Chapter 2, Problem 2.49E

Interpretation Introduction

(a)

Interpretation:

The statements corresponding to the given formula that are equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Answer to Problem 2.49E

The statements corresponding to ${\text{CO}}_2$ that are equivalent to Statements 1-6 are as follows:

1. There are $2\text{C}$ atoms and $4\text{O}$ atoms present in $2$ molecules of ${\text{CO}}_2$.

2. There are $10\text{C}$ atoms and $20\text{O}$ atoms present in $10$ molecules of ${\text{CO}}_2$.

3. There are $100\text{C}$ atoms and $200\text{O}$ atoms present in $100$ molecules of ${\text{CO}}_2$.

4. There are $6.02\times {10}^{23}\text{C}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{CO}}_2$.

5. There are $1\text{mol}\text{C}$ atoms and $2\text{moles}\text{O}$ atoms present in $1\text{mol}{\text{CO}}_2$.

6. There is $12.01\text{g}\text{C}$ and $32.00\text{g}\text{O}$ is present in $44.01\text{g}$ of ${\text{CO}}_2$.

Explanation of Solution

For the given compound carbon dioxide $\left({\text{CO}}_2\right)$, the statements equivalent to Statements 1-6 are,

According to statement $1$, the $2$ molecules of carbon dioxide $\left({\text{CO}}_2\right)$, contain $2\text{C}$ atoms and $4\text{O}$ atoms.

According to statement $2$, the $10$ molecules of carbon dioxide $\left({\text{CO}}_2\right)$, contain $10\text{C}$ atoms and $20\text{O}$ atoms.

According to statement $3$, the $100$ molecules of carbon dioxide $\left({\text{CO}}_2\right)$, contain $100\text{C}$ atoms and $200\text{O}$ atoms.

According to statement $4$, the $6.02\times {10}^{23}$ molecules of carbon dioxide $\left({\text{CO}}_2\right)$, contain $6.02\times {10}^{23}\text{C}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms.

According to statement $5$, one mole of carbon dioxide $\left({\text{CO}}_2\right)$, contain $1\text{mol}\text{C}$ atoms and $2\text{moles}\text{O}$ atoms.

According to statement $6$, the $44.01\text{g}$ amount of carbon dioxide $\left({\text{CO}}_2\right)$, contain $12.01\text{g}\text{C}$ and $32.00\text{g}\text{O}$.

Conclusion

The statements corresponding to ${\text{CO}}_2$ that are equivalent to Statements 1-6 are as follows:

1. There are $2\text{C}$ atoms and $4\text{O}$ atoms present in $2$ molecules of ${\text{CO}}_2$.

2. There are $10\text{C}$ atoms and $20\text{O}$ atoms present in $10$ molecules of ${\text{CO}}_2$.

3. There are $100\text{C}$ atoms and $200\text{O}$ atoms present in $100$ molecules of ${\text{CO}}_2$.

4. There are $6.02\times {10}^{23}\text{C}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{CO}}_2$.

5. There are $1\text{mol}\text{C}$ atoms and $2\text{moles}\text{O}$ atoms present in $1\text{mol}{\text{CO}}_2$.

6. The $44.01\text{g}$ amount of carbon dioxide $\left({\text{CO}}_2\right)$, contain $12.01\text{g}\text{C}$ and $32.00\text{g}\text{O}$.

Interpretation Introduction

(b)

Interpretation:

The statements corresponding to the given formula that is equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Answer to Problem 2.49E

The statements corresponding to ${\text{C}}_2{\text{H}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. There are $4\text{C}$ atoms and $12\text{H}$ atoms present in $2$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

2. There are $20\text{C}$ atoms and $60\text{H}$ atoms present in $10$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

3. There are $200\text{C}$ atoms and $600\text{H}$ atoms present in $100$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

4. There are $12.04\times {10}^{23}\text{C}$ atoms and $36.12\times {10}^{23}\text{H}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

5. There are $2\text{mol}\text{C}$ atoms and $6\text{moles}\text{H}$ atoms present in $1\text{mol}{\text{C}}_2{\text{H}}_{\text{6}}$.

6. There is $24.02\text{g}\text{C}$ and $6.00\text{g}\text{H}$ is present in $30.02\text{g}$ of ${\text{C}}_2{\text{H}}_{\text{6}}$.

Explanation of Solution

The statements corresponding to ${\text{C}}_2{\text{H}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. The $2$ molecules of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $4\text{C}$ atoms and $12\text{H}$ atoms.

