# Using values of Δ r G °, determine the value of Δ r G° at 25 °C for the reaction 2 KClO 3 (s) 2 KCl(s) + 3 O 2 (g) (a) −225 kJ/mol-rxn (b) −112 kJ/mol-rxn (c) 112 kJ/mol-rxn (d) 225 kJ/mol-rxn

### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Chapter
Section

### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 18.7, Problem 2RC
Textbook Problem
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## Using values of ΔrG°, determine the value of ΔrG° at 25 °C for the reaction2 KClO3(s) 2 KCl(s) + 3 O2(g) (a) −225 kJ/mol-rxn (b) −112 kJ/mol-rxn (c) 112 kJ/mol-rxn (d) 225 kJ/mol-rxn

Interpretation Introduction

Interpretation: the value of ΔrG will be identified by using values of ΔfG in the reaction from the given options.

Concept introduction:

ΔrG is the change in entropy at standard condition and it is calculated by sum of the product of stoichiometric coefficients and molar free energies of products minus sum of the product of stoichiometric coefficients and molar free energies of reactants. That is,

ΔrG=nΔfG(products)nΔfG(reactants)

### Explanation of Solution

For the given reaction,

ΔfG for KClO3 is 296.25kJ/mol

ΔfG for KCl is 408.77kJ/mol

The equation for finding ΔrG from ΔfG values is,

ΔrG=nΔfG(products)nΔfG(reactants)

Therefore,

ΔrG=(2×296

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