Concept explainers
Interpretation:
In 1HNMR, Disparlure, C19H38O, shows a large absorption in the alkane region, 1 to 2 δ and a triplet at 2.8 δ. Treatment of Disparlure first with aqueous acid and then with KMnO4 yielded undecanoic acid and 6-methylheptanoic acid. A structure for disparlure is to be proposed neglecting stereochemistry. Its structure also is to be given with stereochemistry if the actual compound is a chiral molecule with 7R, 8S stereochemistry.
Concept introduction:
In 1HNMR, the
Epoxides get protonated in the presence of acids and the nucleophilic attack of water opens the epoxide ring to give a
To propose:
A structure for disparlure neglecting stereochemistry, satisfying the 1HNMR data and the
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Chapter 18 Solutions
ORGANIC CHEMISTRY-EBOOK>I<
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardKetones undergo a reduction when treated with sodium borohydride, NaBH4. What is the structure of the compound produced by reaction of 2-butanone with NaBH4 if it has an IR absorption at 3400 cm-1 and M+=74 in the mass spectrum?arrow_forwardIdentify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forward
- Treatment of benzoic acid (C6H5CO2H) with NaOH followed by 1-iodo-3methylbutane forms H. H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960−2872, and 1721 cm−1. Propose a structure for H.arrow_forwardPropose a structure for compound X (molecular formula C6H12O2), which gives a strong peak in its IR spectrum at 1740 cm−1. The 1H NMR spectrum of X shows only two singlets, including one at 3.5 ppm. The 13C NMR spectrum is given below. Propose a structure for X.arrow_forwardCompound A, C8H10O, has the IR and 1H NMR spectra shown. Propose a structure consistent with the observed spectra, and label each peak in the NMR spectrum. Note that the absorption at 5.5 î disappears when D2O is added.arrow_forward
- Compound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound.arrow_forwardPropose a structural formula for compound A, C5H13N, given its IR and calculated 1H-NMR spectra.arrow_forwardIdentify the structure of compound A (molecular formula C9H10O) from the 1H NMR and IR spectra given.arrow_forward
- Alpha-phellandrene, C₁0H₁6, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C₁0H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: 0 || CH3C-CH 0 || ● Propose a structure for alpha-phellandrene. (+ || HCCH₂CHCH I CH(CH3)2 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. n [ ]# ?arrow_forwardAlpha-phellandrene, C₁0H16, is a pleasant-smelling chiral compound that may be obtained from the leaves of eucalyptus trees. It has the molecular formula C₁0H16 and a UV absorption maximum at 263 nm. On hydrogenation with a palladium catalyst, an achiral hydrocarbon with the formula C10H20 is obtained. Ozonolysis of alpha-phellandrene, followed by treatment with zinc and acetic acid, produces the following two compounds: CHIC-CH HOCHSCHICH CH(CH3)2 Propose a structure for alpha-phellandrene.arrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2, -OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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