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Concept explainers
(a)
Interpretation:
The
Concept introduction:
Carboxylic acid: One
Amide: One
Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.
- Primary amide is produce when a carboxylic acid reacts with ammonia.
- Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.
- Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine
(b)
Interpretation:
The carboxylic acid and amine that are needed to form the given amide in problem 17.58 has to be determined.
Concept introduction:
Carboxylic acid: One
Amide: One
Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.
- Primary amide is produce when a carboxylic acid reacts with ammonia.
- Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.
- Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine
(c)
Interpretation:
The carboxylic acid and amine that are needed to form the given amide in problem 17.58 has to be determined.
Concept introduction:
Carboxylic acid: One
Amide: One
Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.
- Primary amide is produce when a carboxylic acid reacts with ammonia.
- Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.
- Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine
(d)
Interpretation:
The carboxylic acid and amine that are needed to form the given amide in problem 17.58 has to be determined.
Concept introduction:
Carboxylic acid: One
Amide: One
Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.
- Primary amide is produce when a carboxylic acid reacts with ammonia.
- Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.
- Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine
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Chapter 17 Solutions
Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
- Name a naturally occurring carbohydrate and its source for each type of carbohydrate listed in Problem 20.83.arrow_forwardSalicylic acid (o-hydroxybenzoic acid) is used as starting material to prepare aspirin. Draw the structure of salicylic acid.arrow_forwardFumaric acid is a metabolic intermediate that has the systematic name trans-2-butenedioic acid. Draw its structure.arrow_forward
- Which form of aspartic acid in Problem 18.54 is the zwitterion? What is the pI for the zwitterion?arrow_forwardGive one specific sample structure (Fischer Projection or Haworth) of the following carbohydrate derivatives: - Alditols - Deoxy-sugararrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon sugars.) 1 СНО 2 СНО СНО Н-С—ОН Н-С—ОН Н—С—ОН Н-С—ОН НО —С—Н Н-С—ОН Н- С—ОН НО—С— Н НО—С—Н CH̟OH CH̟OH ČH̟OH в iоchemistry |61 STATE ATION Republic of the Philippines Romblon State University Romblan, Philippines 4 СНО 5 СНО 6 СНО НО—С—Н Н-С—ОН НО -С—Н Н—С—ОН НО -С—Н НО -С—Н H-C–OH Н-С—ОН НО—С—Н CH,OH ČH,OH CH,OHarrow_forward
- Give one specific sample structure (Fischer Projection or Haworth) of the following carbohydrate derivatives: - Amino-sugararrow_forwardWhat is unusual about glutathione’s structure? (If you cannot answer this question, draw the structure you would expect for the tripeptide and compare your structure with the actual structure.)arrow_forwardDrawn are four isomeric dimethylcyclopropanes. How are the compounds in each pair related (enantiomers, diastereomers, constitutional isomers): A and B; A and C; B and C; C and D?arrow_forward
- In the monosaccharide derivatives known as sugar alcohols, the carbonyl oxygen is reduced to a hydroxyl group. For example, D-glyceraldehyde can be reduced to glycerol. However, this sugar alcohol is no longer designated D or L. Why?arrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers. CHO сно H-C- OH H-C-OH H-C- OH но-с — н н-с—он но- ČHOH ČH,OH сно CHO Н-с—он но—с— н H-C- OH H-C-OH но—с—н Н-с—он ČHOH ČH,OH сно сно н-с—он но—с —н но—с— н но -с — н H-C- OH но- C-H ČH,OH ČH,OHarrow_forwardTrehalose, a disaccharide found in the blood of insects, has the following structure. What simple sugars would you obtain on hydrolysis of trehalose?arrow_forward
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