   # Given that Δ H° = −2219 kJ/mol-rxn and that Δ r S ° = −216 J/K · mol-rxn at 25 °C, determine the value of Δ r G ° at 25 °C for the reaction C 3 H 8 (g) + 5 O 2 (g) → 3 CO 2 (g) + 4 H 2 O( l ) (a) −2283 kJ/mol-rxn (b) −2214 kJ/mol-rxn (c) −2155 kJ/mol-rxn (d) 6218 × 10 4 kJ/mol-rxn ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 18.7, Problem 1RC
Textbook Problem
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## Given that ΔH° = −2219 kJ/mol-rxn and that ΔrS° = −216 J/K · mol-rxn at 25 °C, determine the value of ΔrG° at 25 °C for the reactionC3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l) (a) −2283 kJ/mol-rxn (b) −2214 kJ/mol-rxn (c) −2155 kJ/mol-rxn (d) 6218 × 104 kJ/mol-rxn

Interpretation Introduction

Interpretation: the value of ΔrG will be identified for the values for ΔrH and ΔrS from the given options.

Concept introduction:

The relation between ΔrG , ΔrH and ΔrS is,

ΔrG=ΔrHTΔrS

### Explanation of Solution

For the given reaction,

ΔrH is 2219kJ/mol

ΔrS is 216J/Kmol=0.216kJ/Kmol

The relation between ΔrG , ΔrH and ΔrS is,

ΔrG=ΔrHTΔrS

Therefore,

ΔrG=2219kJ/mol(298K×(0.216kJ/Kmol)) =2219+64

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