Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840728
Author: Limbrunner
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 15, Problem 15.16P
For Problems 15.15 through 15.26, use the moment-area method.
15.16 A
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A simply supported beam 10 m long has an overhang of 1.1 m at the left support. If a highway uniform load of 12.02 kN/m and a concentrated load of 194 kN, passes thru the beam, compute the maximum positive shear (kN) based on influence line for maximum shear at mid span.
Compute the initial deflection of the beam at midspan under service loads with the following specifications: f'c = 4000 psi, 36-inch height, depth of rebar assumed to be 3 inches less than the height, 16-inch width, 4 #9 bars (tension), Grade 60 rebar, 30' clear spans, service loads of: DL = 0.25k/ft, LL = 1.2k/ft.
The DL does NOT include self-weight of the beam or of the precast concrete deck planks that have a weight of 60 PSF. The beam picks up a tributary width of 12 feet. Also, note that this beam is continuous and is the middle beam of 5 equal spans.
Check the initial deflections against the ACI deflection requirements. Then calculate the long-term deflections and check those against the ACI requirements. For both situations, assume that finish materials will be attached to the beam.
Last: Instead of performing a structural analysis to determine the maximum deflection in the beam, conservatively figure that the maximum deflection will be 60% of what it would have been for a…
A timber beam is 120 mm wide and 200 mm deep and is used on a span of 4 metres. The simply supported beam carries a uniformly distributed load of 2.8 kN/m run over the entire length. Calculate the maximum bending stress induced.
Chapter 15 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 15 - A 14 in.-diameter aluminum rod is bent into a...Ch. 15 - 15.2 Calculate the maximum bending stress produced...Ch. 15 - A 500 -mm-long steel bar having a cross section of...Ch. 15 - 15.4 An aluminum wire has a diameter of in....Ch. 15 - 15.5 A -in.-wide by in.-thick board is bent to a...Ch. 15 - 15.6 A Douglas fir beam is in. wide and in. deep....Ch. 15 - Prob. 15.7PCh. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...
Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.I4, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - 15.27 Draw the moment diagram by parts for the...Ch. 15 - 15.28 Draw the moment diagram by parts for the...Ch. 15 - 15.29 Draw the moment diagram by parts for the...Ch. 15 - 15.30 For the beam shown, draw the conventional...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - 15.49 If the elastic limit of a steel wire is...Ch. 15 - 15.50 Calculate the bending moment required to...Ch. 15 - 15.51 A 6-ft-long cantilever beam is subjected to...Ch. 15 - 15.52 A structural steel wide-flange section is...Ch. 15 - 15.53 A simply supported structural steel...Ch. 15 - 15.54 A structural steel wide-flange shape is...Ch. 15 - A solid, round simply supported steel shaft is...Ch. 15 - Using the moment-area method, check the...Ch. 15 - 15.57 A 1-in.-diameter steel bar is 25 ft long and...Ch. 15 - 15.58 A 102-mm nominal diameter standard-weight...Ch. 15 - I 5.59 Compute the maximum deflection for the...Ch. 15 - An 8-in-wide by 12-in-deep redwood timber beam...Ch. 15 - 15.61 A solid steel shaft 3 in. in diameter and 20...Ch. 15 - 15.62 For the beam shown, draw the conventional...Ch. 15 - 15.63 Rework Problem 15.62 with concentrated loads...Ch. 15 - 15.64 A solid steel shaft 3 in. in diameter and 20...Ch. 15 - 15.65 A structural steel wide-flange section is...Ch. 15 - 15.66 A 6-in.-by-10-in, hem-fir timber beam (S4S)...Ch. 15 - 15.67 A simply supported structural steel...Ch. 15 - Calculate the maximum permissible span length for...Ch. 15 - 15.69 A structural steel wide-flange section 10 ft...Ch. 15 - 15.70 A structural steel wide-flange section...Ch. 15 - 15.71 Determine the deflection at point C and...Ch. 15 - 15.72 Calculate the deflection midway between the...Ch. 15 - 15.73 Derive an expression for the maximum...Ch. 15 - 15.74 Derive an expression for the maximum...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 6.38 Compute the value of EId at the right end of the cantilever beam.arrow_forwardA simply supported beam is loaded as shown. Use E = 200,000MPa and I=150 x 106 mm4. Compute for the slope at support A, B, and C.arrow_forwardA continuous beam has three equal spans of 20 ft eachand a uniformly distributed load of 800 lb/ft extending over the entirelength of the beam. Compute the maximum bending moment and themaximum shear.arrow_forward
- Calculate and draw sheer and moment diagram. Beam is 12ft long with pin connections on both sides. There are 100lb forces at 45 degrees on each end of the beam at 0ft and 12ft.arrow_forwardFor the beam and loading shown, use discontinuity functions to compute(a) the slope of the beam at C (positive if counterclockwise and negative if clockwise).(b) the deflection of the beam at C.Assume LAB = 210 mm, LBC = 140 mm, LCD = 120 mm, LDE = 260 mm, MB = 200 N-m, P = 1080 N and a constant value of EI = 590 × 106 N-mm2 for the beam.arrow_forwarddraw a shear and bending moment diagram for the beam shown. Label each diagram with values at locations, minimums and maximuns, changes in slope and where it crosses zeroarrow_forward
- Problem 3.5.B A simple span beam has a uniformly distributed load of 2.5 kips/ft on a span of 18 ft. Find the value for the maximum bending moment in the beam.arrow_forwardA simply supported beam of hollow rectangular cross section is 100mm deep and 60mm wide with a wall thickness of 10mm. The beam has a span of 6m and carries a load as shown . Neglecting the weight of the beam draw a bending moment diagram and calculate the maximum bending moment. And determine the maximum bending stress in the material.arrow_forwardCalculate the support reaction forces for the above beams. Draw shear and moment diagrams.arrow_forward
- Draw the free body diagram, shear force diagram, and bending moment diagram for the beam shown below and calculate values at each point:arrow_forwardTwo beams of circular cross section, one solid and other hollow are of same material and are equally strong in bending. If the inside diameter of the hollow section is three fifths of the external diameter, compare the areas of the section of two beams.arrow_forwardCalculate the modulus of section of rectangle beam of breadth 120 mm and height 200 mm.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Solids: Lesson 53 - Slope and Deflection of Beams Intro; Author: Jeff Hanson;https://www.youtube.com/watch?v=I7lTq68JRmY;License: Standard YouTube License, CC-BY