ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
2nd Edition
ISBN: 9780393664034
Author: KARTY
Publisher: NORTON
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Chapter 18, Problem 18.69P
Interpretation Introduction

(a)

Interpretation:

The synthesis of the given compound using the cyclopentanone as one of the reagents is to be suggested.

Concept introduction:

In aldol condensation, the aldehyde or ketone with α hydrogen in the presence of a strong base like hydroxide or alkoxide produces β hydroxyl carbonyl compound which in turn undergoes dehydration and forms α,β- unsaturated carbonyl compound. The reaction proceeds with formation of enolate ion. The synthesis of α,β- unsaturated carbonyl compound can be planned by retrosynthetic analysis. The precursor used in aldol condensation can be identified by disconnecting the double bond between α and β carbons. The bond disconnection is indicated by the wavy line.

Expert Solution
Check Mark

Answer to Problem 18.69P

The synthesis of the given compound using cyclopentanone as one of the reagents is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  1

Explanation of Solution

The given compound is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  2

The given compound is a α,β- unsaturated ketone, the double bond between α and β carbons is disconnected to arrive at the precursor used in its synthesis. As mentioned, one of the reagent used must be cyclopentanone. The retrosynthetic analysis is as follows:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  3

The precursor determined is cyclopentanone. Two molecules of cyclopentanone are used in the aldol condensation. Cyclopentanone, on reaction with a strong base, forms the given α,β- unsaturated ketone through the formation of β hydroxyl carbonyl compound. The dehydration of β hydroxyl carbonyl compound is carried out by heating, and can be represented as Δ on the reaction arrow. The synthesis planned is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  4

Conclusion

The synthesis of the given compound is planned by identifying the precursor used with disconnection of bond.

Interpretation Introduction

(b)

Interpretation:

The synthesis of the given compound using cyclopentanone as one of the reagents is to be suggested.

Concept introduction:

In aldol condensation, the aldehyde or ketone with α hydrogen in presence of a strong base like hydroxide or alkoxide produces β hydroxyl carbonyl compound which in turn undergoes dehydration and forms α,β- unsaturated carbonyl compound. In cross-aldol condensation, two different carbonyl compounds react where one carbonyl compound having α hydrogen reacts with the base to form an enolate ion, which further adds to another carbonyl compound. The synthesis of α,β- unsaturated carbonyl compound can be planned by retrosynthetic analysis. The precursor used in aldol condensation can be identified by disconnecting the double bond between α and β carbons. The bond disconnection is indicated by the wavy line.

Expert Solution
Check Mark

Answer to Problem 18.69P

The synthesis of the given compound using cyclopentanone as one of the reagents is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  5

Explanation of Solution

The given compound is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  6

The given compound is α,β- unsaturated ketone, the double bond between α and β carbon is disconnected to arrive at the precursor used in its synthesis. As mentioned, one of the reagents used must be cyclopentanone. The retrosynthetic analysis is as follows:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  7

The precursors determined are cyclopentanone and benzaldehyde. As the benzaldehyde has no α hydrogen, the enolate can be produced by the reaction of cyclopentanone with a strong base like hydroxide. The enolate on reaction with benzaldehyde produces the given α,β- unsaturated ketone through the formation of β hydroxyl carbonyl compound. The dehydration of β hydroxyl carbonyl compound is carried out by heating, and can be represented as Δ on the reaction arrow. The synthesis planned is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  8

Conclusion

The synthesis of the given compound is planned by identifying the precursor used with disconnection of bond.

Interpretation Introduction

(c)

Interpretation:

The synthesis of the given compound using cyclopentanone as one of the reagents is to be suggested.

Concept introduction:

In aldol condensation the aldehyde or ketone with α hydrogen in presence of strong base like hydroxide or alkoxide produces β hydroxyl carbonyl compound which in turn undergoes dehydration and forms α,β- unsaturated carbonyl compound. In cross-aldol condensation, two different carbonyl compounds react where one carbonyl compound having α hydrogen reacts with the base to form an enolate ion, which further adds to another carbonyl compound. The synthesis of α,β- unsaturated carbonyl compound can be planned by retrosynthetic analysis. The precursor used in aldol condensation can be identified by disconnecting the double bond between α and β carbons. The bond disconnection is indicated by the wavy line.

