   Chapter 15, Problem 7PE

Chapter
Section
Textbook Problem

# (a) What is the average metabolic rate in watts of a man who metabolizes 10,500 kJ of feed energy in one day? (b) What is the maximum amount of work in joules he can do without breaking down fat, assuming a maximum eficiency of 20.0%? (c) Compare his work output with the daily output of a 187−W (0.250−horsepower) motor.

(a)

To determine

The average metabolic rate in watts.

Explanation

Given info:

Amount of energy metabolized by man =E=10500 kJ=10500×1000 J=10500000 J

Time period =t=1 day=24 hours = 24×3600 second = 86400 sec

Average metabolic rate =P

Formula Used:

Metab

To determine

(b)

Maximum amount of work the man can do.

To determine

(c)

Daily work output of motor and compare it with work output of man.

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