   Chapter 19, Problem 19.37E

Chapter
Section
Textbook Problem

The mean free path depends on the ratio T / p . What value of T / p is necessary for the mean free path of He ( d = 65   pm ) to equal 130   pm ? How feasible do you think it will be to attain this ratio?

Interpretation Introduction

Interpretation:

The value of T/p that is necessary for He to have a mean free path of 130pm is to be calculated. The reason as to how it would be feasible to attain the corresponding ratio is to be stated.

Concept introduction:

The mean distance traveled by the same particle between two consecutive collisions is termed as a mean free path. The value of the mean free path of a gas depends on the pressure and temperature of the system. The mean free path of gas is represented as,

λ=kT2πd2p

Where,

T represents the temperature.

d collision diameter of a gas.

p represents the pressure.

k represents the Boltzmann constant with value 1.381×1023J/K.

Explanation

The collision diameter of He is 65pm.

The mean free path of He is 130pm.

The mean free path of gas is represented as,

λ=kT2πd2p …(1)

Where,

T represents the temperature.

d collision diameter of a gas.

p represents the pressure.

k represents the Boltzmann constant with value 1.381×1023J/K.

Rearrange the equation (1) for the value of T/p the ratio.

Tp=2πd2λk …(2)

Substitute the value of k, d, π and λ in the equation (2).

Tp=2(3.14)(65pm)2(1012m1pm)3(130pm)(1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 