Expert Solution
Check Mark

Answer to Problem 18.69P

The synthesis of the given compound using cyclopentanone as one of the reagents is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  9

Explanation of Solution

The given compound is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  10

The given compound is α,β- unsaturated ketone, the double bond between α and β carbon is disconnected to arrive at the precursor used in its synthesis. As mentioned, the one of the reagent used must be cyclopentanone. The retrosynthetic analysis is as follows:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  11

The precursors determined are the cyclopentanone and acetophenone. As the both ketones has α hydrogen, the enolate can be produced by the reaction of one of the ketone with a strong base like hydroxide. The enolate ion then reacts with another ketone and produces the given α,β- unsaturated ketone through formation of β hydroxyl carbonyl compound. The dehydration of β hydroxyl carbonyl compound is carried out by heating, and can be represented as Δ on the reaction arrow. The synthesis planned is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  12

Conclusion

The synthesis of the given compound is planned by identifying the precursor used with disconnection of bond.

Interpretation Introduction

(d)

Interpretation:

The synthesis of the given compound using cyclopentanone as one of the reagents is to be suggested.

Concept introduction:

In aldol condensation the aldehyde or ketone with α hydrogen in presence of strong base like hydroxide or alkoxide produces β hydroxyl carbonyl compound which intern undergoes dehydration and forms α,β- unsaturated carbonyl compound.

Instead of carbonyl compounds, the compounds with polar π bond having α hydrogen like nitrile can also be used in aldol condensation, which can form a nucleophile like enolate ion on deprotonation. The synthesis of α,β- unsaturated nitrile can be planned by retrosynthetic analysis. The precursor used in aldol condensation can be identified by disconnecting the double bond between α and β carbons. The bond disconnection is indicated by the wavy line.

Expert Solution
Check Mark

Answer to Problem 18.69P

The synthesis of the given compound using cyclopentanone as one of the reagents is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  13

Explanation of Solution

The given compound is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  14

The given compound is α,β- unsaturated nitrile, the double bond between α and β carbons is disconnected to arrive at the precursor used in its synthesis. As mentioned, one of the reagent used must be cyclopentanone. The retrosynthetic analysis is as follows:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  15

The precursors determined are cyclopentanone and nitrile compound. As the nucleophile adds to carbonyl, the nucleophile can be produced by the reaction of one of the nitrile with a strong base like hydroxide. The nucleophile then reacts with ketone and produces the given α,β- unsaturated nitrile through the formation of β hydroxyl nitrile compound. The dehydration of β hydroxyl nitrile compound is carried out by heating, can be represented as Δ on the reaction arrow. The synthesis planned is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  16

Conclusion

The synthesis of the given compound is planned by identifying the precursor used with disconnection of bond.

Interpretation Introduction

(e)

Interpretation:

The synthesis of the given compound using cyclopentanone as one of the reagents is to be suggested.

Concept introduction:

The Robinson annulations reaction is the addition of enolate to conjugated carbonyl followed by intramolecular aldol condensation. One of the reactant in Robinson annulations must be α,β- unsaturated carbonyl with at least two α hydrogens and another must be simple aldehyde or ketone having α hydrogen. The simple aldehyde or ketone first reacts with strong base to form enolate ion, which undergo 1, 4- addition across the conjugated carbonyl. The product formed is then undergo intramolecular adol condensation and forms a product forming new six membered ring with α,β- unsaturated carbonyl functional group. The synthesis of α,β- unsaturated nitrile can be planned by retrosynthetic analysis. The precursor used in aldol condensation can be identified by disconnecting the double bond between α and β carbons. The bond disconnection is indicated by the wavy line.

Expert Solution
Check Mark

Answer to Problem 18.69P

The synthesis of given compound using cyclopentanone as one of the reagents is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  17

Explanation of Solution

The given compound is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  18

The given compound is α,β- unsaturated ketone with six membered fused ring system; the double bond between α and β carbon is disconnected to arrive at the intermediate product.

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  19

To get the precursor α,β- unsaturated carbonyl, disconnect the bond between β and γ carbons, then place the double bond between α and β carbons and form a carbonyl at γ carbon. As mentioned, one of the reagent used must be cyclopentanone. The retrosynthetic analysis is as follows:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  20

The precursors determined are the cyclopentanone and α,β- unsaturated ketone. As the enolate adds to conugated carbonyl, the enolate can be produced by the reaction of cyclopentanone with a strong base like hydroxide. The enolate then reacts with α,β- unsaturated ketone and forms 1, 6-dione. The 1, 6-dione then undergoes intramolecular aldol condensation and forms the β hydroxyl ketone with the fused six membered ring compound. Thus is further on dehydration by heating produces desired product. The heat is represented as Δ on reaction arrow. The synthesis planned is:

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 18, Problem 18.69P , additional homework tip  21

Conclusion

The synthesis of given compound is planned by identifying the precursor used with disconnection of bond.

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Chapter 18 Solutions

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5

Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Prob. 18.14PCh. 18 - Prob. 18.15PCh. 18 - Prob. 18.16PCh. 18 - Prob. 18.17PCh. 18 - Prob. 18.18PCh. 18 - Prob. 18.19PCh. 18 - Prob. 18.20PCh. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Prob. 18.23PCh. 18 - Prob. 18.24PCh. 18 - Prob. 18.25PCh. 18 - Prob. 18.26PCh. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Prob. 18.29PCh. 18 - Prob. 18.30PCh. 18 - Prob. 18.31PCh. 18 - Prob. 18.32PCh. 18 - Prob. 18.33PCh. 18 - Prob. 18.34PCh. 18 - Prob. 18.35PCh. 18 - Prob. 18.36PCh. 18 - Prob. 18.37PCh. 18 - Prob. 18.38PCh. 18 - Prob. 18.39PCh. 18 - Prob. 18.40PCh. 18 - Prob. 18.41PCh. 18 - Prob. 18.42PCh. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - Prob. 18.45PCh. 18 - Prob. 18.46PCh. 18 - Prob. 18.47PCh. 18 - Prob. 18.48PCh. 18 - Prob. 18.49PCh. 18 - Prob. 18.50PCh. 18 - Prob. 18.51PCh. 18 - Prob. 18.52PCh. 18 - Prob. 18.53PCh. 18 - Prob. 18.54PCh. 18 - Prob. 18.55PCh. 18 - Prob. 18.56PCh. 18 - Prob. 18.57PCh. 18 - Prob. 18.58PCh. 18 - Prob. 18.59PCh. 18 - Prob. 18.60PCh. 18 - Prob. 18.61PCh. 18 - Prob. 18.62PCh. 18 - Prob. 18.63PCh. 18 - Prob. 18.64PCh. 18 - Prob. 18.65PCh. 18 - Prob. 18.66PCh. 18 - Prob. 18.67PCh. 18 - Prob. 18.68PCh. 18 - Prob. 18.69PCh. 18 - Prob. 18.70PCh. 18 - Prob. 18.71PCh. 18 - Prob. 18.72PCh. 18 - Prob. 18.73PCh. 18 - Prob. 18.74PCh. 18 - Prob. 18.75PCh. 18 - Prob. 18.76PCh. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79PCh. 18 - Prob. 18.80PCh. 18 - Prob. 18.81PCh. 18 - Prob. 18.82PCh. 18 - Prob. 18.83PCh. 18 - Prob. 18.84PCh. 18 - Prob. 18.85PCh. 18 - Prob. 18.86PCh. 18 - Prob. 18.87PCh. 18 - Prob. 18.88PCh. 18 - Prob. 18.89PCh. 18 - Prob. 18.90PCh. 18 - Prob. 18.91PCh. 18 - Prob. 18.92PCh. 18 - Prob. 18.93PCh. 18 - Prob. 18.94PCh. 18 - Prob. 18.95PCh. 18 - Prob. 18.96PCh. 18 - Prob. 18.97PCh. 18 - Prob. 18.98PCh. 18 - Prob. 18.99PCh. 18 - Prob. 18.100PCh. 18 - Prob. 18.101PCh. 18 - Prob. 18.102PCh. 18 - Prob. 18.103PCh. 18 - Prob. 18.1YTCh. 18 - Prob. 18.2YTCh. 18 - Prob. 18.3YTCh. 18 - Prob. 18.4YTCh. 18 - Prob. 18.5YTCh. 18 - Prob. 18.6YTCh. 18 - Prob. 18.7YTCh. 18 - Prob. 18.8YTCh. 18 - Prob. 18.9YTCh. 18 - Prob. 18.10YTCh. 18 - Prob. 18.11YTCh. 18 - Prob. 18.12YTCh. 18 - Prob. 18.13YTCh. 18 - Prob. 18.14YTCh. 18 - Prob. 18.15YT
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