The p H at equivalence point of a titration of 50.00 m L o f 0.0500 M solution of ethylamine with 0.100 M H N O 3 has to be calculated. A suitable indicator has to be suggested.

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Chapter 16, Problem 16.64QE

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Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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When titrating a 25 mL solution of 0.20M CH3COOH with 0.10M KOH, you realize you forgot to add an indicator initially. You've added 10 mL of KOH to the flask of acid. Ka of CH3COOH = 1.8 x 10^-5 1) Calculate the pH at this point 2) What color would your solution be if you add 40 mL KOH more. And a few drops of clorophenol blue indicator at this point. Why?

Calculate the pH during the titration of 20.00 mL of 0.1000 M ethylamine, C2H5NH2(aq), with 0.2000 M HNO3(aq) after 7.24 mL of the acid have been added. Kb of ethylamine = 6.5 x 10-4.

A sample of vinegar weighing 10.52 g is titrated with NaOH. The end point is overstepped, and the solution is titrated back with HCl. From the following data, calculate the acidity of the vinegar in terms of percentage of acetic acid, CH3COOH Standardization Data:1.050 mL HCl ≡ 1.000 mL NaOH1.000 mL NaOH ≡ 0.06050 g benzoic acid, C6H5COOH (122.12 g/mol) Analysis Data:Volume NaOH used = 19.03 mLVolume HCl used for back titration = 1.50 mL

Answer 2

Question

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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Answer 3

Question

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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Answer 4

Question

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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Answer 5

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

Answer 6

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

Answer 7

Chapter 16, Problem 16.64QE

Interpretation Introduction

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

Answer 8

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Answer 9

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Answer 11

Ch. 16 - Prob. 16.1QE Ch. 16 - Sketch a titration curve for the titration of...Ch. 16 - Prob. 16.4QE Ch. 16 - Prob. 16.5QE Ch. 16 - Explain why the HendersonHasselbalch equation...Ch. 16 - Prob. 16.7QE Ch. 16 - Prob. 16.8QE Ch. 16 - Prob. 16.9QE Ch. 16 - Prob. 16.11QE Ch. 16 - Prob. 16.13QE

The p H at equivalence point of a titration of 50.00 m L o f 0.0500 M solution of ethylamine with 0.100 M H N O 3 has to be calculated. A suitable indicator has to be suggested.

Solution Summary: The author explains how the pH of a titration of 50.00mL with 0.100M HNO_3 has to be calculated.

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Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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Chapter 16 Solutions

The p H at equivalence point of a titration of 50.00 m L o f 0.0500 M solution of ethylamine with 0.100 M H N O 3 has to be calculated. A suitable indicator has to be suggested.

Solution Summary: The author explains how the pH of a titration of 50.00mL with 0.100M HNO_3 has to be calculated.

Concept explainers

Videos

Interpretation: The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.

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Chapter 16 Solutions

Interpretation:

The pH at equivalence point of a titration of 50.00 mL of 0.0500 M solution of ethylamine with 0.100M HNO3 has to be calculated. A suitable indicator has to be suggested.