Concept explainers
(a)
Interpretation:
Whether
Concept Introduction:
VSEPR model is useful tool to determine shapes as well as properties such as polarity of molecules.
The extent of polarity is quantitatively expressed as dipole moment. It is defined as product of charges of two bonded atoms and the separation between them. The electronegativity difference decides the direction of dipole moment. It is indicated by an arrow head from positive end towards negative end.
For complex molecules, the shape must be determined prior to determination of individual dipoles. Thus shape is governed by the VSEPR model.
(b)
Interpretation:
Whether
Concept Introduction:
Refer to part (a).
Want to see the full answer?
Check out a sample textbook solutionChapter 2 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
- Following are the structures of three isomers of difluorobenzene, C6H4F2. Are any of them nonpolar?arrow_forward(a) Is the molecule BF3 polar or nonpolar? (b) If you react BF3to make the ion BF32-, is this ion planar? (c) Does the moleculeBF2Cl have a dipole moment?arrow_forwardDetermine whether the following molecules are polar ornonpolar: (a) SF4, (b) SiCl4.arrow_forward
- Which one of the following molecules does not have a dipole moment? Justify your answer. (a) BrCI(b) CIF(c) BrF(d) O2(e) ICIarrow_forwardPredict whether each of the following molecules is polar ornonpolar: (a) IF, (b) CS2, (c) SO3, (d) PCl3, (e) SF6, (f) IF5.arrow_forwardExcept for nitrogen, the elements of Group 5A(15) all form pentafluorides and most form pentachlorides. The chlorine atoms of PCI5 can be replaced with fluorine atoms one at a time to give, successively, PCI4F, PCI3F2, .. PF5. (a) Given the relative sizes of F and CI, would you expect the first two F substitutions to be at axial or equatorial positions? O axial equatorial This answer has not been graded yet. (b) Which of the five fluorine-containing molecules have no dipole moment? (Select all that apply.) PCIF4 PCI3F2 PCI2F3 PF5 PCI4Farrow_forward
- Please don't provide handwritten solutionarrow_forwardNitrogen trifluoride (NF3) is used in the electronics industry to clean surfaces. NF3 is also a potent greenhouse gas. (A) Draw the Lewis structure of NF3 and determine its molecular geometry. (B) BF3 and NF3 both have three covalently bonded fluorine atoms around a central atom. Do they have the same dipole moment? (C) Could BF3 also behave as a greenhouse gas? Explain why or why not.arrow_forward(a) How does a polar molecule differ from a nonpolar one? (b) Atoms X and Y have different electronegativities. Will the diatomic molecule X—Y necessarily be polar? Explain. (c) What factors affect the size of the dipole moment of a diatomic molecule?arrow_forward
- (a) What is the hybridization of chlorine in Clo4 ? (Type your answer using the format sp3 for sp3.) (b) What is the hybridization of bromine in BrF5? (c) What is the hybridization of bromine in BrO2 ?arrow_forward2. Consider the following molecules or ions: CIOF5, NOBr, NH2F, and XeO2F3+. Answer the following questions based on the Lewis structures and VSEPR theory prediction of their molecular shapes. (a) Which one has only bond angles of 109.5°? (b) Which one has only bond angles of 120°? (c) Which one has bond angles of 90 and 180°? (d) Which one has bond angles of 90, 120, and 180°?arrow_forwardThere are two main types of covalent bond breakage. In ho-molytic breakage , each atom in the bond gets one of the shared electrons. In some cases, the electronega-tivity of adjacent atoms affects the bond energy. In heterolytic breakage, one atom gets both electrons and the other gets none;thus, a cation and an anion form. (a) Why is the C−C bond in H₃C−CF₃(423 kJ/mol) strongerthan that in H₃C−CH₃(376 kJ/mol)?(b) Use bond energy and any other data to calculate the heat ofreaction for the heterolytic cleavage of O₂.arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning