(a)
Interpretation: To determine the volume of each balloon.
Concept Introduction: Ideal gas equation is given as,
By using the ideal gas equation:
Where, P = pressure, V = volume, T = temperature, R is gas constant
(a)
Answer to Problem 103A
22.4 L
Explanation of Solution
The volume of 1 mol of any gas is 22.4 L.
All the balloons have 1 mol of gas, thus, the volume of each balloon is 22.4 L.
(b)
Interpretation: To determine the mass of each balloon.
Concept Introduction: The molar mass of a compound could be estimated by combining the standard
(b)
Answer to Problem 103A
The mass He is 4 g, the mass of methane is 16 and the mass of oxygen is 32 g.
Explanation of Solution
The mass of Helium = 4 g/mol
(c)
Interpretation: To determine the density of each balloon.
Concept Introduction: Density can be. determined by the volume and mass of the gas. It can be represented by the symbol d which can be expressed as
(c)
Answer to Problem 103A
The density of helium gas will be
Explanation of Solution
It is known that,
The volume of the gas at STP 22.4 L
The mass of the helium gas = 4 g
The mass of the methane gas = 16 g
The mass of oxygen gas = 32g
Density can be determined by using the formula:
The density of methane gas can be calculated by as:
The density of oxygen gas can be calculated as:
(d)
Interpretation: To predict which balloon will rise and which will sink.
Concept Introduction: Density can be determined by the volume and mass of the gas. It can be represented by the symbol d which can be expressed as
(d)
Answer to Problem 103A
Each balloon will rise.
Explanation of Solution
The density of helium gas is
Density of air is
As the density of air is much higher than the density of each balloon, thus, each balloon will rise.
Chapter 15 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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