Package: General Chemistry with Connect 2-year Access Card
Package: General Chemistry with Connect 2-year Access Card
7th Edition
ISBN: 9781259680458
Author: Raymond Chang Dr.
Publisher: McGraw-Hill Education
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Chapter 19, Problem 19.93QP

(a)

Interpretation Introduction

Interpretation:

The unknown electrode ‘X’ has to be identified.

Concept introduction:

Standard reduction potential: The voltage associated with a reduction reaction at an electrode when all solutes are 1M and all gases are at 1 atm. The hydrogen electrode is called the standard hydrogen electrode (SHE).

Standard emf: Ecell0 is composed of a contribution from the anode and a contribution from the cathode is given by,

Ecello=EcathodeoEanodeo

Where both Ecathodeo and Eanodeo are the standard reduction potentials of the electrodes.

(a)

Expert Solution
Check Mark

Explanation of Solution

The standard reduction potential of Mg (+2) as follows,

Mg(s)Mg2+(aq)+2eE0anode=2.37V

The standard reduction potential of Pb (+2) as follows,

X2+(aq)+2eX(s)Ecathode=?

Calculated standard emf for galvanic cell as follows,

oxidation:Mg(s)Mg2+(aq)+2eE0anode=2.37VReduction:X2+(aq)+2eX(s)Ecathode=?_overall:Mg(s)+X2+(aq)Mg2+(aq)+X(s)_

Ecello=Ecathodeo-Eanodeo2.12V=(?)V-(-2.37)Vx=-0.25V

Therefore, the cathode emf is -0.25V, on checking the table 18.1 of the text, X is NICKEL, Ni

(b)

Interpretation Introduction

Interpretation:

The unknown electrode ‘X’ has to be identified.

Concept introduction:

Standard reduction potential: The voltage associated with a reduction reaction at an electrode when all solutes are 1M and all gases are at 1 atm. The hydrogen electrode is called the standard hydrogen electrode (SHE).

Standard emf: Ecell0 is composed of a contribution from the anode and a contribution from the cathode is given by,

Ecello=EcathodeoEanodeo

Where both Ecathodeo and Eanodeo are the standard reduction potentials of the electrodes.

(b)

Expert Solution
Check Mark

Explanation of Solution

The standard reduction potential of Mg (+2) as follows,

Mg(s)Mg2+(aq)+2eE0anode=2.37V

The standard reduction potential of Pb (+2) as follows,

X2+(aq)+2eX(s)Ecathode=?

Calculated standard emf for galvanic cell as follows,

oxidation:Mg(s)Mg2+(aq)+2eE0anode=2.37VReduction:X2+(aq)+2eX(s)Ecathode=?_overall:Mg(s)+X2+(aq)Mg2+(aq)+X(s)_

The given standard emf of the redox reaction is,2.24V

Ecello=Ecathodeo-Eanodeo2.24V=Ecathodeo-(-2.37)VEcathodeo=-0.13V

Therefore, the cathode emf is -0.13V, on checking the table 18.1 of the text, X is LEAD, Pb

c)

Interpretation Introduction

Interpretation:

The unknown electrode ‘X’ has to be identified.

Concept introduction:

Standard reduction potential: The voltage associated with a reduction reaction at an electrode when all solutes are 1M and all gases are at 1 atm. The hydrogen electrode is called the standard hydrogen electrode (SHE).

Standard emf: Ecell0 is composed of a contribution from the anode and a contribution from the cathode is given by,

Ecello=EcathodeoEanodeo

Where both Ecathodeo and Eanodeo are the standard reduction potentials of the electrodes.

c)

Expert Solution
Check Mark

Explanation of Solution

The standard reduction potential of Mg (+2) as follows,

Mg(s)Mg2+(aq)+2eE0anode=2.37V

The standard reduction potential of Pb (+2) as follows,

X2+(aq)+2eX(s)Ecathode=?

Calculated standard emf for galvanic cell as follows,

oxidation:Mg(s)Mg2+(aq)+2eE0anode=2.37VReduction:X2+(aq)+2eX(s)Ecathode=?_overall:Mg(s)+X2+(aq)Mg2+(aq)+X(s)_

The given standard emf of the redox reaction is,1.61V

Ecello=Ecathodeo-Eanodeo1.61V=Ecathodeo-(-2.37)VEcathodeo=-0.76V

Therefore, the cathode emf is -0.76V, on checking the table 18.1 of the text, X is ZINC, Zn

d)

Interpretation Introduction

Interpretation:

The unknown electrode ‘X’ has to be identified.

Concept introduction:

Standard reduction potential: The voltage associated with a reduction reaction at an electrode when all solutes are 1M and all gases are at 1 atm. The hydrogen electrode is called the standard hydrogen electrode (SHE).

Standard emf: Ecell0 is composed of a contribution from the anode and a contribution from the cathode is given by,

Ecello=EcathodeoEanodeo

Where both Ecathodeo and Eanodeo are the standard reduction potentials of the electrodes.

d)

Expert Solution
Check Mark

Explanation of Solution

The standard reduction potential of Mg (+2) as follows,

Mg(s)Mg2+(aq)+2eE0anode=2.37V

The standard reduction potential of Pb (+2) as follows,

X2+(aq)+2eX(s)Ecathode=?

Calculated standard emf for galvanic cell as follows,

oxidation:Mg(s)Mg2+(aq)+2eE0anode=2.37VReduction:X2+(aq)+2eX(s)Ecathode=?_overall:Mg(s)+X2+(aq)Mg2+(aq)+X(s)_

The given standard emf of the redox reaction is,1.93V

Ecello=Ecathodeo-Eanodeo1.93V=Ecathodeo-(-2.37)VEcathodeo=-0.44V

Therefore, the cathode emf is -0.44V, on checking the table 18.1 of the text, X is IRON, Fe.

