INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN
INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN
8th Edition
ISBN: 9780134580289
Author: CORWIN
Publisher: PEARSON
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Chapter 19, Problem 20E
Interpretation Introduction

(a)

Interpretation:

The balanced equation for the complete combustion of ethane is to be stated.

Concept introduction:

Combustion means the reaction of any substance with atmospheric oxygen. The process of combustion is an exothermic reaction that is energy is transferred to the surroundings. Combustion of alkane forms water and carbon dioxide as a byproduct.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced equation for the complete combustion of ethane is stated below.

2C2H6+7O24CO2+6H2O

Explanation of Solution

The general reaction for the combustion of an alkane is shown below.

CnH2n+2+(3n+12)O2nCO2+(n+1)H2O

Where

• n is the number of carbon atoms.

The number of carbon atom present in ethane is 2. Therefore, the value of n is 2. Substitute n=2 in the above reaction. Multiply the whole reaction by a coefficient 2 to convert the atoms of O2 into a whole number.

The balanced chemical reaction of combustion of ethane is stated below.

2C2H6+7O24CO2+6H2O

Conclusion

The balanced equation of ethane is stated above.

Interpretation Introduction

(b)

Interpretation:

The balanced equation for the complete combustion of butane is to be stated.

Concept introduction:

Combustion means the reaction of any substance with atmospheric oxygen. The process of combustion is an exothermic reaction that is energy is transferred to the surroundings. Combustion of alkane forms water and carbon dioxide as a byproduct.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced equation for the complete combustion of butane is stated below.

2C4H10+13O28CO2+10H2O

Explanation of Solution

The general reaction for the combustion of an alkane is shown below.

CnH2n+2+(3n+12)O2nCO2+(n+1)H2O

Where

• n is the number of carbon atoms.

The number of carbon atom present in butane is 4. Therefore, the value of n is 4. Substitute n=4 in the above reaction. Multiply the whole reaction by a coefficient 2 to convert the atoms of O2 into a whole number.

The balanced chemical reaction of combustion of butane is stated below.

2C4H10+13O28CO2+10H2O

Conclusion

The balanced equation of butane is stated above.

Interpretation Introduction

(c)

Interpretation:

The balanced equation for the complete combustion of pentane is to be stated.

Concept introduction:

Combustion means the reaction of any substance with atmospheric oxygen. The process of combustion is an exothermic reaction that is energy is transferred to the surroundings. Combustion of alkane forms water and carbon dioxide as a byproduct.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced equation for the complete combustion of pentane is stated below.

2C5H12+16O210CO2+12H2O

Explanation of Solution

The general reaction for the combustion of an alkane is shown below.

CnH2n+2+(3n+12)O2nCO2+(n+1)H2O

Where

• n is the number of carbon atoms.

The number of carbon atom present in pentane is 5. Therefore, the value of n is 5. Substitute n=5 in the above reaction. Multiply the whole reaction by a coefficient 2 to convert the atoms of O2 into a whole number.

The balanced chemical reaction of combustion of pentane is stated below.

2C5H12+16O210CO2+12H2O

Conclusion

The balanced equation of pentane is stated above.

Interpretation Introduction

(d)

Interpretation:

The balanced equation for the complete combustion of heptane is to be stated.

Concept introduction:

Combustion means the reaction of any substance with atmospheric oxygen. The process of combustion is an exothermic reaction that is energy is transferred to the surroundings. Combustion of alkane forms water and carbon dioxide as a byproduct.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced equation for the complete combustion of heptane is stated below.

2C7H16+22O214CO2+16H2O

Explanation of Solution

The general reaction for the combustion of an alkane is shown below.

CnH2n+2+(3n+12)O2nCO2+(n+1)H2O

Where

• n is the number of carbon atoms.

The number of carbon atom present in heptane is 7. Therefore, the value of n is 7. Substitute n=7 in the above reaction. Multiply the whole reaction by a coefficient 2 to convert the atoms of O2 into a whole number.

The balanced chemical reaction of combustion of heptane is stated below.

2C7H16+22O214CO2+16H2O

Conclusion

The balanced equation of heptane is stated above.