2. The $10$ molecules of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $20\text{C}$ atoms and $60\text{H}$ atoms.

3. The $100$ molecules of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $200\text{C}$ atoms and $600\text{H}$ atoms.

4. The $6.02\times {10}^{23}$ molecules of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $12.04\times {10}^{23}\text{C}$ atoms and $36.12\times {10}^{23}\text{H}$ atoms.

5. One mole of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $2\text{mol}\text{C}$ atoms and $6\text{moles}\text{H}$ atoms.

6. The $30.02\text{g}$ amount of ethane $\left({\text{C}}_2{\text{H}}_{\text{6}}\right)$, contain $24.02\text{g}\text{C}$ and $6.00\text{g}\text{H}$.

Conclusion

The statements corresponding to ${\text{C}}_2{\text{H}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. There are $4\text{C}$ atoms and $12\text{H}$ atoms present in $2$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

2. There are $20\text{C}$ atoms and $60\text{H}$ atoms present in $10$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

3. There are $200\text{C}$ atoms and $600\text{H}$ atoms present in $100$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

4. There are $12.04\times {10}^{23}\text{C}$ atoms and $36.12\times {10}^{23}\text{H}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_2{\text{H}}_{\text{6}}$.

5. There are $2\text{mol}\text{C}$ atoms and $6\text{moles}\text{H}$ atoms present in $1\text{mol}{\text{C}}_2{\text{H}}_{\text{6}}$.

6. There is $24.02\text{g}\text{C}$ and $6.00\text{g}\text{H}$ is present in $30.02\text{g}$ of ${\text{C}}_2{\text{H}}_{\text{6}}$.

Interpretation Introduction

(c)

Interpretation:

The statements corresponding to the given formula that is equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Answer to Problem 2.49E

The statements corresponding to ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. There are $12\text{C}$ atoms, $24\text{H}$ atoms and $12\text{O}$ atoms present in $2$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

2. There are $60\text{C}$ atoms, $120\text{H}$ atoms and $60\text{O}$ atoms present in $10$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

3. There are $600\text{C}$ atoms, $1200\text{H}$ atoms and $600\text{O}$ atoms present in $100$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

4. There are $36.12\times {10}^{23}\text{C}$ atoms, $72.24\times {10}^{23}\text{H}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

5. There are $6\text{mol}\text{C}$ atoms, $12\text{moles}\text{H}$ atoms and $6\text{moles}\text{O}$ atoms present in $1\text{mol}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

6. There is $72.06\text{g}\text{C}$, $12\text{g}\text{H}$ and $96.00\text{g}\text{O}$ present in $180.06\text{g}$ of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

Explanation of Solution

The statements corresponding to ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. The $2$ molecules of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $12\text{C}$ atom, $24\text{H}$ atoms and $12\text{O}$ atoms.

2. The $10$ molecules of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $60\text{C}$ atom, $120\text{H}$ atoms and $60\text{O}$ atoms.

3. The $100$ molecules of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $600\text{C}$ atom, $1200\text{H}$ atoms and $600\text{O}$ atoms.

4. The $6.02\times {10}^{23}$ molecules of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $36.12\times {10}^{23}\text{C}$ atom, $72.24\times {10}^{23}\text{H}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms.

5. One mole of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $6\text{mol}\text{C}$ atoms, $12\text{moles}\text{H}$ atoms and $6\text{moles}\text{O}$ atoms.

6. The $180.06\text{g}$ amount of glucose $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\right)$, contain $72.06\text{g}\text{C}$, $12\text{g}\text{H}$ and $96.00\text{g}\text{O}$.

Conclusion

The statements corresponding to ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ that are equivalent to Statements 1-6 are as follows:

1. There are $12\text{C}$ atoms, $12\text{H}$ atoms and $12\text{O}$ atoms present in $2$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

2. There are $60\text{C}$ atoms, $120\text{H}$ atoms and $60\text{O}$ atoms present in $10$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

3. There are $600\text{C}$ atoms, $1200\text{H}$ atoms and $600\text{O}$ atoms present in $100$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

4. There are $36.12\times {10}^{23}\text{C}$ atoms, $72.24\times {10}^{23}\text{H}$ atoms and $12.04\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

5. There are $6\text{mol}\text{C}$ atoms, $12\text{moles}\text{H}$ atoms and $6\text{moles}\text{O}$ atoms present in $1\text{mol}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.

6. There is $72.06\text{g}\text{C}$, $12\text{g}\text{H}$ and $96.00\text{g}\text{O}$ present in $180.06\text{g}$ of ${\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$.