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Chapter 19 Solutions

Package: General Chemistry with Connect 2-year Access Card

Ch. 19.5 - Prob. 2PECh. 19.5 - Prob. 1RCCh. 19.7 - Prob. 1RCCh. 19.8 - Prob. 1RCCh. 19.8 - An aqueous solution of Mg(NO3)2 is electrolyzed....Ch. 19.8 - Prob. 2RCCh. 19.8 - Prob. 2PECh. 19.8 - Prob. 3RCCh. 19 - Prob. 19.1QPCh. 19 - Prob. 19.2QPCh. 19 - Prob. 19.3QPCh. 19 - Prob. 19.4QPCh. 19 - Prob. 19.5QPCh. 19 - Prob. 19.6QPCh. 19 - 19.7 What is the difference between the...Ch. 19 - Prob. 19.8QPCh. 19 - Prob. 19.9QPCh. 19 - Prob. 19.10QPCh. 19 - Prob. 19.11QPCh. 19 - Prob. 19.12QPCh. 19 - Prob. 19.13QPCh. 19 - 19.14 Which of the following reagents can oxidize...Ch. 19 - 19.15 Consider the following half-reactions: (aq)...Ch. 19 - 19.16 Predict whether the following reactions...Ch. 19 - Prob. 19.17QPCh. 19 - Prob. 19.18QPCh. 19 - Prob. 19.19QPCh. 19 - Prob. 19.20QPCh. 19 - Prob. 19.21QPCh. 19 - Prob. 19.22QPCh. 19 - Prob. 19.23QPCh. 19 - Prob. 19.24QPCh. 19 - Prob. 19.25QPCh. 19 - Prob. 19.26QPCh. 19 - Prob. 19.27QPCh. 19 - Prob. 19.28QPCh. 19 - Prob. 19.29QPCh. 19 - Prob. 19.30QPCh. 19 - Prob. 19.31QPCh. 19 - Prob. 19.33QPCh. 19 - Prob. 19.34QPCh. 19 - 19.35 Explain the differences between a primary...Ch. 19 - Prob. 19.36QPCh. 19 - Prob. 19.37QPCh. 19 - Prob. 19.38QPCh. 19 - Prob. 19.39QPCh. 19 - Prob. 19.40QPCh. 19 - Prob. 19.41QPCh. 19 - Prob. 19.42QPCh. 19 - 19.43 What is the difference between a galvanic...Ch. 19 - Prob. 19.44QPCh. 19 - Prob. 19.45QPCh. 19 - Prob. 19.46QPCh. 19 - Prob. 19.47QPCh. 19 - Prob. 19.48QPCh. 19 - Prob. 19.49QPCh. 19 - Prob. 19.50QPCh. 19 - 19.51 Calculate the amounts of Cu and Br2 produced...Ch. 19 - Prob. 19.52QPCh. 19 - Prob. 19.53QPCh. 19 - Prob. 19.54QPCh. 19 - 19.55 What is the hourly production rate of...Ch. 19 - Prob. 19.56QPCh. 19 - Prob. 19.57QPCh. 19 - Prob. 19.58QPCh. 19 - Prob. 19.59QPCh. 19 - Prob. 19.60QPCh. 19 - Prob. 19.61QPCh. 19 - Prob. 19.62QPCh. 19 - Prob. 19.63QPCh. 19 - Prob. 19.64QPCh. 19 - Prob. 19.65QPCh. 19 - 19.66 A sample of iron ore weighing 0.2792 g was...Ch. 19 - Prob. 19.67QPCh. 19 - Prob. 19.68QPCh. 19 - Prob. 19.69QPCh. 19 - Prob. 19.70QPCh. 19 - Prob. 19.71QPCh. 19 - Prob. 19.72QPCh. 19 - Prob. 19.73QPCh. 19 - Prob. 19.74QPCh. 19 - Prob. 19.75QPCh. 19 - Prob. 19.76QPCh. 19 - Prob. 19.77QPCh. 19 - Prob. 19.78QPCh. 19 - Prob. 19.79QPCh. 19 - Prob. 19.80QPCh. 19 - Prob. 19.81QPCh. 19 - Prob. 19.82QPCh. 19 - Prob. 19.83QPCh. 19 - Prob. 19.84QPCh. 19 - Prob. 19.86QPCh. 19 - Prob. 19.87QPCh. 19 - Prob. 19.88QPCh. 19 - Prob. 19.89QPCh. 19 - Prob. 19.90QPCh. 19 - Prob. 19.91QPCh. 19 - Prob. 19.92QPCh. 19 - Prob. 19.93QPCh. 19 - Prob. 19.94QPCh. 19 - Prob. 19.95QPCh. 19 - Prob. 19.96QPCh. 19 - Prob. 19.97QPCh. 19 - Prob. 19.98QPCh. 19 - Prob. 19.99QPCh. 19 - Prob. 19.100QPCh. 19 - Prob. 19.101QPCh. 19 - 19.102 The magnitudes (but not the signs) of the...Ch. 19 - Prob. 19.103QPCh. 19 - Prob. 19.104QPCh. 19 - Prob. 19.105QPCh. 19 - Prob. 19.106QPCh. 19 - Prob. 19.107QPCh. 19 - Prob. 19.108QPCh. 19 - Prob. 19.109QPCh. 19 - Prob. 19.110QPCh. 19 - 19.111 A spoon was silver-plated electro lyrically...Ch. 19 - Prob. 19.112QPCh. 19 - Prob. 19.113QPCh. 19 - Prob. 19.114QPCh. 19 - Prob. 19.115QPCh. 19 - Prob. 19.116QPCh. 19 - Prob. 19.117QPCh. 19 - Prob. 19.118QPCh. 19 - Prob. 19.119QPCh. 19 - Prob. 19.120QPCh. 19 - Prob. 19.121SPCh. 19 - Prob. 19.122SPCh. 19 - Prob. 19.123SPCh. 19 - Prob. 19.124SPCh. 19 - Prob. 19.125SPCh. 19 - Prob. 19.126SPCh. 19 - Prob. 19.128SPCh. 19 - Prob. 19.129SPCh. 19 - Prob. 19.130SP
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