EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 17, Problem 17.35AP
Interpretation Introduction
Interpretation:
Whether the compound A or B undergo the more rapid reaction with
Concept introduction:
An elimination reaction is a type of reaction in which two atoms are eliminated in the presence of solvent. Elimination reactions usually favors in the alcoholic conditions. The β-elimination follows
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a) If the pH value of an aqueous solution of trimethylamine [(CH3)3N] is 10.75, what should be the molarity of this solution?
(CH3)3N + H2O ↔ (CH3)3NH+ + OH-, Kb = 6,3 × 10-5
b) What will be the pH of the solution prepared by dissolving 8.35 g of aniline hydrochloride (C6H5NH3+Cl-) in 750 mL of 0.215 M aniline (C6H5NH2)? Is this solution an effective buffer? Explain (Kb = 7,4 × 10-10 for aniline, C: 12.0 g / mol, H: 1.0 g / mol, N: 14.0 g / mol, Cl: 35.4 g / mol) .
b)
i)
ii)
iii)
Consider the following reaction scheme to answer questions (i) to (iii)
Br
Mg
Ether
MgBr
Product 2 was never obtained from the reaction shown above, provide a brief explanation
as to why this reaction didn't work.
Give the structure(s) of the compound that will form under these conditions.
The researchers then decided to change the starting material and reaction conditions, to
those shown below, and were able to obtain product 2 in 98% yield. Provide a detailed
mechanism on how reactants 3 and 4 lead to the formation of product 2.
The presence of a pi bond also makes a compound a base. With this in mind, draw the conjugate acid of ethylene, CH2=CH2.
Chapter 17 Solutions
EBK ORGANIC CHEMISTRY
Ch. 17 - Prob. 17.1PCh. 17 - Prob. 17.2PCh. 17 - Prob. 17.3PCh. 17 - Prob. 17.4PCh. 17 - Prob. 17.5PCh. 17 - Prob. 17.6PCh. 17 - Prob. 17.7PCh. 17 - Prob. 17.8PCh. 17 - Prob. 17.9PCh. 17 - Prob. 17.10P
Ch. 17 - Prob. 17.11PCh. 17 - Prob. 17.12PCh. 17 - Prob. 17.13PCh. 17 - Prob. 17.14PCh. 17 - Prob. 17.15PCh. 17 - Prob. 17.16PCh. 17 - Prob. 17.17PCh. 17 - Prob. 17.18PCh. 17 - Prob. 17.19PCh. 17 - Prob. 17.20PCh. 17 - Prob. 17.21PCh. 17 - Prob. 17.22APCh. 17 - Prob. 17.23APCh. 17 - Prob. 17.24APCh. 17 - Prob. 17.25APCh. 17 - Prob. 17.26APCh. 17 - Prob. 17.27APCh. 17 - Prob. 17.28APCh. 17 - Prob. 17.29APCh. 17 - Prob. 17.30APCh. 17 - Prob. 17.31APCh. 17 - Prob. 17.32APCh. 17 - Prob. 17.33APCh. 17 - Prob. 17.35APCh. 17 - Prob. 17.36APCh. 17 - Prob. 17.37APCh. 17 - Prob. 17.38APCh. 17 - Prob. 17.39APCh. 17 - Prob. 17.40APCh. 17 - Prob. 17.41APCh. 17 - Prob. 17.42APCh. 17 - Prob. 17.43APCh. 17 - Prob. 17.44APCh. 17 - Prob. 17.45APCh. 17 - Prob. 17.46APCh. 17 - Prob. 17.47APCh. 17 - Prob. 17.48APCh. 17 - Prob. 17.49APCh. 17 - Prob. 17.50APCh. 17 - Prob. 17.51APCh. 17 - Prob. 17.52APCh. 17 - Prob. 17.53APCh. 17 - Prob. 17.54APCh. 17 - Prob. 17.55APCh. 17 - Prob. 17.56APCh. 17 - Prob. 17.57APCh. 17 - Prob. 17.58APCh. 17 - Prob. 17.59AP
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