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Chapter 17, Problem 17.130EP

(a)

Interpretation Introduction

Interpretation:

Given reaction is an amidification reaction or not has to be indicated.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(a)

Expert Solution
Check Mark

Answer to Problem 17.130EP

It is an amidification reaction.

Explanation of Solution

Given reaction is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  1

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and ammonia is present as reactant and the reaction is conducted at high temperature.  The product obtained is a primary amide.  This is an amidification reaction.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  2

Conclusion

Given reaction is an amidification reaction.

(b)

Interpretation Introduction

Interpretation:

Given reaction is an amidification reaction or not has to be indicated.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(b)

Expert Solution
Check Mark

Answer to Problem 17.130EP

It is an amidification reaction.

Explanation of Solution

Given reaction is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  3

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and primary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a secondary amide.  This is an amidification reaction.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  4

Conclusion

Given reaction is an amidification reaction.

(c)

Interpretation Introduction

Interpretation:

Given reaction is an amidification reaction or not has to be indicated.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(c)

Expert Solution
Check Mark

Answer to Problem 17.130EP

It is an amidification reaction.

Explanation of Solution

Given reaction is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  5

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and secondary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a tertiary amide.  This is an amidification reaction.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  6

Conclusion

Given reaction is an amidification reaction.

(d)

Interpretation Introduction

Interpretation:

Given reaction is an amidification reaction or not has to be indicated.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(d)

Expert Solution
Check Mark

Answer to Problem 17.130EP

It is an amidification reaction.

Explanation of Solution

Given reaction is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  7

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and secondary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a tertiary amide.  This is an amidification reaction.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 17, Problem 17.130EP , additional homework tip  8

Conclusion

Given reaction is an amidification reaction.