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Chapter 19 Solutions

INTRODUCTORY CHEMISTRY-STD.GDE.+SOL.MAN

Ch. 19 - Prob. 4KTCh. 19 - Prob. 5KTCh. 19 - Prob. 6KTCh. 19 - Prob. 7KTCh. 19 - Prob. 8KTCh. 19 - Prob. 9KTCh. 19 - Prob. 10KTCh. 19 - Prob. 11KTCh. 19 - Prob. 12KTCh. 19 - Prob. 13KTCh. 19 - Prob. 14KTCh. 19 - Prob. 15KTCh. 19 - Prob. 16KTCh. 19 - Prob. 17KTCh. 19 - Prob. 18KTCh. 19 - Prob. 19KTCh. 19 - Prob. 20KTCh. 19 - Prob. 21KTCh. 19 - Prob. 22KTCh. 19 - Prob. 23KTCh. 19 - Prob. 24KTCh. 19 - Prob. 1ECh. 19 - Prob. 2ECh. 19 - Prob. 3ECh. 19 - Prob. 4ECh. 19 - Prob. 5ECh. 19 - Prob. 6ECh. 19 - Prob. 7ECh. 19 - Prob. 8ECh. 19 - Prob. 9ECh. 19 - Prob. 10ECh. 19 - Prob. 11ECh. 19 - Prob. 12ECh. 19 - Prob. 13ECh. 19 - Prob. 14ECh. 19 - Prob. 15ECh. 19 - Prob. 16ECh. 19 - Prob. 17ECh. 19 - Prob. 18ECh. 19 - Prob. 19ECh. 19 - Prob. 20ECh. 19 - Prob. 21ECh. 19 - Prob. 22ECh. 19 - Prob. 23ECh. 19 - Prob. 24ECh. 19 - Prob. 25ECh. 19 - Prob. 26ECh. 19 - Prob. 27ECh. 19 - Prob. 28ECh. 19 - Prob. 29ECh. 19 - Prob. 30ECh. 19 - Prob. 31ECh. 19 - Prob. 32ECh. 19 - Prob. 33ECh. 19 - Prob. 34ECh. 19 - Prob. 35ECh. 19 - Prob. 36ECh. 19 - Prob. 37ECh. 19 - Prob. 38ECh. 19 - Prob. 39ECh. 19 - Prob. 40ECh. 19 - Prob. 41ECh. 19 - Prob. 42ECh. 19 - Prob. 43ECh. 19 - Prob. 44ECh. 19 - Prob. 45ECh. 19 - Prob. 46ECh. 19 - Prob. 47ECh. 19 - Prob. 48ECh. 19 - Prob. 49ECh. 19 - Prob. 50ECh. 19 - Prob. 51ECh. 19 - Prob. 52ECh. 19 - Prob. 53ECh. 19 - Prob. 54ECh. 19 - Prob. 55ECh. 19 - Prob. 56ECh. 19 - Prob. 57ECh. 19 - Prob. 58ECh. 19 - Prob. 59ECh. 19 - Prob. 60ECh. 19 - Prob. 61ECh. 19 - Prob. 62ECh. 19 - Prob. 63ECh. 19 - Prob. 64ECh. 19 - Prob. 65ECh. 19 - Prob. 66ECh. 19 - Prob. 67ECh. 19 - Prob. 68ECh. 19 - Prob. 69ECh. 19 - Prob. 70ECh. 19 - Prob. 71ECh. 19 - Prob. 72ECh. 19 - Prob. 73ECh. 19 - Prob. 74ECh. 19 - Prob. 75ECh. 19 - Prob. 76ECh. 19 - Prob. 77ECh. 19 - Prob. 78ECh. 19 - Prob. 79ECh. 19 - Prob. 80ECh. 19 - Prob. 81ECh. 19 - Prob. 82ECh. 19 - Prob. 83ECh. 19 - Prob. 84ECh. 19 - Prob. 85ECh. 19 - Prob. 86ECh. 19 - Prob. 1STCh. 19 - Prob. 2STCh. 19 - Prob. 3STCh. 19 - Prob. 4STCh. 19 - Prob. 5STCh. 19 - Prob. 6STCh. 19 - Prob. 7STCh. 19 - Prob. 8STCh. 19 - Prob. 9STCh. 19 - Prob. 10STCh. 19 - Prob. 11STCh. 19 - Prob. 12STCh. 19 - Prob. 13STCh. 19 - Prob. 14STCh. 19 - Prob. 15STCh. 19 - Prob. 16STCh. 19 - Prob. 17STCh. 19 - Prob. 18ST
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