General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 2, Problem 2.64QP

(a)

Interpretation Introduction

Interpretation: The neutron numbers should be predicted for the given neutron–rich isotope 40Mg.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

(a)

Expert Solution
Check Mark

Answer to Problem 2.64QP

 40Mg has totally 28 neutrons.

Explanation of Solution

Predict the neutron numbers in the 40Mg.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

  The element symbol : 40Mg,Z (atomic number) of magnesium is 12No.of  neutrons = mass number - atomic number.    no.of  neutrons = 40 - 12   = 28The total neutrons are : 28.

(b)

Interpretation Introduction

Interpretation: The neutron numbers should be predicted for the given neutron–rich isotope 44Si.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

(b)

Expert Solution
Check Mark

Answer to Problem 2.64QP

44Si has totally 30 neutrons.

Explanation of Solution

Predict the neutron numbers in the 44Si.

  The element symbol : 44Si,Z (atomic number) of Silicon is 14No.of  neutrons = mass number - atomic number.    no.of  neutrons = 44 - 14   = 30The total neutrons are : 30.

(c)

Interpretation Introduction

Interpretation: The neutron numbers should be predicted for the given neutron–rich isotope 48Ca.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

(c)

Expert Solution
Check Mark

Answer to Problem 2.64QP

48Ca has totally 28 neutrons.

Explanation of Solution

Predict the neutron numbers in the 48Ca.

  The element symbol : 48Ca,Z (atomic number) of Calcium is 20.No.of  neutrons = mass number - atomic number.    no.of  neutrons = 48 - 20   = 28The total neutrons are : 28.

(d)

Interpretation Introduction

Interpretation: The neutron numbers should be predicted for the given neutron–rich isotope 43Al.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between coulombic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

(d)

Expert Solution
Check Mark

Answer to Problem 2.64QP

43Al has totally 30 neutrons.

Explanation of Solution

Predict the neutron numbers in the 43Al.

  The element symbol : 43Al,Z (atomic number) of Aluminum is 13No.of  neutrons = mass number - atomic number.    no.of  neutrons = 43 - 13   = 30The total neutrons are : 30.

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Chapter 2 Solutions

General Chemistry

Ch. 2.7 - Prob. 1PECh. 2.7 - Prob. 2PECh. 2.7 - Prob. 3PECh. 2.7 - Prob. 4PECh. 2.7 - Prob. 5PECh. 2.8 - Prob. 1RCCh. 2 - Prob. 2.1QPCh. 2 - Prob. 2.2QPCh. 2 - Prob. 2.3QPCh. 2 - 2.4 Describe the contributions of these scientists...Ch. 2 - 2.5 A sample of a radioactive element is found to...Ch. 2 - 2.6 Describe the experimental basis for believing...Ch. 2 - Prob. 2.7QPCh. 2 - 2.8 Roughly speaking, the radius of an atom is...Ch. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - 2.11 What is the mass number of an iron atom that...Ch. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Prob. 2.20QPCh. 2 - Prob. 2.21QPCh. 2 - Prob. 2.22QPCh. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - 2.31 Identify the following as elements or...Ch. 2 - Prob. 2.32QPCh. 2 - Prob. 2.33QPCh. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - Prob. 2.38QPCh. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Prob. 2.42QPCh. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Prob. 2.45QPCh. 2 - Prob. 2.46QPCh. 2 - Prob. 2.47QPCh. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - Prob. 2.65QPCh. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Prob. 2.71QPCh. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76SPCh. 2 - Prob. 2.77SPCh. 2 - Prob. 2.78SPCh. 2 - Prob. 2.79SPCh. 2 - Prob. 2.80SPCh. 2 - Prob. 2.81SPCh. 2 - Prob. 2.82SP
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