Chapter 2, Problem 2.85CP

(a)

Interpretation Introduction

Interpretation:

The mass of single atom of 12-Carbon should be calculated.

Concept introduction:

One atomic mass unit is given below

$\text{1}\text{amu}\text{=}\text{1}\text{.661×}{\text{10}}^{\text{-24}}\text{gram}$

Number of moles can be calculated by using following formula,

$\text{Number}\text{of moles }\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$

$\begin{array}{l}\text{The number of atoms is calculated by using following formula, }\\ \text{Number}\text{of}\text{atoms}\text{=}\text{Number}\text{of}\text{moles}\text{×}\text{Avogadro's number}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The mass of $\text{6}{\text{.023×10}}^{\text{23}}$ atoms of 12-Carbon should be calculated.

Concept introduction:

One atomic mass unit is given below

$\text{1}\text{amu}\text{=}\text{1}\text{.661×}{\text{10}}^{\text{-24}}\text{gram}$

Number of moles can be calculated by using following formula,

$\text{Number}\text{of moles }\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$

$\begin{array}{l}\text{The number of atoms is calculated by using following formula, }\\ \text{Number}\text{of}\text{atoms}\text{=}\text{Number}\text{of}\text{moles}\text{×}\text{Avogadro's number}\end{array}$

(c)

Interpretation Introduction

Interpretation:

The mass of  $\text{6}{\text{.023×10}}^{\text{23}}$ atoms of 23- Sodium should be calculated.

Concept introduction:

One atomic mass unit is given below

$\text{1}\text{amu}\text{=}\text{1}\text{.661×}{\text{10}}^{\text{-24}}\text{gram}$

Number of moles can be calculated by using following formula,

$\text{Number}\text{of moles }\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$

$\begin{array}{l}\text{The number of atoms is calculated by using following formula, }\\ \text{Number}\text{of}\text{atoms}\text{=}\text{Number}\text{of}\text{moles}\text{×}\text{Avogadro's number}\end{array}$