Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 20TYK
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Phenylketonuria (PKU) is a disease that results from a recessive gene.Suppose that two unaffected parents produce a child with PKU.
a. What is the probability that a sperm from the father will contain the PKU allele?b. What is the probability that an egg from the mother will contain the PKU allele?c. What is the probability that their next child will have PKU?d. What is the probability that their next child will be heterozygous for the PKU gene?
Phenylketonuria (PKU) is a disease that results from a recessive gene. Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele? b. What is the probability that an egg from the mother will contain the PKU allele? c. What is the probability that their next child will have PKU? d. What is the probability that their next child will be heterozygous for the PKU gene?
Match the pattern of inheritance to the appropriate term.
A. Heterozygotes with different alleles of the DTL1 gene survive better than homozygotes B. The disease is usually passed from a mother to all children
C. Pure-breeding pumpkin plants grown on sandy soil have bigger seeds than plants of the same pure-breeding lineage grown on peaty soil.
D. A cross between a true-breeding plant with serrated leaf edges and a true- breeding plant with smooth leaf edges produces an F1 generation with 88% plants with serrated leaves.
E. A cross between two heterozygotes, DdFf, produces offspring in three phenotypic groups; Long wings in offspring with genotype D_F_, short wings in offspring with D_ff, and no wings in offspring with the genotypes ddF_ and ddff.
F. Individuals homozygous for a mutation in SME have a heightened sense of smell and large earlobes.
G. Grey chickens bred together have offspring that are black, grey and white in a 1:2:1 ratio
H.Alleles at locus S…
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- In a cross between a homozygous red-eyed female fruit fly and a white-eyed male fruit fly, what is the expected outcome? a. all white-eyed male offspring b. all white-eyed female offspring c. all red-eyed offspring d. half white-eyed make offspringarrow_forwardIn a trait that follows Mendelian rules of inheritance, what is the only way an organism can have the recessive phenotype? A. By having the homozygous recessive genotype B. By being heterozygous for that genotype C. It is not possible to get the recessive phenotype in Mendelian genetics D. If one parent is homozygous recessive for that trait, any offspring are guaranteed the recessive phenotype E. By being homozygous dominant for that genotypearrow_forwardIn humans, failure to synthesize melanin leads to a condition called albinism. This is a recessive condition. If parents heterozygous (Nn) for normal skin pigmentation give rise to 4 offspring, what is the probability that: a. they will have an albino child? b. the second child is albino? c. they will have all boys with normal pigmentation? d. they will have ONE albino child, no matter the order.arrow_forward
- Which of the following cannot be true about the inheritance the trait depicted in the pedigree diagram below? A. It is recessive B. It is dominant C. It is on the X chromosome D. There is not enough information to determine the mechanism of inheritancearrow_forwardAlbinism is inherited as a recessive trait in humans. If the parents are both heterozygous for the trait, what is the probability of obtaining the following: a. 3 albino children? b. 2 normal girls? c. 4 albino boys? d. first 4 children will be normal and the last 2 children will be albino? e. 4 normal children and 2 albinos in any order?arrow_forwardwhen else do we see a non-Mendelian pattern of inheritance? a)When genes are located on different chromosomes b)When genes are located far away on the same chromosome c)When genes are located close together on the same chromosomearrow_forward
- Please choose the correct answer. If a recessive mutation kills an individual during the early stages of its development, what is the possible mode of inheritance exhibited if a recessive F1 with heterozygous parents survives? a. epigenetic inheritance b. maternal inheritance c. maternal effect d. organelle inheritancearrow_forwardBecause red-green colour-blindness is an X-linked recessive condition, which of the following situations is not possible? a) a colourblind father passes the condition to this daughter b) a colourblind father passes the condition to his son c) a heterozygous mother passes the condition to her daughter d) a heterozygous mother passes the condition to her son Red-green colour blindness is a deficiency of colour vision so that a person affected by it cannot tell the difference between red and green. This is an X-linked recessive condition. Which statement is correct? a) The allele is written as X^r, and an affected female is heterozygous. b) The allele is written as X^r; an affected male is X^rY and a heterozygous female is X^RX^r c)The allele is written as X^r and a male with genotype X^RY is affected d) The allele is written as X^R; a normal male is X^RY and a homozygous recessive female is X^rX^r.arrow_forwardFruit flies are very useful model organisms that have been used to study genetics. One mutant recessive trait in fruit flies is called "eyeless" because it causes flies to have no eyes. Cross an eyeless fly with a homozygous normal fly. a. Draw the Punnett square. b. What is the genotyoe ratio of the offspring? c. What is the phenotype ratio of the offspring? d. What genetic problem is this? (monohybrid, dihybrid or multiple allele)arrow_forward
- Based on the observed inheritance pattern and ratio of phenotypes, what are the genotypes of the affected children? a) If c- = Cystic Fibrosis, the children are c-/c-. b) If c- = Cystic Fibrosis, the children are C/C. c) If c- = Cystic Fibrosis, the children are C/c-. d) If c- = Cystic Fibrosis, the children are C.arrow_forwardExplain this human pedigree and what inheritance is this?arrow_forwardConsider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?arrow_forward
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