Chapter 16, Problem 16.79P

Interpretation Introduction

(a)

Interpretation:

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including splitting pattern and the integral trace are to be sketched.

Concept introduction:

Each chemically distinct type of hydrogen atom in a molecule gives rise to an independent signal in a proton NMR spectrum. In a ${}^{\text{1}}\text{H}$ NMR spectrum, integration is proportional to the number of protons giving rise to that signal. Every chemically distinct carbon atom produces one ${}^{\text{13}}\text{C}$ NMR signal.

The $\text{N + 1}$ rule states the splitting pattern of the signal; N protons will split the signal of an adjacent, chemically distinct proton into $\text{N + 1}$ peaks. The relative intensities of those peaks are described by Pascal’s triangle.

Answer to Problem 16.79P

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including splitting pattern and the integral trace are as follows:

${}^{\text{1}}\text{H}$ NMR spectrum:

${}^{\text{13}}\text{C}$ NMR spectrum:

Explanation of Solution

The given compound is

There are two types of chemically different H atoms and three types of C atoms in the above compound. Thus, the ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including splitting pattern and the integral trace are

Conclusion

The ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are sketched on the basis of the chemically different types of carbon and hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are to be sketched.

Concept introduction:

Each chemically distinct type of hydrogen atom in a molecule gives rise to an independent signal in a proton NMR spectrum. In a ${}^{\text{1}}\text{H}$ NMR spectrum, integration is proportional to the number of protons giving rise to that signal. Every chemically distinct carbon atom produces one ${}^{\text{13}}\text{C}$ NMR signal.

The $\text{N + 1}$ rule states the splitting pattern of the signal; N protons will split the signal of an adjacent, chemically distinct proton into $\text{N + 1}$ peaks. The relative intensities of those peaks are described by Pascal’s triangle.

Answer to Problem 16.79P

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are as follows:

${}^{\text{1}}\text{H}$ NMR spectrum:

${}^{\text{13}}\text{C}$ NMR spectrum:

Explanation of Solution

The given compound is

There are three types of chemically different H atoms and five types of C atoms in the above compound. Thus, the ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are

Conclusion

The ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are sketched on the basis of the chemically different types of carbon and hydrogen atoms.

Interpretation Introduction

(c)

Interpretation:

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are to be sketched.

Concept introduction:

Each chemically distinct type of hydrogen atom in a molecule gives rise to an independent signal in a proton NMR spectrum. In a ${}^{\text{1}}\text{H}$ NMR spectrum, integration is proportional to the number of protons giving rise to that signal. Every chemically distinct carbon atom produces one ${}^{\text{13}}\text{C}$ NMR signal.

The $\text{N + 1}$ rule states the splitting pattern of the signal; N protons will split the signal of an adjacent, chemically distinct proton into $\text{N + 1}$ peaks. The relative intensities of those peaks are described by Pascal’s triangle.

Answer to Problem 16.79P

For the given compound, both ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are as follows:

${}^{\text{1}}\text{H}$ NMR spectrum:

${}^{\text{13}}\text{C}$ NMR spectrum:

Explanation of Solution

The given compound is

There are five types of chemically different H atoms and six types of C atoms in the above compound. Thus, the ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are

Conclusion

The ${}^{\text{1}}\text{H}$ NMR spectrum and a ${}^{\text{13}}\text{C}$ NMR spectrum including the splitting pattern and integral trace are sketched on the basis of the chemically different types of carbon and hydrogen atoms.