Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Textbook Question
Chapter 15, Problem 13TYK
Genomic imprinting
- a. explains cases in which the
phenotypic effect of an allele depends on the sex of the parent from whom that allele is inherited. - b. may involve the silencing of an allele by methylation such that offspring inherit only one active copy of a gene.
- c. occurs more often in females because of the larger maternal contribution of cytoplasm.
- d. involves both a and b.
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1A. What is the molecular basis for genomic imprinting?
B. How is the process of X-chromosome inactivation similar to genomic imprinting.
C. How is the process of X-chromosome inactivation different from genomic imprinting.
D. In mice, the Igf2 gene inherited from the mother is never expressed in her offspring? Explain.
E. What genes are deleted in a female born with Angelman syndrome. Which parent transmitted the deletion to her?
1.a) With the aid of annotated diagrams differentiate between incomplete dominance, complete dominance and codominance
b) List and explain the 5 modes of inheritance in pedigree analysis
c) With the aid of illustrative diagrams explain the three theories of DNA replication
d) Discuss the impact of COVID-19 pandemic on ecosystems.
a. What is the Raly gene? What does it encode? How does it relate to the lethality of Ay?
b. A heterozygous mouse AAy does not produce enough pigment and it is yellow. Homozygous individuals die during development, but AAy heterozygous do not. Why? You may use any graphic aid to explain this, if necessary. This means that you may use a Punnett square or a forking segregation diagram, or computations with fractions.
c. Explain why there is a non-Mendelian 2:1 yellow/agouti phenotypic ratio in this cross.
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- The case of golden labs in which a mutation in a gene for the pigment transport protein results in a lack of pigment (the golden color) instead of the brown or black the results from the actual pigment genes, is an example of... Select one: a. multiple alleles b. epistasis c. genomic imprinting d. altered methylationarrow_forwardSuppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture) (ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Based on these data, does it appear that Protein B, when present and active, favors or inhibits PCD/Apoptosis?Briefly explain your reasoning. The answer should address both the paw and brain/skull data.arrow_forwardMolecular geneticists have performed experiments in which they altered the number of copies of the bicoid gene in flies, affecting the amount of Bicoid protein produced. a. What would be the effect on development of an increased number of copies of the bicoid gene? b. What would be the effect of a decreased number of copies of bicoid? Justify your answers.arrow_forward
- a. Explain the difference between maternal inheritanceof organelle DNAs and maternal effect inheritance.b. How do the inheritance patterns of phenotypescaused by mitochondrial genes differ from thosecaused by maternal effect genes?arrow_forwardGenomic imprinting refers to the fact that A. some proteins are made from mRNA transcribed by the mother B. one cell type follows the developmental path of another C. the X-ray repair system is inactivated D. programmed cell death occurs E. gene activity depends upon whether the gene is of maternal or paternal originarrow_forwardIf a Drosophila female that is homozygous for an X-linked recessive mutation is bred with a male that carries the corresponding wild-type allele, the offspring will..... a. show the mutant phenotype in all individuals. b. be uniform wild-type. c. show a phenotype intermediate to the parents' phenotype. d. show the mutant phenotype in all males and the wild-type phenotype in all females. e. have mutant and wild-type males and mutant and wild-type females.arrow_forward
- Red–green color blindness in humans is due to an X-linked recessive gene. A woman whose father is color blind possesses one eye with normal color vision and one eye with color blindness. a. Propose an explanation for this woman’s vision pattern. Assume that no new mutations have spontaneously arisen. b. Would it be possible for a man to have one eye with normal color vision and one eye with color blindness?arrow_forwardWhen mice carrying the Avy allele exhibit a darker coat, thisphenotype is thought to be caused by dietary factors thatresult ina. a greater level of DNA methylation and a decrease in theexpression of the Agouti gene.b. a lower level of DNA methylation and a decrease in theexpressionof the Agouti gene.c. a greater level of DNA methylation and the overexpressionof the Agouti gene.d. a lower level of DNA methylation and the overexpression ofthe Agouti gene.arrow_forwardTwo plants with white flowers, each from true-breeding strains, were crossed. All the F1 plants had red flowers. When these F1 plants were intercrossed, they produced an F2 consisting of 177 plants with red flowers and 142 with white flowers. (a) Propose an explanation for the inheritance of flower color in this plant species. (b) Propose a biochemical pathway for flower pigmentation and indicate which genes control which steps in this pathway.arrow_forward
- What is true of the Progress Zone model? a) the length of time a cell resides in the progress zone dictates its identity along the proximodistal axis b) it is consistent with the outcome of removing the AER at successively later stages of limb development c) once a cell leaves the progress zone, its identity is established along the proximodistal axis d) cells of the progress zone are stimulated to divide by the AER e) all of the above You isolate a new mutant chicken strain in which limb outgrowth is severely curtailed. Limbdevelopment begins and the AER initially forms, but the AER then degenerates and subsequent development of the limb is aborted. Which of the following is a possible explanation for the AER phenotype? a) the mutant gene may function cell autonomously in the AER b) the mutant gene may function cell-nonautonomously in the limb bud mesenchyme c) the mutant gene may interfere with the feedback loop between the mesenchyme and AER d) all of the abovearrow_forwardImagine a scenario in which prenatal testing of a human female fetus indicates that the baby will have a normal XX karyotype but is heterozygous for a mutation that inactivates the Xist promoter. Allele “Xr” represents the mutated version of the Xist promoter, and “XR” represents the normal version of the Xist promoter. How will this mutation affect the process of X inactivation?A. "X inactivation will still be random with both mutant and normal X chromosomes being randomly inactivated" B. "The chromosome with the mutant Xist promoter will always be active" C. "The chromosome with the mutant Xist promoter will always be inactivated" D. "The normal X chromosome (no mutation in Xist) will always be active" E. "The normal X chromosome (no mutation in Xist) will always be inactivated"arrow_forwardThe wild-type (normal) fruit fly, Drosophila melanogaster, has straight wings and long bristles. Mutant strains have been isolated with either curled wings or short bristles. The genes representing these two mutant traits are located on separate chromosomes. Carefully examine the data from the five crosses below. (a) For each mutation, determine whether it is dominant or recessive. In each case, identify which crosses support your answer; and (b) define gene symbols and determine the genotypes of the parents for each cross.arrow_forward
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