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Chapter 17 Solutions

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card

Ch. 17.4 - Prob. 1QQCh. 17.4 - Prob. 2QQCh. 17.5 - Prob. 1QQCh. 17.5 - Prob. 2QQCh. 17.5 - Prob. 3QQCh. 17.6 - Prob. 1QQCh. 17.6 - Prob. 2QQCh. 17.6 - Prob. 3QQCh. 17.7 - Prob. 1QQCh. 17.7 - Prob. 2QQCh. 17.7 - Prob. 3QQCh. 17.8 - Prob. 1QQCh. 17.8 - Prob. 2QQCh. 17.8 - Prob. 3QQCh. 17.8 - Prob. 4QQCh. 17.9 - Prob. 1QQCh. 17.9 - Prob. 2QQCh. 17.10 - Prob. 1QQCh. 17.10 - Prob. 2QQCh. 17.10 - Prob. 3QQCh. 17.10 - Prob. 4QQCh. 17.11 - Prob. 1QQCh. 17.11 - Prob. 2QQCh. 17.11 - Prob. 3QQCh. 17.12 - Prob. 1QQCh. 17.12 - Prob. 2QQCh. 17.12 - Prob. 3QQCh. 17.12 - Prob. 4QQCh. 17.13 - Prob. 1QQCh. 17.13 - Prob. 2QQCh. 17.13 - Prob. 3QQCh. 17.13 - Prob. 4QQCh. 17.14 - Prob. 1QQCh. 17.14 - Prob. 2QQCh. 17.14 - Prob. 3QQCh. 17.15 - Prob. 1QQCh. 17.15 - Prob. 2QQCh. 17.16 - Prob. 1QQCh. 17.16 - Prob. 2QQCh. 17.16 - Prob. 3QQCh. 17.17 - Prob. 1QQCh. 17.17 - Prob. 2QQCh. 17.17 - Prob. 3QQCh. 17.18 - Prob. 1QQCh. 17.18 - Prob. 2QQCh. 17.18 - Prob. 3QQCh. 17.19 - Prob. 1QQCh. 17.19 - Prob. 2QQCh. 17.19 - Prob. 3QQCh. 17.19 - Prob. 4QQCh. 17 - Prob. 17.1EPCh. 17 - Prob. 17.2EPCh. 17 - Prob. 17.3EPCh. 17 - Prob. 17.4EPCh. 17 - Prob. 17.5EPCh. 17 - Prob. 17.6EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Prob. 17.9EPCh. 17 - Prob. 17.10EPCh. 17 - Prob. 17.11EPCh. 17 - Prob. 17.12EPCh. 17 - Prob. 17.13EPCh. 17 - Prob. 17.14EPCh. 17 - Prob. 17.15EPCh. 17 - Assign a common name to each of the following...Ch. 17 - Prob. 17.17EPCh. 17 - Prob. 17.18EPCh. 17 - Prob. 17.19EPCh. 17 - Prob. 17.20EPCh. 17 - Prob. 17.21EPCh. 17 - Prob. 17.22EPCh. 17 - Prob. 17.23EPCh. 17 - Prob. 17.24EPCh. 17 - Prob. 17.25EPCh. 17 - Prob. 17.26EPCh. 17 - Prob. 17.27EPCh. 17 - Prob. 17.28EPCh. 17 - Prob. 17.29EPCh. 17 - Prob. 17.30EPCh. 17 - Prob. 17.31EPCh. 17 - Prob. 17.32EPCh. 17 - Prob. 17.33EPCh. 17 - Prob. 17.34EPCh. 17 - Determine the maximum number of hydrogen bonds...Ch. 17 - Prob. 17.36EPCh. 17 - Prob. 17.37EPCh. 17 - Prob. 17.38EPCh. 17 - Prob. 17.39EPCh. 17 - Prob. 17.40EPCh. 17 - Prob. 17.41EPCh. 17 - Prob. 17.42EPCh. 17 - Prob. 17.43EPCh. 17 - Prob. 17.44EPCh. 17 - Prob. 17.45EPCh. 17 - Prob. 17.46EPCh. 17 - Prob. 17.47EPCh. 17 - Prob. 17.48EPCh. 17 - Prob. 17.49EPCh. 17 - Prob. 17.50EPCh. 17 - Prob. 17.51EPCh. 17 - Prob. 17.52EPCh. 17 - Prob. 17.53EPCh. 17 - Prob. 17.54EPCh. 17 - Prob. 17.55EPCh. 17 - Prob. 17.56EPCh. 17 - Prob. 17.57EPCh. 17 - Prob. 17.58EPCh. 17 - Prob. 17.59EPCh. 17 - Prob. 17.60EPCh. 17 - Prob. 17.61EPCh. 17 - Prob. 17.62EPCh. 17 - Prob. 17.63EPCh. 17 - Prob. 17.64EPCh. 17 - Prob. 17.65EPCh. 17 - Prob. 17.66EPCh. 17 - Prob. 17.67EPCh. 17 - Prob. 17.68EPCh. 17 - Prob. 17.69EPCh. 17 - Prob. 17.70EPCh. 17 - Prob. 17.71EPCh. 17 - Prob. 17.72EPCh. 17 - Prob. 17.73EPCh. 17 - Prob. 17.74EPCh. 17 - Prob. 17.75EPCh. 17 - Prob. 17.76EPCh. 17 - Prob. 17.77EPCh. 17 - Prob. 17.78EPCh. 17 - Prob. 17.79EPCh. 17 - Prob. 17.80EPCh. 17 - Prob. 17.81EPCh. 17 - Prob. 17.82EPCh. 17 - Prob. 17.83EPCh. 17 - Prob. 17.84EPCh. 17 - Prob. 17.85EPCh. 17 - Prob. 17.86EPCh. 17 - Prob. 17.87EPCh. 17 - Prob. 17.88EPCh. 17 - Prob. 17.89EPCh. 17 - Prob. 17.90EPCh. 17 - Prob. 17.91EPCh. 17 - Prob. 17.92EPCh. 17 - Prob. 17.93EPCh. 17 - Prob. 17.94EPCh. 17 - Prob. 17.95EPCh. 17 - Prob. 17.96EPCh. 17 - Prob. 17.97EPCh. 17 - Prob. 17.98EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the amides in Problem 17-101 as a...Ch. 17 - Prob. 17.104EPCh. 17 - Prob. 17.105EPCh. 17 - Prob. 17.106EPCh. 17 - Prob. 17.107EPCh. 17 - Prob. 17.108EPCh. 17 - Prob. 17.109EPCh. 17 - Prob. 17.110EPCh. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Prob. 17.113EPCh. 17 - Prob. 17.114EPCh. 17 - Prob. 17.115EPCh. 17 - Prob. 17.116EPCh. 17 - Prob. 17.117EPCh. 17 - Prob. 17.118EPCh. 17 - Prob. 17.119EPCh. 17 - What is the relationship between the acronym DEET...Ch. 17 - Prob. 17.121EPCh. 17 - Prob. 17.122EPCh. 17 - Prob. 17.123EPCh. 17 - Prob. 17.124EPCh. 17 - Prob. 17.125EPCh. 17 - Prob. 17.126EPCh. 17 - Prob. 17.127EPCh. 17 - Prob. 17.128EPCh. 17 - Prob. 17.129EPCh. 17 - Prob. 17.130EPCh. 17 - Prob. 17.131EPCh. 17 - Prob. 17.132EPCh. 17 - Prob. 17.133EPCh. 17 - Prob. 17.134EPCh. 17 - Prob. 17.135EPCh. 17 - Prob. 17.136EPCh. 17 - Prob. 17.137EPCh. 17 - Prob. 17.138EPCh. 17 - Prob. 17.139EPCh. 17 - Prob. 17.140EPCh. 17 - Prob. 17.141EPCh. 17 - Prob. 17.142EPCh. 17 - Prob. 17.143EPCh. 17 - Prob. 17.144EPCh. 17 - Prob. 17.145EPCh. 17 - Prob. 17.146EPCh. 17 - Prob. 17.147EPCh. 17 - Prob. 17.148EPCh. 17 - Prob. 17.149EPCh. 17 - Prob. 17.150EPCh. 17 - Prob. 17.151EPCh. 17 - Prob. 17.152EPCh. 17 - Prob. 17.153EPCh. 17 - Prob. 17.154EP
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