EBK CAMPBELL BIOLOGY
11th Edition
ISBN: 9780134505589
Author: Urry
Publisher: PEARSON CO
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Chapter 14.4, Problem 4CC
MAKE CONNECTIONS Ø In Table 14.1, note the
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2. Devise a simple method to calculate the total number of offspring genotypes and the total number of phenotypes (assuming complete dominance of Q, R and T) produced in the following cross without completing a branch diagram?
q q R r Tt X Q Q r r T t
EXAMPLE PROBLEM A plant with orange, spotted flowers was grown in the greenhouse from a seed collected in the wild. The plant was self-pollinated and gave rise to the following progeny: 88 orange with spots, 34 yellow with spots, 32 orange with no spots, and 8 yellow with no spots. What can you conclude about the dominance relationships of the alleles responsible for the spotted and unspotted phenotypes? What can you conclude about the genotype of the original plant that had orange, spotted flowers?
Finish these crosses below:(assume all parents are homozygous for alleles)
Cross 1:These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+)
Use a Punnett square below to determine the F1 generation phenotypic ratios.
What is the phenotypic ratio of the F1?
If two F1 individuals mated, what would the F2 phenotypic ratios be?
Chapter 14 Solutions
EBK CAMPBELL BIOLOGY
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Hemochromatosis is an inherited disease caused by...Ch. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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- TOPIC: GENE INTERACTION AND EPISTASIS Two pure-breeding (homozygous) lines of shrubs were crossed as follows: P1 phenotype red leaves X green leaves P1 genotype ___________ _____________ F1 phenotype 100% green leaves with white flecks F1 genotype ___________ Crossing the F1s produced: F2 phenotypes F2 genotypes 123 green leaves w/ white flecks ____ 44 green leaves ____ 63 red leaves ____arrow_forwardTopic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The F1 progenty: 27/64 will be as tall as the parents; 37/64 will be shorter than the parents. Pls explain it with more details. thanksarrow_forwardPlease answer fast When setting up crosses to determine map distances, why do geneticists prefer to cross the hybrid individuals to individuals homozygous for the recessive alleles in the cross?arrow_forward
- Consider these two crosses and assume that independent segregation is exhibited by all gene pairs: RrmmTT x RRMmTtFfGg x FfGg Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method. Show complete solutions.arrow_forwardConsidering hybridization in a trait like the color of the flowers of a given plant species (red dominant/ yellow recessive) conditioned by a pair of different alleles, what are the phenotypical results of the first generation (F1) and the phenotypical results of the second generation (F2, formed by crossing among F1 genotypes)? What are the phenotypical proportions in F1 and F2?arrow_forwardINTERPRET DATA Using the graph in Figure 11-20, determine how many offspring were involved in the hypothetical cross studying skin color. What percentage had the lightest skin possible? the darkest skin possible? Figure 11-20 Polygenic inheritance in human s pigmentation This simplified example assumes that skin pigmentation in humans is governed by alleles of three unlinked loci. The alleles producing dark skin (A, B, and C) are represented by capital letters, but they are not dominant. Instead, their effects are additive. The number of dark dots, each signifying an allele producing dark skin, is counted to determine the phenotype. A wide range of phenotypes is possible when individuals of intermediate phenotype mate and have offspring (AaBbCc AaBbCc). The expected distribution of phenotypes is consistent with the superimposed normal distribution curve.arrow_forward
- More Crosses with Pea Plants: The Principle of Independent Assortment Given the following matings, what are the predicted phenotypic ratios of the offspring? a. AABb Aabb b. AaBb aabb c. AaBb AaBbarrow_forwardfigure shows the results of a dihybrid cross involving seed shape and seed color. Q. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?arrow_forwardGive typing answer with explanation and conclusion Suppose that in a given species of plant the color of the flowers is determined by a gene whose dominant allele is embryonic lethal in homozygosis (AA). Two heterozygous plants are crossed (Aa x Aa) to produce 120 individuals. How many individuals in the progeny are expected to present the recessive phenotype? please explain None 30 40 120arrow_forward
- Using a Punnett Square, workout the distribution of phenotypic featuresin the first filial generation after a cross between a homozygous femaleand a heterozygous male for a single locusarrow_forward. Figure shows the results of a dihybrid cross involving seed shape and seed color. Q. What proportion of the round and yellow F2 progeny from this cross is homozygous at both loci?arrow_forwardNeep help ASAP. A red flowered plant was crossed with a blue flowered plant and produced all purple flowered plants. When the purple flowered plants were crossed with each other they produced 5 red plants, 5 blue plants, 20 deep purple plants, 20 light lilac plants, and 30 purple plants How many genes are involved in the color production? Assume that red color is caused by an A allele and blue color by a B allele and determine the likely genotype of the plants in the F2 generation.arrow_forward
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