Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 2, Problem 26P
To determine
Whether the driver should appeal the ticket or not.
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A driver is traveling at 90 mi/h down a 3% grade on good, wet pavement. An accident investigation team noted that braking skid marks started 410 ft before a parked car was hit at an estimated 45 mi/h. Ignoring air resistance, and using theoretical stopping distance,
a. If the car’s antilock braking system was effective (no sliding wheels on the pavement), what would the crash speed be?
An accident investigator estimates that a vehicle hit an advertisement column at a
speed of 30 mi/h, based on his assessment of damage. Leading up to the accident
location, he observes skid marks of 100 ft on the pavement (F = 0.35), 10 ft on the
shoulder (F=0.3), and 75 ft on the grass shoulder (F = 0.25); the grades of the
pavement, the shoulder and the grass are 2%, 8% and 6% downgrade, respectively. If
the post speed of this highway is 60 mi/h, does the initial speed of the driver is one of
the accident cause?
i need solutions in 10 minutes please
a vehicle was stopped in 2.1 seconds by fully jamming the brakes and the skid mark measured 10 meters. Determine the average skid resistance on the level pavement surface.
Chapter 2 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- A driver is traveling at 90 mi/h down a 3% grade on good, wet pavement. An accident investigation team noted that braking skid marks started 410 ft before a parked car was hit at an estimated 45 mi/h. Ignoring air resistance, and using theoretical stopping distance, what was the braking efficiency of the car? If the car’s antilock-braking system was effective (no sliding wheels on the pavement), what would the crash speed be?arrow_forwardA car hits a tree at an estimated speed of 35 miles/hour at a 3% descent. If a 100 ft slip mark is observed on dry pavement (F = 0.45), followed by 250 ft (F = 0.20) on the grass stabilized shoulder. Estimate the instantaneous initial speed of the vehicle before pavement slippage begins.arrow_forwardOn a single directioned and 5% graded descending highway section, a vehicle is moving with a velocity of 60 km/h. Meanwhile another vehicle moving on the opposite direction is approaching with a velocity of 40 km/h. What is the minimum sight distance to avoid vehicles crashing each other ?Given: Pavement sliding coefficient, f=0,60; detection-reaction time for each driver, tr=1,0 sec.arrow_forward
- A student trying to test the braking ability of her car determined that she needed 19.5 ft more to stop her car when driving downhill on a road segment of 5% grade than when driving downhill at the same speed along another segment of 3.5% grade. Determine the speed at which the student conducted her test and the braking distance on the 5% grade if the student is traveling at the test speed in the uphill direction.arrow_forwardA car hits a tree at an estimated speed of 32 mph on a 3% downgrade. If skid marks are observed for a distance of 130 feet on a dry pavement (a= 15.5 feet/sec2), followed by 210 feet on a grass-stabilized shoulder (a= 7.6 feet/sec2), estimate the initial speed of the vehicle.arrow_forwardYou are shown an accident scene with a vehicle and a tree on uphill grade of 3%. The vehicle was estimated to hit the tree at 120 km/hr. The average length of skid marks was 20 meters. You have found that a car traveling that section under similar weather conditions at 60 km/hr can stop in 60 m. What was its initial speed?arrow_forward
- A car hits a tree at an estimated speed of 35 mi/h on a 3% downgrade. If skid marks of 100 ft are observed on dry pavement (F = 0.45), followed by 250 ft (F = 0.20) on a grass-stabilized shoulder, estimate the initial speed of the vehicle just before the pavement skid was begun.arrow_forwardIn an intersection collision, one of the vehicles leave 165 ft of skid marks. A skid mark analysis indicates that the vehicle was traveling 54 mph at the onset of braking. Assuming the driver’s perception-reaction time is 1.25 seconds, estimate the distance from the point of impact to the vehicle position when the driver initially reacted.arrow_forwardcompute the required SSD for a two-way traffic in a single lane to avoid collision with a car approaching from opposite direction if both cars are moving at 80kph, perception reaction time of each driver is 2 seconds. The coefficient of friction between the tires and the pavement is 0.50. G=2%arrow_forward
- A two-lane highway (two 12-ft lanes) has a posted speed limit of 45 mi/h and one section has both horizontal and vertical curves, as shown in the figure below. A recent daytime crash (driver traveling eastbound and striking a stationary roadway object) resulted in a fatality and a lawsuit alleging that the 45 mi/h posted speed limit is an unsafe speed for the curves in question and was a major cause of the crash. Evaluate and comment on the roadway design if superelevation and radius, as well as SSD and K (rate of curvature) values of the road was adequate in safety provisions. Use g = 32.2 ft/sec2. Use 1.47 as conversion factor from mi/h to ft/s. Formula of rate of curvature is K = L/A hint: compare values of fs, SSD, and K with allowable values listed below allowable fs for 45 mi/h at e = 7.0%: 0.15 allowable SSD for 45 mi/h = 360 ft allowable K at 45 mi/h = 79arrow_forwardA driver driving at 69 kph at a straight flat portion of the highway suddenly encounters an obstruction. He applies his brakes. If the coefficient of friction of the roadway to the tires is equal to 0.5, calculate the maximum safe distance (rounded to the nearest meters) the driver can apply his brakes to avoid collision.arrow_forwardA car is approaching toward an intersection with speed 45 mph. The road has a downhill grade of 1%. When the car is at a distance of 250 ft from the intersection, the signal turned yellow. If the driver applies brake and the reaction time of the driver is 1.5 s, will the driver be able to come to a complete stop? Justify your answer with calculations. Assume braking friction coefficient of 0.35.arrow_forward
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