General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 2, Problem 2.13QP
Interpretation Introduction

Interpretation:

The number of protons, neutrons and electrons in given species has to be identified.

Concept Introduction:

Mass number(A): Mass number of an element is sum of protons and neutrons of the atom.

A= Number of protons(P) + Number of neutrons(n)

Consider an element X with atomic number and mass number,

ZAX

Where,

A is mass number and Z is atomic number ( number of proton or electron)

Expert Solution & Answer
Check Mark

Answer to Problem 2.13QP

Number of proton, neutron and electrons for given species are given as follows.

IsotopesHe23He24Mg1224Mg1225Ti2248Br3579Pt78195
No. of Protons221212223578
No. of Neutrons1212132644117

Explanation of Solution

For He23, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = 23HeZ (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 2A (mass number) = Number of protons (P) + Number of  neutrons (N)                      3 = 2 + n n=1

Thus, the number of neutrons, protons and electrons are found as 1,2 and 2 respectively.

For He24, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = 24HeZ (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 2A (mass number) = Number of protons (P) + Number of  neutrons (N)                      4 = 2 + n n=2

Thus, the number of neutrons, protons and electrons are found as 2,2 and 2 respectively.

For Mg1224, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Mg1224Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 12A (mass number) = Number of protons (P) + Number of  neutrons (N)                      24 = 12 + n n=12

Thus, the number of neutrons, protons and electrons are found as 12,12 and 12 respectively.

For Mg1225, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Mg1225Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 12A (mass number) = Number of protons (P) + Number of  neutrons (N)                      25 = 12 + n n=13

Thus, the number of neutrons, protons and electrons are found as 13,12 and 12 respectively.

For Ti2248, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =Ti2248Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 22A (mass number) = Number of protons (P) + Number of  neutrons (N)                      48 = 22 + n n=26

Thus, the number of neutrons, protons and electrons are found as 26,22 and 22 respectively.

For Br3579, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =Br3579Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 35A (mass number) = Number of protons (P) + Number of  neutrons (N)                      79 = 35 + n n= 44

Thus, the number of neutrons, protons and electrons are found as 44,35 and 35 respectively.

For Pt78195, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Pt78195Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 78A (mass number) = Number of protons (P) + Number of  neutrons (N)                      195 = 78 + n n= 117

Thus, the number of neutrons, protons and electrons are found as 117,78 and 78 respectively.

Conclusion

The number of protons, neutrons and electrons in given species were identified.

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Chapter 2 Solutions

General Chemistry

Ch. 2.7 - Prob. 1PECh. 2.7 - Prob. 2PECh. 2.7 - Prob. 3PECh. 2.7 - Prob. 4PECh. 2.7 - Prob. 5PECh. 2.8 - Prob. 1RCCh. 2 - Prob. 2.1QPCh. 2 - Prob. 2.2QPCh. 2 - Prob. 2.3QPCh. 2 - 2.4 Describe the contributions of these scientists...Ch. 2 - 2.5 A sample of a radioactive element is found to...Ch. 2 - 2.6 Describe the experimental basis for believing...Ch. 2 - Prob. 2.7QPCh. 2 - 2.8 Roughly speaking, the radius of an atom is...Ch. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - 2.11 What is the mass number of an iron atom that...Ch. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Prob. 2.20QPCh. 2 - Prob. 2.21QPCh. 2 - Prob. 2.22QPCh. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - 2.31 Identify the following as elements or...Ch. 2 - Prob. 2.32QPCh. 2 - Prob. 2.33QPCh. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - Prob. 2.38QPCh. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Prob. 2.42QPCh. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Prob. 2.45QPCh. 2 - Prob. 2.46QPCh. 2 - Prob. 2.47QPCh. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - Prob. 2.65QPCh. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Prob. 2.71QPCh. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76SPCh. 2 - Prob. 2.77SPCh. 2 - Prob. 2.78SPCh. 2 - Prob. 2.79SPCh. 2 - Prob. 2.80SPCh. 2 - Prob. 2.81SPCh. 2 - Prob. 2.82SP
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