Concept explainers
(a) A hanging spring stretches by 35.0 cm when an object of mass 450 g is hung on it at rest. In this situation, we define its position as x = 0. The object is pulled down an additional 18.0 cm and released from rest to oscillate without friction. What is its position x at a moment 84.4 s later? (b) Find the distance traveled by the vibrating object in part (a), (c) What If? Another hanging spring stretches by 35.5 cm when an object of mass 440 g is hung on it at rest. We define this new position as x = 0. This object is also pulled down an additional 18.0 cm and released from rest to oscillate without friction. Find its position 84.4 s later, (d) Find the distance traveled by the object in part (c). (e) Why are the answers to parts (a) and (c) so different when the initial data in parts (a) and (c) are so similar and the answers to parts (b) and (d) are relatively close? Does this circumstance reveal a fundamental difficulty in calculating the future?
(a)
The position
Answer to Problem 15.12P
The position
Explanation of Solution
Given info: The distance through which spring stretches is
Write the equation of position of an object attached to a spring.
Here,
Write the equation for angular frequency.
Here,
Write the equation of force generated due to stretch in spring.
Here,
Write the equation of force due to the weight of the object.
Here,
Substitute
Substitute
Substitute
Substitute
Conclusion:
Therefore, the position
(b)
The distance travelled by the object in part (a).
Answer to Problem 15.12P
The distance travelled by the object is
Explanation of Solution
Given info: The distance through which spring stretches is
Write the equation of distance travelled by the object for complete oscillation.
Here,
The total distance
Substitute
The number of complete oscillation for angular displacement of
Substitute
Conclusion:
Therefore, the distance travelled by the object is
(c)
The position of the object.
Answer to Problem 15.12P
The position
Explanation of Solution
Given info: The distance through which spring stretches is
Substitute
Conclusion:
Therefore, the position
(d)
The distance travelled by the object in part (c).
Answer to Problem 15.12P
The distance travelled by the object is
Explanation of Solution
Given info: The distance through which spring stretches is
Write the equation of distance travelled by the object for complete oscillation.
The number of complete oscillation for angular displacement of
Substitute
Conclusion:
Therefore, the distance travelled by the object is
(e)
The reason that the answer of parts (a) and (c) is different when the initial data in parts (a) and (c) are similar and the answers of parts (b) and (d) are relatively close and whether this circumstance give the fundamental difficulty.
Answer to Problem 15.12P
The oscillation patterns diverge from each other, starts out in phase and becomes out of phase completely. It is impossible to make future predictions with the known data.
Explanation of Solution
Given info: The distance through which spring stretches is
The pattern of oscillation diverges completely from each other even if the initial data are same. Starts out in phase initially, but becomes completely out of phase.
To calculate the future predictions, exact data of the present is required which is impossible. It is difficult to make prediction with the known data.
Thus, the oscillation patterns diverge from each other, starts out in phase and becomes out of phase completely. It is impossible to make future predictions with the known data.
Conclusion:
Therefore, the oscillation patterns diverge from each other, starts out in phase and becomes out of phase completely. It is impossible to make future predictions with the known data.
Want to see more full solutions like this?
Chapter 15 Solutions
PHYSICS:F/SCI.+ENG.,TECH.UPD.-WEBASSIGN
- If the amplitude of a damped oscillator decreases to 1/e of its initial value after n periods, show that the frequency of the oscillator must be approximately [1 − (8π2n2)−1] times the frequency of the corresponding undamped oscillator.arrow_forwardA vibration sensor, used in testing a washing machine, consists of a cube of aluminum 1.50 cm on edge mounted on one end of a strip of spring steel (like a hacksaw blade) that lies in a vertical plane. The strips mass is small compared with that of the cube, but the strips length is large compared with the size of the cube. The other end of the strip is clamped to the frame of the washing machine that is not operating. A horizontal force of 1.43 N applied to the cube is required to hold it 2.75 cm away from its equilibrium position. If it is released, what is its frequency of vibration?arrow_forwardIn an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.arrow_forward
- Show that the time rate of change of mechanical energy for a damped, undriven oscillator is given by dE/dt = bv2 and hence is always negative. To do so, differentiate the expression for the mechanical energy of an oscillator, E=12mv2+12kx2, and use Equation 12.28.arrow_forwardRefer to the problem of the two coupled oscillators discussed in Section 12.2. Show that the total energy of the system is constant. (Calculate the kinetic energy of each of the particles and the potential energy stored in each of the three springs, and sum the results.) Notice that the kinetic and potential energy terms that have 12 as a coefficient depend on C1 and 2 but not on C2 or 2. Why is such a result to be expected?arrow_forwardShow that, if a driven oscillator is only lightly damped and driven near resonance, the Q of the system is approximately Q2(TotalenergyEnergylossduringoneperiod)arrow_forward
- An automobile with a mass of 1000 kg, including passengers, settles 1.0 cm closer to the road for every additional 100 kg of passengers. It is driven with a constant horizontal component of speed 20 km/h over a washboard road with sinusoidal bumps. The amplitude and wavelength of the sine curve are 5.0 cm and 20 cm, respectively. The distance between the front and back wheels is 2.4 m. Find the amplitude of oscillation of the automobile, assuming it moves vertically as an undamped driven harmonic oscillator. Neglect the mass of the wheels and springs and assume that the wheels are always in contact with the road.arrow_forwardA 1.00-kg glider attached to a spring with a force constant of 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = 3.00 cm (that is, the spring is compressed by 3.00 cm). Find (a) the period of the gliders motion, (b) the maximum values of its speed and acceleration, and (c) the position, velocity, and acceleration as functions of time.arrow_forwardA mass is placed on a frictionless, horizontal table. A spring (k=100N/m) , which can be stretched or compressed, is placed on the table. A 5.00-kg mass is attached to one end of the spring, the other end is anchored to the wall. The equilibrium position is marked at zero. A student moves the mass out to x=4.0 cm and releases it from rest. The mass oscillates in SHM. (a) Determine the equations of motion. (b) Find the position, velocity, and acceleration of the mass at time t=3.00 s.arrow_forward
- Consider a damped harmonic oscillator. After four cycles the amplitude of the oscillator has dropped to 1/e of its initial value. Find the ratio of the frequency of the damped oscillator to its natural frequency.arrow_forwardIf a car has a suspension system with a force constant of 5.00104 N/m , how much energy must the car’s shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m?arrow_forwardWe do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.arrow_forward
- Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning