Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 18.1, Problem 3PP
Interpretation Introduction

(a)

Interpretation:

The conjugate acid-base pairs in given reaction is to be identified.

Concept introduction:

The concept of conjugate acid-base pair is given by Bronsted-Lowry.

According to it,

Acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.

When acid donates H+, the species form is conjugate base and when base accepts H+, the species form is conjugate acid.

Expert Solution
Check Mark

Answer to Problem 3PP

Conjugate acid: H2O

Conjugate base: NH3

Explanation of Solution

The equation is:

NH4++OHNH3+H2O

Ammonium ion donates hydrogen ions to form ammonia. So it is conjugate base.

Hydroxide ion accepts proton to form water so it is conjugate acid.

Interpretation Introduction

(b)

Interpretation:

The conjugate acid-base pairs in given reaction is to be identified.

Concept introduction:

The concept of conjugate acid-base pair is given by Bronsted-Lowry.

According to it,

Acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.

When acid donates H+, the species form is conjugate base and when base accepts H+, the species form is conjugate acid.

Expert Solution
Check Mark

Answer to Problem 3PP

Conjugate acid: H3O+

Conjugate base: Br

Explanation of Solution

The equation is:

HBr+H2OH3O++Br

HBr donates hydrogen ions to form Br. So it is conjugate base.

Water accepts proton to form H3O+ so it is conjugate acid.

Interpretation Introduction

(c)

Interpretation:

The conjugate acid-base pairs in given reaction is to be identified.

Concept introduction:

The concept of conjugate acid-base pair is given by Bronsted-Lowry.

According to it,

Acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.

When acid donates H+, the species form is conjugate base and when base accepts H+, the species form is conjugate acid.

Expert Solution
Check Mark

Answer to Problem 3PP

Conjugate acid: HCO3

Conjugate base: OH

Explanation of Solution

The equation is:

CO32+H2OHCO3+OH

Water donates hydrogen ions to form hydroxide ion. So it is conjugate base.

Carbonate ion accepts proton to form HCO3 so it is conjugate acid.

Chapter 18 Solutions

Chemistry: Matter and Change

Ch. 18.1 - Prob. 11SSCCh. 18.2 - Prob. 12PPCh. 18.2 - Prob. 13PPCh. 18.2 - Prob. 14PPCh. 18.2 - Prob. 15PPCh. 18.2 - Prob. 16PPCh. 18.2 - Prob. 17SSCCh. 18.2 - Prob. 18SSCCh. 18.2 - Prob. 19SSCCh. 18.2 - Prob. 20SSCCh. 18.2 - Prob. 21SSCCh. 18.3 - Prob. 22PPCh. 18.3 - Prob. 23PPCh. 18.3 - Prob. 24PPCh. 18.3 - Prob. 25PPCh. 18.3 - Prob. 26PPCh. 18.3 - Prob. 27PPCh. 18.3 - Prob. 28PPCh. 18.3 - Prob. 29PPCh. 18.3 - Prob. 30PPCh. 18.3 - Prob. 31PPCh. 18.3 - Prob. 32PPCh. 18.3 - Prob. 33PPCh. 18.3 - Prob. 34PPCh. 18.3 - Prob. 35SSCCh. 18.3 - Prob. 36SSCCh. 18.3 - Prob. 37SSCCh. 18.3 - Prob. 38SSCCh. 18.3 - Prob. 39SSCCh. 18.3 - Prob. 40SSCCh. 18.3 - Prob. 41SSCCh. 18.3 - Prob. 42SSCCh. 18.3 - Prob. 43SSCCh. 18.4 - Prob. 44PPCh. 18.4 - Prob. 45PPCh. 18.4 - Prob. 46PPCh. 18.4 - Prob. 47PPCh. 18.4 - Prob. 48PPCh. 18.4 - Prob. 49SSCCh. 18.4 - Prob. 50SSCCh. 18.4 - Prob. 51SSCCh. 18.4 - Prob. 52SSCCh. 18.4 - Prob. 53SSCCh. 18.4 - Prob. 54SSCCh. 18 - Prob. 55ACh. 18 - Write a balanced chemical equation that represents...Ch. 18 - Classify each compound as an Arrhenius acid or an...Ch. 18 - Geology When a geologist adds a few drops of HCl...Ch. 18 - Explain the meaning of the relative sizes of the...Ch. 18 - Explain the difference between a monoprotic acid,...Ch. 18 - Why can H+ and H3O+ be used interchangeably in...Ch. 18 - Use the symbols ,, and = to express the...Ch. 18 - Explain how the definition of a Lewis acid differs...Ch. 18 - Prob. 64ACh. 18 - Explain the difference between a strong acid and a...Ch. 18 - Explain why equilibrium arrows are used in the...Ch. 18 - Which of the beakers shown in Figure 18.29 might...Ch. 18 - How would you compare the strengths of two weak...Ch. 18 - Identify the conjugate acid-base pairs in the...Ch. 18 - Prob. 70ACh. 18 - Prob. 71ACh. 18 - Prob. 72ACh. 18 - Prob. 73ACh. 18 - Prob. 74ACh. 18 - What is the relationship between the pOH and the...Ch. 18 - Solution A has a pH of 2.0. Solution B has a pH of...Ch. 18 - \If the concentration of H+ ions in an aqueous...Ch. 18 - Use Le Chátelier's principle to explain what...Ch. 18 - Common Acids and Bases Use the data in Table 18.8...Ch. 18 - Prob. 80ACh. 18 - Prob. 81ACh. 18 - Prob. 82ACh. 18 - Prob. 83ACh. 18 - Prob. 84ACh. 18 - What acid and base must react to produce an...Ch. 18 - What acid-base indicators, shown in Figure 18.24...Ch. 18 - When might a pH meter be better than an indicator...Ch. 18 - sWhat happens when an acid is added to a solution...Ch. 18 - When methyl red is added to an aqueous solution, a...Ch. 18 - Give the name and formula of the acid and the base...Ch. 18 - Prob. 91ACh. 18 - Prob. 92ACh. 18 - In an acid-base titration, 45.78 mL of a sulfuric...Ch. 18 - Prob. 94ACh. 18 - Prob. 95ACh. 18 - Prob. 96ACh. 18 - Prob. 97ACh. 18 - Prob. 98ACh. 18 - Prob. 99ACh. 18 - Prob. 100ACh. 18 - Prob. 101ACh. 18 - Prob. 102ACh. 18 - Prob. 103ACh. 18 - Prob. 104ACh. 18 - Prob. 105ACh. 18 - Prob. 106ACh. 18 - Prob. 107ACh. 18 - Prob. 108ACh. 18 - Prob. 109ACh. 18 - Prob. 110ACh. 18 - Prob. 111ACh. 18 - Prob. 112ACh. 18 - Prob. 113ACh. 18 - Prob. 114ACh. 18 - Prob. 115ACh. 18 - Prob. 116ACh. 18 - Prob. 117ACh. 18 - Prob. 118ACh. 18 - Prob. 119ACh. 18 - Prob. 120ACh. 18 - Prob. 121ACh. 18 - Prob. 122ACh. 18 - Prob. 123ACh. 18 - Prob. 124ACh. 18 - Prob. 125ACh. 18 - Prob. 1STPCh. 18 - Prob. 2STPCh. 18 - Prob. 3STPCh. 18 - Prob. 4STPCh. 18 - Prob. 5STPCh. 18 - Prob. 6STPCh. 18 - Prob. 7STPCh. 18 - Prob. 8STPCh. 18 - Prob. 9STPCh. 18 - Prob. 10STPCh. 18 - Prob. 11STPCh. 18 - Prob. 12STPCh. 18 - Prob. 13STPCh. 18 - Prob. 14STPCh. 18 - Prob. 15STPCh. 18 - Prob. 16STPCh. 18 - Prob. 17STPCh. 18 - Prob. 18STP
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