Chapter 16, Problem 16.27A

Interpretation Introduction

Interpretation:

Molar solubility of ${\text{Zn(OH)}}_{\text{2}}$ in a solution buffered at $\text{pH=11}$ must be determined.

Concept introduction:

• Solubility of a sparingly soluble salt decreases when same ion is present in that solution. It’s known as common ion effect.
• When concentration of an ion increases then concentration of counter ion decreases to maintain the solubility product constant.

Given:

${\text{K}}_{\text{sp}}$ of ${\text{Zn(OH)}}_{\text{2}}$ and $\text{pH}$ of the buffer as $11$.