9.2, 11, 14, 20 and 21.

The number of observations in the upper half of the ordered data set is 8 and is even.

Hence, the median is the average of 4th and 5th observation of the upper half of the ordered data set.

The upper fourth is obtained below as,

Upper fourth=9.2+112=10.1

Thus, the upper fourth is 10.1.

Step5:

The lower fourth is 4 and the upper fourth is 10.1.

The fourth spread is obtained below as,

fs=upper fourthlower fourth=10.14=6.1EUmg

Thus, the fourth spread of farm homes is 6.1EUmg_.

Comparison:

The fourth spread of the urban homes is 22.5EUmg.

The fourth spread of the farm homes is 6.1EUmg.

From the fourth spread of the endotoxin concentration of urban homes and farm homes it can be concluded that, the variation in observed and mean endotoxin concentration is greater for urban homes than for farm homes.

Conclusion:

The standard deviations obtained in part (a) conveyed that, the variability in endotoxin concentration is greater for urban homes than for farm homes.

From these two conclusions, it can be said that the information conveyed by standard deviations and fourth spreads issimilar regarding the variability in endotoxin concentration.

c.

Expert Solution
Check Mark
To determine

Draw and interpret the comparative boxplot for the four different samples.

Answer to Problem 48E

Box plot:

Output obtained from MINITAB is given below:

Probability and Statistics for Engineering and the Sciences, Chapter 1.4, Problem 48E

Explanation of Solution

Given info:

The data represents the values of endotoxin concentration in dust bag for a sample of urban homes and farm homes.

Calculation:

Box plot:

Software Procedure:

Step-by-step procedure to draw the box plot using the MINITAB software:

  • Choose Graph > Box plot.
  • Choose Multiple, and then click OK.
  • In Graph variables, enter the column of urban-set, farm-set, urban-bag and farm-bag.
  • Click OK.

Interpretation:

From the comparativeboxplots, the following points are observed.

  • The median endotoxin concentration in bag is higher for urban homes.
  • The data sets of settled dust in urban homes, bag dust in urban homes and bag dust in farm homes consist of one outlier each.
  • The variation in the entire distribution is lower for the data set of settled dust in urban homes and higher for the data set of bag dust in urban homes.
  • Overall it can be concluded that, endotoxin concentration is higher for urban homes than in farm homes for both settled dust and bag dust.
  • The overall variation is less for farm homes.
  • The bag dust is higher than the settled dust in both urban and farm homes.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Researchers interested in lead exposure due to car exhaust sampled the blood of 52 police officers subjected to constant inhalation of automobile exhaust fumes while working traffic enforcement in a primarily urban environment. The blood samples of these officers had an average lead concentration of 124.32 µg/l and a SD of 37.74 µg/l; a previous study of individuals from a nearby suburb, with no history of exposure, found an average blood level concentration of 35 µg/l. Test the hypothesis that the downtown police officers have a higher lead exposure than the group in the previous study. Interpret your results in context. Based on your preceding result, without performing a calculation, would a 99% confidence interval for the average blood concentration level of police officers contain 35 µg/l? Based on your preceding result, without performing a calculation, would a 99% confidence interval for this difference contain 0? Explain why or why not.
The following data are from a random sample of 10 students who participated in a study undertaken to investigate the effect of sleep time (measured in average number of hours of sleep per night) on GPA (grade point average, measured on a 4-point scale). Student Sleep time GPA 1 7 3.28 2 9 3.16 3 8 3.75 4 6 2.50 5 4 2.45 6 8 2.91 7 7 3.53 8 6 3.02 9 3 2.30 10 8 3.48 a. Find the equation between GPA (y) as function of sleep time (x). b. What is the estimated GPA of a student who averages 5 hours of sleep per night? c. What is the coefficient of determination?  *(no use EXCEL)
Sample data on weekly sales of two dairy products, X and Y were reported as follows: Lilongwe dairy, X 120 100 160 250 180 130 300 40 Long life, Y 70 86 67 100 45 80 90 95 a. Apply the CV, and find out which of the 2 products shows greater fluctuations in sales.

