(a)
Interpretation:
The given reduction half- reactions has to be arranged in decreasing order to occur.
Concept Introduction:
Oxidizing agent:
An oxidizing agent or oxidant is a substance that gains electrons and gets reduced in a
Reducing agent:
A reducing agent or reductant is a substance that loses electrons and gets oxidized in a chemical reaction. A reducing agent is also called as electron donor.
(b)
Interpretation:
The strongest oxidizing and reducing agent has to be given.
Concept Introduction:
Oxidizing agent:
An oxidizing agent or oxidant is a substance that gains electrons and gets reduced in a chemical reaction. An oxidizing agent is also called as electron acceptor.
Reducing agent:
A reducing agent or reductant is a substance that loses electrons and gets oxidized in a chemical reaction. A reducing agent is also called as electron donor.
(c)
Interpretation:
Among the three cell reactions, the one which delivers the highest voltage has to be given.
Concept Introduction:
Oxidizing agent:
An oxidizing agent or oxidant is a substance that gains electrons and gets reduced in a chemical reaction. An oxidizing agent is also called as electron acceptor.
Reducing agent:
A reducing agent or reductant is a substance that loses electrons and gets oxidized in a chemical reaction. A reducing agent is also called as electron donor.
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General Chemistry: Atoms First
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- You have 1.0 M solutions of Al(NO3)3 and AgNO3 along with Al and Ag electrodes to construct a voltaic cell. The salt bridge contains a saturated solution of KCl. Complete the picture associated with this problem by a writing the symbols of the elements and ions in the appropriate areas (both solutions and electrodes). b identifying the anode and cathode. c indicating the direction of electron flow through the external circuit. d indicating the cell potential (assume standard conditions, with no current flowing). e writing the appropriate half-reaction under each of the containers. f indicating the direction of ion flow in the salt bridge. g identifying the species undergoing oxidation and reduction. h writing the balanced overall reaction for the cell.arrow_forwardIt took 150. s for a current of 1.25 A to plate out 0.109 g of a metal from a solution containing its cations. Show that it is not possible for the cations to have a charge of 1+.arrow_forwarda Calculate G for the following cell reaction: Tl(s)Tl+(aq)Pb2+(aq)Pb(s) The Gf for Tl+(aq) is 32.4 kJ/mol. b From G, calculate the standard cell potential for the cell reaction and from this, determine the standard potential for Tl2+(aq)+eTl(s).arrow_forward
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