Concept explainers
In Fig. 15-28, a spring–block system is put into
Figure 15-28 Question 11.
Trending nowThis is a popular solution!
Chapter 15 Solutions
Fundamentals Of Physics - Volume 1 Only
Additional Science Textbook Solutions
An Introduction to Thermal Physics
Conceptual Physics: The High School Physics Program
College Physics: A Strategic Approach (4th Edition)
Conceptual Integrated Science
The Cosmic Perspective
Essential University Physics (3rd Edition)
- Which of the following statements is not true regarding a massspring system that moves with simple harmonic motion in the absence of friction? (a) The total energy of the system remains constant. (b) The energy of the system is continually transformed between kinetic and potential energy. (c) The total energy of the system is proportional to the square of the amplitude. (d) The potential energy stored in the system is greatest when the mass passes through the equilibrium position. (e) The velocity of the oscillating mass has its maximum value when the mass passes through the equilibrium position.arrow_forwardAn automobile with a mass of 1000 kg, including passengers, settles 1.0 cm closer to the road for every additional 100 kg of passengers. It is driven with a constant horizontal component of speed 20 km/h over a washboard road with sinusoidal bumps. The amplitude and wavelength of the sine curve are 5.0 cm and 20 cm, respectively. The distance between the front and back wheels is 2.4 m. Find the amplitude of oscillation of the automobile, assuming it moves vertically as an undamped driven harmonic oscillator. Neglect the mass of the wheels and springs and assume that the wheels are always in contact with the road.arrow_forwardConsider a graphical representation (Fig. 12.3) of simple harmonic motion as described mathematically in Equation 12.6. When the particle is at point on the graph, what can you say about its position and velocity? (a) The position and velocity are both positive. (b) The position and velocity are both negative. (c) The position is positive, and the velocity is zero. (d) The position is negative, and the velocity is zero. (e) The position is positive, and the velocity is negative. (f) The position is negative, and the velocity is positive. Figure 12.3 (Quick Quiz 12.2) An xt graph for a particle undergoing simple harmonic motion. At a particular time, the particles position is indicated by in the graph.arrow_forward
- We do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.arrow_forwardWhat conditions must be met to produce SHM?arrow_forwardAn object with a mass of 1.0 kg executes SHM along x-axis with a frequency of 3.185 Hz. At the position x the objective has kinetic energy of 0.7 J and potenial enegry of 0.3 J. The amplitude of the oscillation isarrow_forward
- 14.39 • A thrill-seeking cat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched length. Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring), the kinetic energy of the cat, the gravitational potential energy of the system relative to the lowest point of the motion, and the sum of these three energies when the cat is (a) at its highest point; (b) at its lowest point; (c) at its equilibrium position. here are the answers just need solution 14.39 (a) 0, 0, 3.92 J, 3.92 J (b) 3.92 J, 0, 0, 3.92 J (c) 0.98 J, 0.98 J, 1.96 J, 3.92 Jarrow_forwardA small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the ampli tude of the motion is 0.090 m, it takes the block 2.70 s to travel from x = 0.090 m to x = -0.090 m. If the amplitude is doubled, to 0.180 m, how long does it take the block to travel (a) from x = 0.180 m to x = -0.180 m and (b) from x = 0.090 m to x = -0.090 m?arrow_forwardA 10kg load suspended by a brass wire 10m long is observed to vibrate vertically in SHM at a frequency of 10 vib/s. Given that the Young's modulus for brass is 9 x 10^10 N/m^2, what is the cross-sectional area of the wire?arrow_forward
- A thrill-seeking cat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched length. Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring), the kinetic energy of the cat, the gravitational potential energy of the system relative to the lowest point of the motion, and the sum of these three energies when the cat is (b) at its lowest point found the answer on quizlet but i cannot understand the Us part. it says k=mg/2A but when it was substituted to equation 9, it was just mg/A it says Us= mgh yet there is a times 2 before 0.05 (check picture for context) please explain it to me. thanksarrow_forwardA thrill-seeking cat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched length. Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring), the kinetic energy of the cat, the gravitational potential energy of the system relative to the lowest point of the motion, and the sum of these three energies when the cat is (b) at its lowest point found the answer on quizlet but i cannot understand the Us part. it says Us= mgh yet there is a times 2 before 0.05 (check picture for context) please explain it to me. thanksarrow_forwardA rope of homogeneous material, of length L= 20.0 m and mass M= 2.0 kg is stretched in the horizontal direction under a tension of 35.0 N. One end of the rope is oscillated transversely, with an amplitude of 0.03 cm and frequency of 15.0 oscillations per second. The initial transverse position of this end at t=0 is yi= 0.015 m, considering the y axis oriented upwards. Which function describes the transverse displacement of a point at a distance x from the oscillating end, after being hit by the wave but before the wave reaches the other end, as shown in the figure? Choose the correct alternative (option are in the image):arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University