Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
4th Edition
ISBN: 9780133178579
Author: Ross L. Finney
Publisher: PEARSON
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Question
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Chapter 2, Problem 51RE

(a)

To determine

To graph: A scatter plot of the given data.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The table given below shows the population of Florida in several years:

    Population of Florida
    YearPopulation(in thousands)
    200016,047
    200216,341
    200417,314
    200618,019
    200818,328
    200918,538

Graph:

To graph the points on scatter plot, follow the steps using graphing calculator.

First press the 2nd key and then Y= and make sure that Plot 1 is ON and choose the scatter plot icon in type.

Go to Y1 and then press the key STAT and then in edit enter the data in L1 and L2 .

Now, press the ZOOM9 key and TRACE key to produce the scatter plot of given function in standard window as shown below.

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2, Problem 51RE

Figure (1)

Interpretation: From the scatter plot of give data of population it can be observed that the population of Florida is increasing every year.

(b)

To determine

To find: The slope of the secant line PQi for i=1,2,3 .

(b)

Expert Solution
Check Mark

Answer to Problem 51RE

The slopes of the secant line PQi for i=1,2,3 are 313.86, 244.8 and 210 respectively.

Explanation of Solution

Given information:

The table given below shows the population of Florida in several years:

    Population of Florida
    YearPopulation(in thousands)
    200016,047
    200216,341
    200417,314
    200618,019
    200818,328
    200918,538

The point P represents the points corresponding to 2009, Q1 the point corresponding to 2002, Q2 the point corresponding to 2004 and Q3 the point corresponding to 2008.

Calculation:

Simplify the slope of the secant line PQ1 .

  m=y2−y1x2−x1=16341−185382002−2009=−2197−7=313.86

So, the slope of the secant line PQ1 is equal to 313.86.

Simplify the slope of the secant line PQ2 .

  m=y2−y1x2−x1=17314−185382004−2009=−1224−5=244.8

So, the slope of the secant line PQ2 is equal to 244.8.

Simplify the slope of the secant line PQ3 .

  m=y2−y1x2−x1=18328−185382008−2009=−210−1=210

So, the slope of the secant line PQ3 is equal to 210.

Therefore, the slopes of the secant line PQi for i=1,2,3 are 313.86, 244.8 and 210 respectively.

(c)

To determine

To find: The average rates of change from Qi to P .

(c)

Expert Solution
Check Mark

Answer to Problem 51RE

The average rate of change in the population of the given data is 244,800.

Explanation of Solution

Given information:

The table given below shows the population of Florida in several years:

    Population of Florida
    YearPopulation(in thousands)
    200016,047
    200216,341
    200417,314
    200618,019
    200818,328
    200918,538

The point P represents the points corresponding to 2009, Q1 the point corresponding to 2002, Q2 the point corresponding to 2004 and Q3 the point corresponding to 2008.

Calculation:

The slopes of the secant line PQi for i=1,2,3 are 313.86, 244.8 and 210 respectively. The average rate of change in the population of the given data is 244,800.

Therefore, the average rate of change in the population of the given data is 244,800.

(d)

To determine

To find: The instantaneous rate of change of population on July 1, 2009.

(d)

Expert Solution
Check Mark

Answer to Problem 51RE

The instantaneous rate of change of population on July 1, 2009 is 210,000.

Explanation of Solution

Given information:

The table given below shows the population of Florida in several years:

    Population of Florida
    YearPopulation(in thousands)
    200016,047
    200216,341
    200417,314
    200618,019
    200818,328
    200918,538

Calculation:

The slope of the secant line from year 2009 to 2000 is 210. The average rate of change in the population of the given data is 210,000.

Therefore, the instantaneous rate of change of population on July 1, 2009 is 210,000.

(e)

To determine

To find: The estimated population of Florida in 2020.

(e)

Expert Solution
Check Mark

Answer to Problem 51RE

The estimated population of Florida in 2020 is 442738.

Explanation of Solution

Given information:

The table given below shows the population of Florida in several years:

    Population of Florida
    YearPopulation(in thousands)
    200016,047
    200216,341
    200417,314
    200618,019
    200818,328
    200918,538

Calculation:

Consider that the population growth is liner function. The formula for a linear equation in slope-intercept form is:

  y=mx+c

The required equation is:

  y=210x+18538

Substitute 2020 for x in the above equation to find the population in 2020,

  y=210(2020)+18538=442738

Therefore, the estimated population of Florida in 2020 is 442738.