Chapter 1 Solutions

Probability and Statistics for Engineering and the Sciences

Ch. 1.2 - The accompanying specific gravity values for...Ch. 1.2 - The accompanying summary data on CeO2 particle...Ch. 1.2 - Allowable mechanical properties for structural...Ch. 1.2 - The accompanying data set consists of observations...Ch. 1.2 - Do running limes of American movies differ somehow...Ch. 1.2 - The article cited in Example 1.2 also gave the...Ch. 1.2 - The accompanying data came from a study of...Ch. 1.2 - Every corporation has a governing board of...Ch. 1.2 - The number of contaminating particles on a silicon...Ch. 1.2 - The article Determination of Most Representative...Ch. 1.2 - The article cited in Exercise 20 also gave the...Ch. 1.2 - How does the speed of a runner vary over the...Ch. 1.2 - The article Statistical Modeling of the Time...Ch. 1.2 - The accompanying data set consists of observations...Ch. 1.2 - A transformation of data values by means of some...Ch. 1.2 - The accompanying summary data on CeO2 particle...Ch. 1.2 - The article Study on the Life Distribution of...Ch. 1.2 - The accompanying frequency distribution on...Ch. 1.2 - The following categories for type of physical...Ch. 1.2 - A Pareto diagram is a variation of a histogram for...Ch. 1.2 - The cumulative frequency and cumulative relative...Ch. 1.2 - Fire load (MJ/m2) is the heat energy that could be...Ch. 1.3 - The May 1, 2009, issue of The Montclarian reported...Ch. 1.3 - Exposure to microbial products, especially...Ch. 1.3 - Mercury is a persistent and dispersive...Ch. 1.3 - A sample of 26 offshore oil workers took part in a...Ch. 1.3 - The article Snow Cover and Temperature...Ch. 1.3 - Blood pressure values are often reported to the...Ch. 1.3 - The propagation of fatigue cracks in various...Ch. 1.3 - Compute the sample median. 25% trimmed mean. 10%...Ch. 1.3 - A sample of n = 10 automobiles was selected, and...Ch. 1.3 - a. If a constant c is added to each xi in a...Ch. 1.3 - An experiment to study the lifetime (in hours) for...Ch. 1.4 - Poly(3-hydroxybutyrate) (PHB), a semicrystalline...Ch. 1.4 - The value of Youngs modulus (GPa) was determined...Ch. 1.4 - The article Effects of Short-Term Warming on Low...Ch. 1.4 - Zinfandel is a popular red wine varietal produced...Ch. 1.4 - Exercise 34 presented the following data on...Ch. 1.4 - A study of the relationship between age and...Ch. 1.4 - In 1997 a woman sued a computer keyboard...Ch. 1.4 - The article A Thin-Film Oxygen Uptake Test for the...Ch. 1.4 - The first four deviations from the mean in a...Ch. 1.4 - A mutual fund is a professionally managed...Ch. 1.4 - Grip is applied to produce normal surface forces...Ch. 1.4 - Here is a stem-and-leaf display of the escape time...Ch. 1.4 - The following data on distilled alcohol content...Ch. 1.4 - A sample of 20 glass bottles of a particular type...Ch. 1.4 - A company utilizes two different machines to...Ch. 1.4 - Blood cocaine concentration (mg/L) was determined...Ch. 1.4 - Observations on burst strength (lb/in2) were...Ch. 1.4 - The accompanying comparative boxplot of gasoline...Ch. 1 - Consider the following information on ultimate...Ch. 1 - A sample of 77 individuals working at a particular...Ch. 1 - Fretting is a wear process that results from...Ch. 1 - The accompanying frequency distribution of...Ch. 1 - A deficiency of the (race element selenium in the...Ch. 1 - Aortic stenosis refers to a narrowing of the...Ch. 1 - a. For what value of c is the quantity (xi c)2...Ch. 1 - a. Let a and b be constants and let yi = axi + b...Ch. 1 - Elevated energy consumption during exercise...Ch. 1 - Here is a description from Minitab of the strength...Ch. 1 - Anxiety disorders and symptoms can often be...Ch. 1 - The article Can We Really Walk Straight? (Amer. J....Ch. 1 - The mode of a numerical data set is the value that...Ch. 1 - Specimens of three different types of rope wire...Ch. 1 - The three measures of center introduced in this...Ch. 1 - The authors of the article Predictive Model for...Ch. 1 - Consider a sample x1 , x2,..., xn and suppose that...Ch. 1 - Let xn and sn2 denote the sample mean and variance...Ch. 1 - Lengths of bus routes for any particular transit...Ch. 1 - A study carried out to investigate the...Ch. 1 - Prob. 82SECh. 1 - Prob. 83SECh. 1 - Consider a sample x1, ... , xn with n even. Let xL...
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Text book image
Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License