   Chapter 14.1, Problem 35E

Chapter
Section
Textbook Problem

Level curves (isothermals) are shown for the typical water temperature (in °C) in Long Lake (Minnesota) as a function of depth and time of year. Estimate the temperature in the lake on June 9 (day 160) at a depth of 10 m and on June 29 (day 180) at a depth of 5 m. To determine

To estimate: The temperature in the lake on June 9 (day 160) at a depth of 10 m and on June 29 (day 180) at a depth of 5 m.

Explanation

Given:

The temperature on the 160th day with depth 10 m is represented by (160,10).

The temperature on the 180th day with depth 5 m is represented by (180,5).

Calculation:

The point (160,10) lies between the temperatures 8°C and 12°C. Identify that the point lies closeset to 11°C.

Therefore, the temperature at the point (160,10) is approximately 11°C

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