PEARSON ETEXT FOR CAMPBELL BIOLOGY
12th Edition
ISBN: 9780135988046
Author: Urry
Publisher: PEARSON
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Chapter 17.4, Problem 3CC
Summary Introduction
To draw: Each codon on a messenger RNA (mRNA) that can bind to anticodon 3′-CGU-5′, tRNA molecule, and the amino acid it carries.
Concept introduction:
The genetic information of DNA is based on the
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codon: 1 2 3 4 5 6 7
sequence: TAC ATG GAC AAT GAT TAG GGG
1. What is the sequence of the peptide that would result following translation with a ribosome?
Write your answer like this Met Ala Gly......
2. What mutation(s) would change the peptide to Met Asp Asn Gly Leu Gly ?
Use the codon numbers to help describe where the mutation is located
. What mutation(s) would eliminate peptide translation?
Use the codon numbers to help describe where the mutation is located
Open reading frames...
correspond to introns, which are not read by the ribosome during translation
correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in a particular frame
correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in any of six frames
are often rich in acetylated histones which allow transcription
occur when fragments of DNA sequence are highly similar between two species
are recognized by ribosomes to initiate translation
WHAT IF? DRAW IT Draw a tRNA with the anticodon3¿-CGU-5¿. What two different codons could it bind to?Draw each codon on an mRNA, labeling all 5¿ and 3¿ends, the tRNA, and the amino acid it carries.
Chapter 17 Solutions
PEARSON ETEXT FOR CAMPBELL BIOLOGY
Ch. 17.1 - Prob. 1CCCh. 17.1 - What polypeptide product would you expect from a...Ch. 17.1 - Prob. 3CCCh. 17.2 - MAKE CONNECTIONS In a research artide about...Ch. 17.2 - What enables RNA polymerase to start transcribing...Ch. 17.2 - WHAT IF? Suppose X-rays caused a sequence change...Ch. 17.3 - There are about 20,000 human protein-coding genes....Ch. 17.3 - How is RNA splicing similar to how you would watch...Ch. 17.3 - Prob. 3CCCh. 17.4 - What two processes ensure that the correct amino...
Ch. 17.4 - Prob. 2CCCh. 17.4 - Prob. 3CCCh. 17.4 - WH AT IF? In eukaryotic cells, mRNAs have been...Ch. 17.5 - What happens when one nucleotide pair is lost from...Ch. 17.5 - MAKE CONNECTIONS Individuals heterozygous for the...Ch. 17.5 - WHAT IF? DRAW IT The template strand of a gene...Ch. 17.5 - Prob. 4CCCh. 17 - Describe the process of gene expression, by which...Ch. 17 - What are the similarities and differences in the...Ch. 17 - What function do the 5' cap and the poly-A tail...Ch. 17 - Prob. 17.4CRCh. 17 - What will be the results of chemically modifying...Ch. 17 - In eukaryotic cells, transcription cannot begin...Ch. 17 - Prob. 2TYUCh. 17 - The anticodon of a particular tRNA molecule is (A)...Ch. 17 - Prob. 4TYUCh. 17 - Which component is not directly involved in...Ch. 17 - Using Figure 17.6, identify a 5' 3' sequence of...Ch. 17 - Prob. 7TYUCh. 17 - Would the coupling of the processes shown in...Ch. 17 - Prob. 9TYUCh. 17 - Prob. 10TYUCh. 17 - scientific inquiry Knowing that the genetic code...Ch. 17 - Prob. 12TYUCh. 17 - Prob. 13TYU
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- . What is the minumum number of tRNA molecules that a cell must contain in order to translate all 61 sense codons?arrow_forwardSA p PDF as trasc d PDF During the translation of an mRNA segment, different activated tRNAs (aatRNAs)-specified here by their anticodons written 3' to 5' bind through hydrogen bonds to mRNA in subscripts-successively codons in the following order: Teas fill PDF Cave UNOFFIC aatRNAGAA binds, then aatRNACAC, then aatRNAUUG, then aatRNAGUU, then aatRNAGUG, then aatRNAGAC What would the sequence of that mRNA segment be? O GAA CAC UUG GUU GUG GAC O CUU GUG AAC CAA CAC CUG O CTT GTG AAC CAA CAC CTG O Glu-His-Leu-Val-Val-Asp hu O Search PD maste omissarrow_forward10. A portion of 5'-AUGCCACGAGUUGAC-3'. What amino acid sequence does this code for? To answer the question please: I) explain what is the genetic code and list the properties of the genetic e 2) draw a diagram of protein synthesis; 3) determine which tRNA should be attached to the mRNA; 4) what is the anticodon for the very first tRNA that will attach to mRNA? mRNA molecule has the sequence anarrow_forward
- AAAGAGAAAAGAAUA to AAAGAGAAAUGAAUA. Suppose the codon sequence has a single base pair mutation If the old protein sequence was Lys-Glu-Lys-Arg-Ile, what will be the new sequence encoded by the mutant gene? (Use the 3-letter amino acid abbreviations with hyphens and no spaces in between, i.e. Ser-Asn-Tyr-Leu-Pro.) Submit Answer Retry Entire Group No more group attempts remainarrow_forwardRefer to the codon diagram on. Which of the following is a codon that will terminate translation?* ates es Ders rences anline Gly (G) Leu (F) Ser (S) Ty 3. Asp (E) (D) C la Ala (A) GU Cys (C) eriods 1 and 2 G ds P1, Highschool pol MP3, P4 Trp (W) AC Arg (R) Leu (L) Ser (S) Lys (K) C. Pro Asn (N) (P) His The (H) Thu Fri Gin (0) INTLarrow_forwardPLEASE FL OUT TABLE USING INSTRXUTIONS -USE BASE PAIRING RULES TO COMPLETE SECOND COLUMN FOR EACH MUTATION WRIYE IN ANY MRNA DOEONS RHAT WILL BE FHANGED AS THE REEULR OF RHE MURATION AND USE X MARKS RO INDÍCATE DOONS THAT WONT BE FHANGES CIRCLE STOP CODONSarrow_forward
- Translation. Write the anti-codon sequence of the MRNA transcript. Translate the MRNA transcript into peptide sequence using both the 3 letter abbreviation and 1 letter abbreviation. ANTI-CODON 3' 5' SEQUENCE AMINO ACID N- C- SEQUENCE (3 letter terminus Abbreviation) Terminus AMINO ACID N- C- SEQUENCE (1 letter terminus Abbreviation) Terminusarrow_forward5’-AUGCCGGACUGAAAU-3’ What is the sequence of the resulting protein assuming the ribosome takes the first AUG as triplet codon ?arrow_forwardChrome ... x ← C Port A m ERNA F i t DESE a e d Use the codon table to determine which mRNA triplets code for the amino acid cysteine, Cys. Second mRNA base C A (5' 0 f COTON COCO с b CUA OG Course H U 000 UUU UUC UUA UUG CUU CUC CUG AUU AUA AUG Submit GUU mylabmastering.pearson.com/?courseid=12411621&key=28... ☆ GUC AUC lle UGG UGC UGU ACA AGU U 833 Phe Leu GUA n) GUG Select all that apply. Leu View Met or start Val UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG 160 History Bookmarks Profiles Tab Window Help QuickLaun X Thr Request Answer Ser Pro Ala UAU UAC UAA Stop UAG Stop CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr His Gin Asn Lys Asp Glu CGA UGU UGC UGA Stop A UGG Trp G CGU U CGC CGG AGU AGC AGA AGG GGU GGC GGA QuickLaury X G GGG Cys Arg Ser Arg Gly NOV 6 UT h CA A b a G U C G So OcO O COTON Right to be (3¹ X Gn) M (no subje x ☆出口口 **** 31 + U JOarrow_forward
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