Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 18, Problem 14P
Given that maternal Bicoid activates the expression of hunchback (see Figure
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A maternal effect gene in Drosophila, called torso, is found as a recessive allele that prevents the correct development of anterior- and posterior-most structures. A wild-type (homozygous) male is crossed to a female of unknown genotype. This mating produces 100% larva that are missing their anterior- and posterior-most structures and therefore die during early development. What is the genotype and phenotype of the female fly in this cross? What are the genotypes and phenotypes of the female fly’s parents? Show COMPLETE cross.
Why is it that mutations in bicoid and nanos exhibit genetic maternal effect in Drosophila (a mutation in the maternal parent produces a phenotype that shows up in the offspring), but mutations in runt and gooseberry do not?
Imagine a scenario in which prenatal testing of a human female fetus indicates that the baby will have a normal XX karyotype but is heterozygous for a mutation that inactivates the Xist promoter. Allele “Xr” represents the mutated version of the Xist promoter, and “XR” represents the normal version of the Xist promoter.
How will this mutation affect the process of X inactivation?A. "X inactivation will still be random with both mutant and normal X chromosomes being randomly inactivated"
B. "The chromosome with the mutant Xist promoter will always be active"
C. "The chromosome with the mutant Xist promoter will always be inactivated"
D. "The normal X chromosome (no mutation in Xist) will always be active"
E. "The normal X chromosome (no mutation in Xist) will always be inactivated"
Chapter 18 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 18 - 18.1 Explain why many developmental genes encode...Ch. 18 - Bird beaks develop from an embryonic group of...Ch. 18 - 18.3 How is positional information provided along...Ch. 18 - Early development in Drosophila is atypical in...Ch. 18 - 18.5 Consider the evenskipped regulatory sequences...Ch. 18 - What is the difference between a parasegment and...Ch. 18 - Why do loss-of-function mutations in Hox genes...Ch. 18 - 18.8 Compare and contrast the specification of...Ch. 18 - Prob. 9PCh. 18 - Ablation of the anchor cell in wild type C....
Ch. 18 - 18.11 In gain-of-function and. elegans mutants,...Ch. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - 18.14 Given that maternal Bicoid activates the...Ch. 18 - What phenotypes do you expect in flies homozygous...Ch. 18 - The pair rule gene fushitarazu is expressed in...Ch. 18 - 18.17 In contrast to Drosophila, some insects...Ch. 18 - Prob. 18PCh. 18 - 18.19 You are traveling in the Netherlands and...Ch. 18 - 19.20 A powerful approach to identifying genes of...Ch. 18 - The Hoxd 913 genes are thought to specify digit...Ch. 18 - Three-spined stickleback fish live in lakes formed...Ch. 18 - The flowering jungle plant Lacandoniaschismatica,...Ch. 18 - 18.24 Homeotic genes are thought to regulate each...Ch. 18 - Prob. 25PCh. 18 - Basidiomycota is a monophyletic group of fungi...Ch. 18 - Prob. 27PCh. 18 - In C. elegans there are two sexes: hermaphrodite...Ch. 18 - In Drosophila, recessive mutations in the...