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Chapter 2, Problem 50RE
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Chapter 2, Problem 52RE

Chapter 2 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 2.1 - Prob. 1QRCh. 2.1 - Prob. 2QRCh. 2.1 - Prob. 3QRCh. 2.1 - Prob. 4QRCh. 2.1 - Prob. 5QRCh. 2.1 - Prob. 6QRCh. 2.1 - Prob. 7QRCh. 2.1 - Prob. 8QRCh. 2.1 - Prob. 9QRCh. 2.1 - Prob. 10QR
Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49ECh. 2.1 - Prob. 50ECh. 2.1 - Prob. 51ECh. 2.1 - Prob. 52ECh. 2.1 - Prob. 53ECh. 2.1 - Prob. 54ECh. 2.1 - Prob. 55ECh. 2.1 - Prob. 56ECh. 2.1 - Prob. 57ECh. 2.1 - Prob. 58ECh. 2.1 - Prob. 59ECh. 2.1 - Prob. 60ECh. 2.1 - Prob. 61ECh. 2.1 - Prob. 62ECh. 2.1 - Prob. 63ECh. 2.1 - Prob. 64ECh. 2.1 - Prob. 65ECh. 2.1 - Prob. 66ECh. 2.1 - Prob. 67ECh. 2.1 - Prob. 68ECh. 2.1 - Prob. 69ECh. 2.1 - Prob. 70ECh. 2.1 - Prob. 71ECh. 2.1 - Prob. 72ECh. 2.1 - Prob. 73ECh. 2.1 - Prob. 74ECh. 2.1 - Prob. 75ECh. 2.1 - Prob. 76ECh. 2.1 - Prob. 77ECh. 2.1 - Prob. 78ECh. 2.1 - Prob. 79ECh. 2.1 - Prob. 80ECh. 2.2 - Prob. 1QRCh. 2.2 - Prob. 2QRCh. 2.2 - Prob. 3QRCh. 2.2 - Prob. 4QRCh. 2.2 - Prob. 5QRCh. 2.2 - Prob. 6QRCh. 2.2 - Prob. 7QRCh. 2.2 - Prob. 8QRCh. 2.2 - Prob. 9QRCh. 2.2 - Prob. 10QRCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.2 - Prob. 7ECh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.2 - Prob. 38ECh. 2.2 - Prob. 39ECh. 2.2 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54ECh. 2.2 - Prob. 55ECh. 2.2 - Prob. 56ECh. 2.2 - Prob. 57ECh. 2.2 - Prob. 58ECh. 2.2 - Prob. 59ECh. 2.2 - Prob. 60ECh. 2.2 - Prob. 61ECh. 2.2 - Prob. 62ECh. 2.2 - Prob. 63ECh. 2.2 - Prob. 64ECh. 2.2 - Prob. 65ECh. 2.2 - Prob. 66ECh. 2.2 - Prob. 67ECh. 2.2 - Prob. 68ECh. 2.2 - Prob. 69ECh. 2.2 - Prob. 70ECh. 2.2 - Prob. 71ECh. 2.2 - Prob. 1QQCh. 2.2 - Prob. 2QQCh. 2.2 - Prob. 3QQCh. 2.2 - Prob. 4QQCh. 2.3 - Prob. 1QRCh. 2.3 - Prob. 2QRCh. 2.3 - Prob. 3QRCh. 2.3 - Prob. 4QRCh. 2.3 - Prob. 5QRCh. 2.3 - Prob. 6QRCh. 2.3 - Prob. 7QRCh. 2.3 - Prob. 8QRCh. 2.3 - Prob. 9QRCh. 2.3 - Prob. 10QRCh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 4ECh. 2.3 - Prob. 5ECh. 2.3 - Prob. 6ECh. 2.3 - Prob. 7ECh. 2.3 - Prob. 8ECh. 2.3 - Prob. 9ECh. 2.3 - Prob. 10ECh. 2.3 - Prob. 11ECh. 2.3 - Prob. 12ECh. 2.3 - Prob. 13ECh. 2.3 - Prob. 14ECh. 2.3 - Prob. 15ECh. 2.3 - Prob. 16ECh. 2.3 - Prob. 17ECh. 2.3 - Prob. 18ECh. 2.3 - Prob. 19ECh. 2.3 - Prob. 20ECh. 2.3 - Prob. 21ECh. 2.3 - Prob. 22ECh. 2.3 - Prob. 23ECh. 2.3 - Prob. 24ECh. 2.3 - Prob. 25ECh. 2.3 - Prob. 26ECh. 2.3 - Prob. 27ECh. 2.3 - Prob. 28ECh. 2.3 - Prob. 29ECh. 2.3 - Prob. 30ECh. 2.3 - Prob. 31ECh. 2.3 - Prob. 32ECh. 2.3 - Prob. 33ECh. 2.3 - Prob. 34ECh. 2.3 - Prob. 35ECh. 2.3 - Prob. 36ECh. 2.3 - Prob. 37ECh. 2.3 - Prob. 38ECh. 2.3 - Prob. 39ECh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 60ECh. 2.3 - Prob. 61ECh. 2.3 - Prob. 62ECh. 2.3 - Prob. 63ECh. 2.3 - Prob. 64ECh. 2.4 - Prob. 1QRCh. 2.4 - Prob. 2QRCh. 2.4 - Prob. 3QRCh. 2.4 - Prob. 4QRCh. 2.4 - Prob. 5QRCh. 2.4 - Prob. 6QRCh. 2.4 - Prob. 7QRCh. 2.4 - Prob. 8QRCh. 2.4 - Prob. 9QRCh. 2.4 - Prob. 10QRCh. 2.4 - Prob. 1ECh. 2.4 - Prob. 2ECh. 2.4 - Prob. 3ECh. 2.4 - Prob. 4ECh. 2.4 - Prob. 5ECh. 2.4 - Prob. 6ECh. 2.4 - Prob. 7ECh. 2.4 - Prob. 8ECh. 2.4 - Prob. 9ECh. 2.4 - Prob. 10ECh. 2.4 - Prob. 11ECh. 2.4 - Prob. 12ECh. 2.4 - Prob. 13ECh. 2.4 - Prob. 14ECh. 2.4 - Prob. 15ECh. 2.4 - Prob. 16ECh. 2.4 - Prob. 17ECh. 2.4 - Prob. 18ECh. 2.4 - Prob. 19ECh. 2.4 - Prob. 20ECh. 2.4 - Prob. 21ECh. 2.4 - Prob. 22ECh. 2.4 - Prob. 23ECh. 2.4 - Prob. 24ECh. 2.4 - Prob. 25ECh. 2.4 - Prob. 26ECh. 2.4 - Prob. 27ECh. 2.4 - Prob. 28ECh. 2.4 - Prob. 29ECh. 2.4 - Prob. 30ECh. 2.4 - Prob. 31ECh. 2.4 - Prob. 32ECh. 2.4 - Prob. 33ECh. 2.4 - Prob. 34ECh. 2.4 - Prob. 35ECh. 2.4 - Prob. 36ECh. 2.4 - Prob. 37ECh. 2.4 - Prob. 38ECh. 2.4 - Prob. 39ECh. 2.4 - Prob. 40ECh. 2.4 - Prob. 41ECh. 2.4 - Prob. 42ECh. 2.4 - Prob. 43ECh. 2.4 - Prob. 44ECh. 2.4 - Prob. 45ECh. 2.4 - Prob. 46ECh. 2.4 - Prob. 47ECh. 2.4 - Prob. 48ECh. 2.4 - Prob. 49ECh. 2.4 - Prob. 50ECh. 2.4 - Prob. 51ECh. 2.4 - Prob. 52ECh. 2.4 - Prob. 53ECh. 2.4 - Prob. 54ECh. 2.4 - Prob. 55ECh. 2.4 - Prob. 1QQCh. 2.4 - Prob. 2QQCh. 2.4 - Prob. 3QQCh. 2.4 - Prob. 4QQCh. 2 - Prob. 1RECh. 2 - Prob. 2RECh. 2 - Prob. 3RECh. 2 - Prob. 4RECh. 2 - Prob. 5RECh. 2 - Prob. 6RECh. 2 - Prob. 7RECh. 2 - Prob. 8RECh. 2 - Prob. 9RECh. 2 - Prob. 10RECh. 2 - Prob. 11RECh. 2 - Prob. 12RECh. 2 - Prob. 13RECh. 2 - Prob. 14RECh. 2 - Prob. 15RECh. 2 - Prob. 16RECh. 2 - Prob. 17RECh. 2 - Prob. 18RECh. 2 - Prob. 19RECh. 2 - Prob. 20RECh. 2 - Prob. 21RECh. 2 - Prob. 22RECh. 2 - Prob. 23RECh. 2 - Prob. 24RECh. 2 - Prob. 25RECh. 2 - Prob. 26RECh. 2 - Prob. 27RECh. 2 - Prob. 28RECh. 2 - Prob. 29RECh. 2 - Prob. 30RECh. 2 - Prob. 31RECh. 2 - Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RE

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