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- A maternal effect gene in Drosophila, called torso, is found as a recessive allele that prevents the correct development of anterior- and posterior-most structures. A wild-type (homozygous) male iscrossed to a female of unknown genotype. This mating produces 100% larva that are missing theiranterior- and posterior-most structures and therefore die during early development. What is the genotype and phenotype of the female fly in this cross? What are the genotypes andphenotypes of the female fly’s parents? Show COMPLETE cross. Maternal genotype:Paternal genotype:F1 genotype:F1 phenotype:arrow_forwardIn Drosophila, one of the genes controlling wing length is located on the X chromosome. A recessive mutant allele of this gene makes the wings miniature—hence, its symbol m; the wild-type allele of this gene, m_, makes the wings long. One of the genes controlling eye color is located on an autosome. A recessive mutant allele of this gene makes the eyes brown—hence, its symbol bw; the wildtype allele of this gene, bw_, makes the eyes red. Miniature-winged, red-eyed females from one true-breeding strain were crossed to normal-winged, brown-eyed males from another true-breeding strain. 1. Predict the phenotypes of the F1 flies. 2. If these flies are intercrossed with one another, what phenotypes will appear in the F2, and in what proportions?arrow_forwardWhat would you predict to be the phenotype of a Drosophila larva whose mother was homozygous for a loss-of-function allele in the nanos gene?arrow_forward
- How do we know that the mutant Bar-eye phenotype in Drosophila is due to a duplicated gene region rather than to a change in the nucleotide sequence of a gene?arrow_forwardIn a particular organism, there are two similar genes called YFG1 and YFG2. YFG1 is expressed in the liver and not in the pancreas, and YFG2 is expressed in the pancreas but not the liver. Neither YFG1 nor YFG2 is expressed in the heart. If you extract DNA from heart cells, do you expect to see the YFG2 gene? Explain why. Do you expect to see the YFG1 protein when you analyze protein extract from liver cells? And from pancreas cells? And from heart cells? Explain why. Is it possible to produce YFG1 and YFG2 proteins via alternative splicing? Explain one possible way (mechanism) to regulate the expression of YFG1 gene.arrow_forwardWould the pattern of segment-polarity gene expression be normal if one or more gap genes were not expressed properly? Why or why not?arrow_forward
- In Drosophila subobscura, the presence of a recessive gene called grandchildless (gs) causes the offspring of homozygous females, but not those of homozygous males, to be sterile. Can you offer an explanation as to why females and not males are affected by the mutant gene?arrow_forwardThe locations of six deletions have been mapped to a Drosophila chromosome, as shown in the following deletion map. Recessive mutations a, b, c, d, e, and f are known to be located in the same region as the deletions, but the order of the mutations on the chromosome is not known. (refer image for contination )arrow_forwardFigure 19.25 shows that the Sxl protein binds to the mRNA of the msl-2 gene, inhibiting translation of the mRNA’s proper reading frame. The MSL-2 protein is a transcription factor that binds to the X chromosome in XY males to double the level of X-linked gene transcription, thus equalizing X-linked gene expression in XY males and XX females. a. In which sex, XY males or XX females, would the Sxl protein bind to the msl-2 mRNA? b. As discussed in Problem 35, some Sxl alleles are lethal to females and others are lethal to males. Is the function of Sxl in regulating the synthesis of Msl-2 protein sufficient to explain the sex-specific lethality caused by both kinds of alleles? c. Predict the effect of loss-of-function mutations in msl-2 on male and female fertility and viability.arrow_forward
- A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? a. 1/8 b. 1/16 c.1/2 d. 3/16 e. 1/3 f. 3/4 g. 15/16 h. 2/3 i. 1/4arrow_forwardSeveral Drosophila species with unspotted wings are descended from a spotted ancestor. Would you predict the loss of spot formation to entail coding or noncoding changes in pigmentation genes? How would you test which is the case?arrow_forwardIn the haplodiploid system of sex determination in honey bees: a. homozygosity at the csd locus results in male-specific mRNA from the fem and Am-dsx genes, ultimately resulting in the development of an inviable diploid drone. b. the csd gene codes for CSD proteins, which splice the mRNA from the hunchback and gurken genes into female specific RNAs that code for female specific proteins. c. heterozygosity at the csd locus results in mRNA from the fem gene being spliced into femF which is transcribed into active FEM proteins that establish a positive feedback splicing loop that contributes to the development of a diploid female. d. heterozygosity for the Am-dsx gene results in mRNAs that ultimately contribute to the development of an aggressive, dominant queen, whereas homozygosity for the Am-dsx gene results mRNAs that contribute to the development of a subordinate, non-aggressive sterile worker. e. all of these are correct f. a & c g. b & darrow_forward
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